4/9.11+4/11.13+.............................................4/153.155
4 /(9.11)+4 /(11.13)+4 /(13.15)+........+4 /(97.99)
Đặt \(A=\frac{4}{9.11}+\frac{4}{11.13}+\frac{4}{13.15}+...+\frac{4}{97.99}\)
\(\Rightarrow A=2.\left(\frac{4}{9}-\frac{4}{11}+\frac{4}{11}-\frac{4}{13}+...+\frac{4}{97}-\frac{4}{99}\right)\)
\(\Rightarrow A=2.\left(\frac{4}{9}-\frac{4}{99}\right)=2.\left(\frac{40}{99}\right)=\frac{80}{99}\)
Vậy \(A=\frac{80}{99}\)
\(\frac{4}{9.11}+\frac{4}{11.13}+\frac{4}{13.15}+...+\frac{4}{97.99}=2.\left(\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{97.99}\right)\)
\(=2.\left(\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(=2.\left(\frac{1}{9}-\frac{1}{99}\right)=2.\left(\frac{11}{99}-\frac{1}{99}\right)=2.\frac{10}{99}=\frac{20}{99}\)
A=\(\dfrac{4}{3.5}-\dfrac{6}{5.7}+\dfrac{8}{7.9}-\dfrac{10}{9.11}+\dfrac{12}{11.13}-...-\dfrac{100}{99.100}\)
Tính giá trị của A
Tìm x, biết:
x/3.5 + x/5.7 + x/7.9 + x/9.11 + x/11.13 + x/13.15 = 4/45
\(\frac{x}{3.5}+\frac{x}{5.7}+\frac{x}{7.9}+...+\frac{x}{13.15}=\frac{4}{45}\)
\(\Leftrightarrow\frac{x}{2}.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{13.15}\right)=\frac{4}{45}\)
\(\Leftrightarrow\frac{x}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{13}-\frac{1}{15}\right)=\frac{4}{45}\)
\(\Leftrightarrow\frac{x}{2}.\left(\frac{1}{3}-\frac{1}{15}\right)=\frac{4}{45}\)
\(\Leftrightarrow\frac{x}{2}.\frac{4}{15}=\frac{4}{45}\)
\(\Leftrightarrow\frac{x}{2}=\frac{4}{45}:\frac{4}{15}\)
\(\Leftrightarrow\frac{x}{2}=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}.2\)
\(\Leftrightarrow x=\frac{2}{3}\)
Vậy x = \(\frac{2}{3}\)
_Chúc bạn học tốt_
B=\(\frac{4}{3.5}-\frac{6}{5.7}+\frac{8}{7.9}-\frac{10}{9.11}+\frac{12}{11.13}-...+\frac{100}{99.101}\)
TINH B
B=2(2/3.5 - 2/ 5.7 +....................+ 2/99.101)
B=2(1/3.5 -2/5.7+..............+1/99.100)
B=2(1/3-1/5+1/5-.............+1/99-1/100)
B=2(1/3-1/100)
B=2.97/100
B=97/50
B=\(\frac{4}{3.5}-\frac{6}{5.7}+\frac{8}{7.9}-\frac{10}{9.11}+\frac{12}{11.13}-...+\frac{100}{99.101}\)
TINH B
B=\(\frac{4}{3.5}-\frac{6}{5.7}+\frac{8}{7.9}-\frac{10}{9.11}+\frac{12}{11.13}-...+\frac{100}{99.101}\)
TINH B
A=6/1.3.7 + 6/3.7.9 + 6/7.9.13 + 6/9.13.15 + 6/13/15/19
Giup mk nhé và làm theo cách dưới :
C=4/1.3.5 + 4/3.5.7 + 4/5.7.9 + 4/7.9.11 + 4/9.11.13
C=5-1/1.3.5 + 7-3 /3.5.9 + ............................ + 13-9/9.11.13
C=5/1.3.5 - 1/1.3.5 + 7/3.5.7 - 3/3.5.7 + ................... + 13/9.11.13 - 9/9.11.13
C=1/1.3 -1/3.5 + 1/3.5- 1/5.7 + ................................. + 1/9.11 - 1/11.13
C=1/1.3 - 1/11.13
C= 11.13/3.11.13 - 3/3.11.13
C=140/425
mình cũng ko hiểu cách giải này cho lắm nên mình làm thế thôi
Giup mk .Mk like bn nào trả lời sóm nhất , đúng nhất .
A=6/1.3.7 + 6/3.7.9 + 6/7.9.13 + 6/9.13.15 + 6/13.15.19
Nếu các bn ko biết giải cách tiểu học thì giải theo sau
B=4/1.3.5 + 4/3.5.7 + 4/5.7.9 + 4/7.9.11 + 4/9.11.13
B=5-1/1.3.5 + 7-3/3.5.7 +........+ 13-9/9.11.13
B=5/1.3.5 - 1/1.3.5 + 7/3.5.7 - 3/3.5.7 +............... + 13/9.11.13 - 9/9.11.13
B=1/1.3 - 1/3.5 + 1/3.5 - 1/5.7 + ............. + 1/9.11 - 1/11.13
B=1/1.3-1/11.13
B= 11.13/3.11.13 - 3/3.11.13 = 140/425
1)Tính:
P= 2/3.5+2/5.7+2/7.9+2/9.11+2/11.13+2/13.15
2) Thực hiện phép tính:
a) 0,2:1/3/5+80%
b) 0,5:5/4-2/1/5
1) P = 2/3.5 + 2/5.7 + 2/7.9 + 2/9.11 + 2/11.13 + 2/13.15
P= (1/3-1/5) + (1/5-1/7) + (1/7-1/9) + (1/9-1/11) + (1/11-1/13) + (1/13-1/15)
P=1/3-1/15= 4/15
2) a/ 0,2:1+3/5+80%
= 2/10:8/5+8/10
= 2/10.5/8+8/10
= 1/8 + 4/5 = 5/40 + 32/40 = 37/40
b/ 0,5:5/4-2+1/5
= 5/10:5/4-11/5
= 5/10.4/5-11/5
=2/5-11/5 = -9/5