=>(x . 3 -8)=7 . 4

=>x . 3-8 =28

=.x.3 = 28+8

=>x.3= 36

=>x=36:3

=>x=12

(x . 3 - 8):4 = 7

x.3 - 8 = 7 . 4 = 28

x.3 = 28 + 8 = 36

x = 36:3 = 12

Ta có\(ob^2+oe^2=6,25\)và \(od^2+oc^2=25\)

Mà \(od=\frac{1}{2}ob;oc=2oe\Rightarrow oe=2,5cm\)

C/m tt : ta được BC=5cm :))

101 x 102 = 10302

10302

101x102

=(100+1)x102

=100x102+1x102

=10200+102

=    10302.

Đáp án đúng là : \(\frac{9}{196}\) nha bạn

đáp án là:\(\frac{9}{196}\)

Đặt A = \(\frac{1}{4.9}+\frac{1}{9.14}+\frac{1}{14.19}+...+\frac{1}{44.49}\)

5A = \(\frac{5}{4.9}+\frac{5}{9.14}+\frac{5}{14.19}+...+\frac{5}{44.49}\)

5A = \(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+\frac{1}{14}-\frac{1}{19}+...+\frac{1}{44}-\frac{1}{49}\)

5A = \(\frac{1}{4}-\frac{1}{49}\)

5A = \(\frac{45}{196}\)

A = \(\frac{45}{196}:5\)

A = \(\frac{9}{196}\)

nhưng trong violympic thì cái này là lớp 5

Answer:

Bài 1: 

\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)\)

\(=100.\left(-37\right)+37.\left(-100\right)\)

\(=\left(-3700\right)+\left(-3700\right)\)

\(=-7400\)

\(-65.\left(87-17\right)-87.\left(17-65\right)\)

\(=\left(-65\right).87-\left(-65\right).17-87.17+87.65\)

\(=-\left(-65\right).17-87.17\)

\(=17.\left(65-87\right)\)

\(=-374\)

\([3.\left(-2\right)-\left(-8\right)].\left(-7\right)-\left(-2\right).\left(-5\right)\)

\(=[\left(-6\right)+8].\left(-7\right)-\left(-2\right).\left(-5\right)\)

\(=2.\left(-7\right)-10\)

\(=-24\)

Bài 2:

\(\left(-55\right).\left(-25\right).\left(-8\right)\)

\(=\left(-55\right).[\left(-25\right).\left(-8\right)]\)

\(=\left(-55\right).200\)

\(=-11000\)

\(\left(-1\right).\left(-2\right).\left(-3\right).\left(-4\right).\left(-5\right).10\)

\(=[\left(-1\right).10].[\left(-2\right).\left(-5\right)].[\left(-3\right).\left(-4\right)]\)

\(=\left(-10\right).10.12\)

\(=-1200\)

4:3=1,(3)

4 : 3 = tứ chia tam = tám chia tư = 8 : 4 = 2

4:3= tứ chia tam = tám chia tư =2