so sanh 1/4+1/9+1/10+1/41+1/42 voi 1/2
1)so sanh : a=10^41-1/10^42-1 va b=10 ^ 40 -1 /40^11+1 .
2)ct: 1/2-1/4+1/8-1/16+1/32-1/64
1)so sanh : a=10^41-1/10^42-1 va b=10 ^ 40 -1 /40^11+1 .2)ct: 1/2-1/4+1/8-1/16+1/32-1/64<1/3
so sanh a=(1/2-1)(1/3-1)(1/4-1)...(1/10-1)voi -1/9
ta có \(A=\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right).......\left(\frac{1}{10}-1\right)\)
\(A=-\left(\frac{1}{2}.\frac{2}{3}.....\frac{9}{10}\right)\)
\(A=-\frac{1}{10}\)
vi\(-\frac{1}{10}>-\frac{1}{9}\)
do đó A>\(\frac{-1}{9}\)
1)so sanh :
a=10^41-1/10^42-1va b=10 ^ 40 -1 /40^11+1 .2)ct:
1/2-1/4+1/8-1/16+1/32-1/64<1/3
So sanh S=\(\frac{1}{5}+\frac{1}{9}+\frac{1}{10}+\frac{1}{40}+\frac{1}{42}voi\frac{1}{2}\)
minh can cach lam
ai nhanh minh tick
Nhận xét: \(\frac{1}{5}< \frac{1}{42};\frac{1}{9}< \frac{1}{42};\frac{1}{10}< \frac{1}{42};\frac{1}{40}< \frac{1}{42}\)
\(\Rightarrow S< \frac{1}{42}+\frac{1}{42}+\frac{1}{42}+\frac{1}{42}+\frac{1}{42}\)
\(\Rightarrow S< \frac{5}{42}< \frac{21}{42}=\frac{1}{2}\)
Vậy S < 1/2
1/5+1/9+1/10+1/40+1/42=1159/2520
1159/2520=0.4599.....
1/2=0.5
Mà:0.5>0.4599
Nên:1/5+1/9+1/10+1/40+1/42>1/2
(1/4-1).(1/9-1).....91/400-1) so sanh voi -1/2
so sanh : 2001/2004 va 39/40
so sanh : A = 1/6 + 1/7 + 1/8 + 1/9 + 1/10 voi B = 1
\(A< \frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{5}{5}=1=B\)
a/
\(\frac{2001}{2004}=\frac{2004-3}{2004}=1-\frac{3}{2004}=1-\frac{1}{668}.\)
\(\frac{39}{40}=\frac{40-1}{40}=1-\frac{1}{40}\)
Ta có \(40< 668\Rightarrow\frac{1}{40}>\frac{1}{668}\Rightarrow1-\frac{1}{40}< 1-\frac{1}{668}\Rightarrow\frac{39}{40}< \frac{2001}{2004}\)
b/
\(A< \frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=1=B\)
So sánh: 1/5+1/9+1/10+1/41+1/42 và 1/2
Mình cũng đang cân người giúp câu dó nên ko trả lời được đâu !
So sanh
1/41 +1/42 + 1/4+1/43+...+1/79 va 7/12
lam nhanh minh tick