Tính \(4\frac{25}{16}\)+25x\(\left(\frac{9}{16}-1\frac{17}{64}\right)\div\frac{27}{8}\)
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\(4\frac{25}{16}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
KQ là \(-\frac{61}{16}\)
mk ko bít bạn có cần lời giải ko mk chỉ vít kq hoi
có j nếu cần lời giải ns mk ha
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\(4\frac{25}{16_{ }}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{25}{4}+25.\left(\frac{36}{64}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{25}{4}+25.\left(\frac{-81}{64}\right):\frac{28}{7}\)
=\(\frac{25}{4}+\left(\frac{-2025}{64}\right).\frac{7}{28}\)
=\(\frac{25}{4}+\left(\frac{-2025}{256}\right)\)
=\(\frac{1600}{256}-\frac{2025}{256}\)
=\(\frac{-425}{256}\)
bn xem có đúng k nhé!
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tÍNH:
a, \(4\frac{25}{16}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
b, -15,5x20,8+3,5x9,2-15,5x9,2+3,5x20,8
c, \(\frac{5}{16}:0,125+1,456:\frac{7}{25}+4\frac{1}{2}.0,8\)
\(\frac{89}{15}+25\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{89}{15}+25(-\frac{81}{64}):\frac{27}{8}\)
=\(\frac{89}{15}+(-\frac{2025}{64}):\frac{27}{8} \)
=\(\frac{89}{15}+(-\frac{75}{8})\)
=\(-\frac{89}{24}\)
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\(\frac{89}{15}\)+ 25 \((\) \(\frac{36}{64}\)\(-\)\(\frac{117}{64}\)\()\). \(\frac{8}{27}\)
= \(\frac{89}{15}\)+ 25 \((\)\(\frac{-81}{64}\)\()\)\(\frac{8}{27}\)
= \(\frac{89}{15}\)+ 25 . \((\)\(\frac{-3}{8}\)\()\)
= \(\frac{89}{15}\)+ \(\frac{-75}{8}\)
= \(\frac{-413}{120}\)
Nếu đúng cho mình xin 1 k nhé
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Tính giá trị biểu thức1.Afrac{1}{5}+frac{3}{17}-frac{4}{3}+left(frac{4}{5}-frac{3}{17}+frac{1}{3}right)-frac{1}{7}+left[frac{-14}{30}right]2.Bleft(frac{5}{8}-frac{4}{12}+frac{3}{2}right)-left(frac{5}{8}+frac{9}{13}right)-left[frac{-3}{2}right]+frac{7}{-15}3.Cfrac{5}{18}+frac{8}{19}-frac{7}{21}+left(frac{-10}{36}+frac{11}{19}+frac{1}{3}right)-frac{5}{8}4.Dfrac{1}{9}-left[frac{-5}{23}right]-left(frac{-5}{23}+frac{1}{9}+frac{25}{7}right)+frac{50}{14}-frac{7}{30}5.Efrac{1}{13}+left(frac{-5}{18}-frac...
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Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
\(4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{164}\right):\left(\frac{_{-27}}{8}\right)\)
\(=\frac{89}{16}+25.\frac{369}{500}:\left(\frac{-27}{8}\right)\)
\(=\frac{89}{16}+\frac{369}{20}:\left(\frac{-27}{8}\right)\)
\(=\frac{89}{16}+\frac{-82}{15}\)
\(=\frac{23}{240}\)
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\(4\frac{25}{16}\).25.\(\left(\frac{9}{16}-\frac{117}{64}\right)\): \(\frac{27}{8}\)
\(\frac{5}{16}\): 0.125+1.456: \(\frac{7}{25}\)+\(4\frac{1}{2}\)+0.8
mik làm được mỗi ý b thui :
b ) \(\frac{169}{10}=16,9\)
mik nha
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phần đầu bằng -6675/128
phần sau bằng 13
bạn dùng máy tính là được mà
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\(4\frac{25}{16}X25\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}=-\frac{6675}{128}=-52,1484375\)
\(\frac{5}{16}:0,125+1,456:\frac{7}{25}+4\frac{1}{2}+0,8=13\)
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Tính:
A = $5\frac{3}{7}+\left(-5,35\right)+\frac{1}{3}+\left(-2,41\right)+\frac{3}{21}+\left(-1,24\right)$537 +(−5,35)+13 +(−2,41)+321 +(−1,24)
B = $4\frac{25}{16}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}$42516 +25.(916 −11764 ):278
Trình bày cách giải và đáp án giúp mình nha! ^^
Tính giá trị biểu thức:
\(A=\frac{\frac{16}{10}:\left(1\frac{3}{5}\times \frac{5}{4}\right)}{\frac{64}{100}-\frac{1}{25}}+\frac{\left(\frac{108}{100}-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-2\frac{1}{4}\right)\times 2\frac{2}{17}}+\frac{3}{5}\times \frac{1}{2}:\frac{2}{5}\)
Thực hiện các phép tính:
a) \(A=4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)
b) \(C=\frac{2^3}{3.5}+\frac{2^3}{5.7}+\frac{2^3}{7.9}+...+\frac{2^3}{101.103}\)
a)Ta có:
\(A=4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+25.\frac{36}{125}:\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+\frac{36}{5}:\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+\frac{-32}{15}\)
\(\Rightarrow A=\frac{823}{240}\)
Vậy A=.....
b)Ta có:
\(C=\frac{2^3}{3.5}+\frac{2^3}{5.7}+\frac{2^3}{7.9}+...+\frac{2^3}{101.103}\)
\(\Rightarrow C=\frac{2^2.2}{3.5}+\frac{2^2.2}{5.7}+\frac{2^2.2}{7.9}+...+\frac{2^2.2}{101.103}\)
\(\Rightarrow C=2^2\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{101.103}\right)\)
\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{101}-\frac{1}{103}\right)\)
\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{103}\right)\)
\(\Rightarrow C=4.\frac{100}{309}\)
\(\Rightarrow C=\frac{400}{309}\)
Vậy C=.....
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B, C=2^3/3.5 + 2^3/5.7+......+2^3/101.103
C= 2^3(1/3-1/5+1/5-1/7+....+1/101-1/103)
C=8(1/3-1/103)
C=8.100/309
C=800/309
VẬY C= 800/309
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