( x² - 4x + 16 )( x + 4 ) - x( x + 1 )( x + 2 ) + 3x² = 0

<=> x³ + 4³ - x( x² + 3x + 2 ) + 3x² = 0

<=> x³ + 64 - x³ - 3x² - 2x + 3x² = 0

<=> 64 - 2x = 0

<=> 2x = 64

<=> x = 32

( 8x + 2 )( 1 - 3x ) + ( 6x - 1 )( 4x - 10 ) = -50

<=> 2x - 24x² + 2 + 24x² - 64x + 10 = -50

<=> -62x + 12 = -50

<=> -62x = -62

<=> x = 1 

\(50\%x+\frac{2}{3}x=x+4\)

\(\Rightarrow x\left\{\frac{1}{2}+\frac{2}{3}=x=4\right\}\)

\(\Rightarrow\frac{7}{6}x=x+4\) 

\(\Rightarrow7x=\left\{x+4\right\}6\)

\(\Rightarrow7x=6x+24\)

\(\Rightarrow7x-6x=24\)

\(\Rightarrow x=24\)

\(50\%\cdot x+\frac{2}{3}\cdot x=x+4\)

\(\frac{1}{2}x+\frac{2}{3}x=x+4\)

\(\left(\frac{1}{2}+\frac{2}{3}\right)x=x+4\)

\(\frac{7}{6}x=x+4\)

\(\left(\frac{7}{6}-1\right)x=4\)

\(\frac{1}{6}x=4\)

\(\Rightarrow x=24\)

\(50\%x+\frac{2}{3}x=x+4\)

\(\Rightarrow x\left(\frac{1}{2}+\frac{2}{3}\right)=x+4\)

\(\Rightarrow\frac{7}{6}x=x+4\)

\(\Rightarrow7x=\left(x+4\right)6\)

\(\Rightarrow7x=6x+24\)

\(\Rightarrow7x-6x=24\)

\(\Rightarrow x=24.\)

a,

x-43+7=49-(50+3)

<=>x-36=49-53

<=>x-36=-4

<=>x=-4+36

<=>x=32

b

-(x-16)+70=45

<=>-x+16+70=45

<=>-x+86=45

<=>x=86-45

<=>x=41

Bài 2

a.,

2x-(-60)=3x-18

<=>2x+60=3x-18

<=>3x-2x=60+18

<=>x=78

b,

-45-5x=10-4x

<=>-4x+5x=-45-10

<=>x=-55

Nếu thấy bài làm của mình đúng thì tick nha bạn,mình xin chân thành cảm ơn.

a) x-  43 + 7 = 49 - (50 + 3)

x - 36 = -4

x = -4 + 36

x = 32

b) -(x - 16) + 70 = 45

-(x - 16) = -15

x - 16 = 15

x = 31

Bài 2:

2x - (-60) = 3x - 18

2x + 60 = 3x - 18

3x - 2x = 60 + 18

x = 78

b) -4- 5x = 10 - 4x

5x - 4x = -4 - 10

x = -14