Tim x,y,z : 3(x-1)=2(y-2),4(y-2)=3(z-3) va 2x+3y-z=50
tim x ,y,z
3(x-1)=2(y-2) va 4(y-2)=3(z-3) va 2x=3y-z=50
tim x,y,z biet
x+1/2 = y-2/3 = z-3/4 va 2x + 3y - z = 50
tim x,y,z biet
x+1/2 = y-2/3 = z-3/4 va 2x + 3y - z = 50
a, x/5=y/3 và 5x-3y=8
b, x/3=y/4 ; y/5 = z/7 va 2x+ 3y-z=124
c, 3x=2y ; 7y=5z va x-y+z=32
đ, 2x/3=3y/4=4z/5 và x+y+z=49
e, 2x=3y=5z va x+y-z=95
f, x-1/2=y-2/3=z-3/4 va 2x+3y-z=50
Bạn áp dụng tính chất dãy tỉ số bằng nhau đi :)
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Tim x, y , z
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) va 2x+3y-z=50
Tim x+y+z = ? biet (x-1) /2= (y-2) /3 = (z-3) /4 va 2x+3y-z=95
Áp dụng tính chất dãy tỉ số bằng nhau , ta có:
x-1/2 = y-2/3 = z-3/4 = 2x-2+3y-6-z+3/4+9-4 = 2x+3y-z + (-5)/9 = 90/9 = 10
x-1/2 = 10 => x= 21
y-2/3 = 10 => y = 32
z-3/4 = 10 => x = 43
Vậy x + y + z= 21 + 32 + 43 = 96
Cho ba số x;y;z thoa man: x-1/2=y-2/3=z-3/4
va 2x+3y-z=50
tìm x;y;z
Tim x,y,z:
\(\frac{x-1}{2}\)=\(\frac{y-2}{3}\)=\(\frac{z-3}{4}\)va 2x+3y-z=503x=2y ; 7y=5z va x-y+z=32
2) Ta có: \(\hept{\begin{cases}3x=2y;7y=5z\\x-y+z=32\end{cases}\Rightarrow\frac{x}{2}=\frac{y}{3};\frac{y}{5}=\frac{z}{7}\Rightarrow\frac{x}{10}=\frac{y}{15}=\frac{z}{21}.}\)
\(\Rightarrow\frac{x-y+z}{10-15+21}=\frac{32}{16}=2\)
Vậy \(\hept{\begin{cases}x=2.10=20\\y=2.15=30\\z=2.21=42\end{cases}}\)
Ủng hộ nha m.n
\(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\) va 3x + 3y - z = 50
tim x, y ,z
\(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\Leftrightarrow\dfrac{3\left(x-1\right)}{6}=\dfrac{3\left(y-2\right)}{9}=\dfrac{z-3}{4}\)
\(\Leftrightarrow\dfrac{3x-3}{6}=\dfrac{3y-6}{9}=\dfrac{z-3}{4}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{3x-3}{6}=\dfrac{3y-6}{9}=\dfrac{z-3}{4}=\dfrac{3x-3+3y-6-z+3}{6+9-4}=\dfrac{\left(3x+3y-z\right)+\left(3-3-6\right)}{11}=\dfrac{50-6}{11}=4\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x-1}{2}=4\Leftrightarrow x=4.2+1=9\\\dfrac{y-2}{3}=4\Leftrightarrow y=4.3+2=14\\\dfrac{z-3}{4}=4\Leftrightarrow z=4.4+3=19\end{matrix}\right.\)