3333 + x = 64913257
Tìm x biết 7/4*(3333/1212+3333/2020+3333/3030+3333/4242+3333/5656)*x=-385/32
7/4 x (3333/1212 -3333/2020 +3333/3030 +3333/4242)
M = \(\frac{7}{4}x\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}+\frac{3333}{5656}\right)\)
\(M=\frac{7}{4}\times\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}+\frac{3333}{5656}\right)\)
\(M=\frac{7}{4}\times\left(\frac{11}{4}+\frac{33}{20}+\frac{11}{10}+\frac{11}{14}+\frac{33}{56}\right)\)
\(M=\frac{7}{4}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}+\frac{33}{56}\right)\)
\(M=\frac{7}{4}\times\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}+\frac{33}{7.8}\right)\)
\(M=\frac{7}{4}\times\left[33\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\right]\)
\(M=\frac{7}{4}\times\left[33\times\left(\frac{1}{3}-\frac{1}{8}\right)\right]\)
\(M=\frac{7}{4}\times\left(33\times\frac{5}{24}\right)=\frac{7}{4}\times\frac{55}{8}=\frac{385}{32}\)
3333.....3333 x 3333...3333
50 c/s 3 50 c/s 3
3x3=9 vì vậy bài toán trên sẽ chuyen thanh
50c\s 9 x50= ......( tự tính nghen)
A=\(\frac{7}{4}x\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
Tính tích của các phép tính sau
3333....333 (có 50 chữ số 3) x 9999....9999 (có 50 chữ số 9)
3333...333 (có 50 chữ số 3) x 3333.....3333 (có 50 chữ số 3)
\(A=\frac{7}{4}X\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
giúp mình với nha everybody !
\(A=\frac{7}{4}X\left(\frac{11}{4}+\frac{33}{20}+\frac{11}{10}+\frac{11}{14}\right)\)
\(A=\frac{7}{4}X\frac{44}{7}=11\)
Tính A= \(\frac{7}{4}\)x (\(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{4242}+\frac{3333}{3030}\))
A = \(\frac{7}{4}.\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{4242}+\frac{3333}{3030}\right)\)
A = \(\frac{7}{4}.\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)
A = \(\frac{7}{4}.33.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\)
A = \(\frac{7}{4}.33.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
A = \(\frac{7}{4}.33.\left(\frac{1}{3}-\frac{1}{7}\right)=\frac{7}{4}.33.\frac{4}{21}\)
=> A = \(\frac{1}{3}.33\)
=> A = 11
0:x=0 . 2222 mũ 3333 và 3333 mũ 2222
22223333=33332222
P/S:Không nhận đá ném vô mặt