Rút gọn phân số
a, 198/126
b,103/3090
rút gọn các phân sô sau:
-35/280 ; 24/72 ; 15/-105 ; 36/240 ; 125/1000 ; 198/126 ; 3/243 ; 103/3090 ; 252525/535353 ; 25.9-25.17/-8.80-8.10
lấy máy tính ra bấm là nó ra liền à
\(\frac{-35}{280}=\frac{\left(-35\right):35}{280:35}=\frac{-1}{8}\)
\(\frac{24}{72}=\frac{24:24}{72:24}=\frac{1}{3}\)
\(\frac{15}{-105}=\frac{-15}{105}=\frac{\left(-15\right):15}{105:15}=\frac{-1}{7}\)
\(\frac{36}{240}=\frac{36:12}{240:12}=\frac{3}{20}\)
\(\frac{125}{1000}=\frac{125:125}{1000:125}=\frac{1}{8}\)
\(\frac{198}{126}=\frac{198:18}{126:18}=\frac{11}{7}\)
\(\frac{3}{243}=\frac{3:3}{243:3}=\frac{1}{81}\)
\(\frac{103}{3090}=\frac{103:103}{3090:103}=\frac{1}{30}\)
\(\frac{252525}{535353}=\frac{252525:10101}{535353:10101}=\frac{25}{53}\)
\(\frac{25.9-25.17}{-8.80-8.10}=\frac{25.\left(9-17\right)}{-8.\left(80+10\right)}=\frac{25.\left(-8\right)}{\left(-8\right).90}=\frac{5}{18}\)
Ai Giúp mình bài rút gọn phân số này với a) 103/3090 b) 7314/-18126 c)23.5-23.8/414 d) 7/102-8.102 e) -13.6+12.5/6.(-7)-(-4).6 f) 914.255.(-8)7/(-18)12.6253.(-24)3
\(\)RÚT GỌN CÁC PHÂN SỐ SAU:
a)\(\frac{6}{10}\);\(\frac{6}{16}\);\(\frac{-15}{-20}\);\(\frac{-10}{30}\)
b)\(\frac{42}{28}\);\(\frac{54}{-21}\);\(\frac{-27}{33}\);\(\frac{25}{14}\)
c\(\frac{125}{1000}\);\(\frac{198}{126}\);\(\frac{3}{243}\);\(\frac{103}{3090}\)
d)\(\frac{2.3}{7.10}\)
e\(\frac{2.3}{9.14}\)
f\(\frac{3.25}{4.21}\)
g\(\frac{4.7}{5.21}\)
\(a,\frac{6}{10}=\frac{3}{5};\frac{6}{16}=\frac{3}{8};-\frac{15}{20}=\frac{3}{4};-\frac{10}{30}=\frac{-1}{3}\)
\(b,\frac{42}{28}=\frac{3}{2};\frac{54}{-21}=-\frac{10}{7};-\frac{27}{33}=-\frac{9}{11};\frac{25}{14}=\frac{25}{14}\)
\(c,\frac{125}{1000}=\frac{1}{8};\frac{198}{126}=\frac{11}{7};\frac{3}{243}=\frac{1}{81};\frac{103}{2090}=\frac{103}{2090}\)
\(d,\frac{2.3}{9.14}=\frac{28}{3}\)
3090*9999999999999999999
10,5*x + 2,7*(1000-x)=3090 giải hộ mình vs có lời giải nha
A= \(\frac{101}{102}\)+ \(\frac{102}{103}\)+\(\frac{103}{104}\) và B =\(\frac{101+102+103}{102+103+104}\) .So sánh A và B
\(A=2,970871956;B=\frac{102}{103}\)
\(A>2>1>B\)
\(\Rightarrow A>B\)
Đúng 100%
Đúng 100%
Đúng 100%
Ta có: \(B=\frac{101+102+103}{102+103+104}=\frac{101}{102+103+101}+\frac{102}{102+103+104}+\)\(\frac{103}{102+103+104}\)
Vì: \(\frac{101}{102}>\frac{101}{102+103+104}\)
\(\frac{102}{103}>\frac{102}{102+103+104}\)
\(\frac{103}{104}>\frac{103}{102+103+104}\)
\(\Rightarrow A>B\)
Vậy A > B
\(\frac{\frac{3}{7}+\frac{3}{103}+\frac{3}{17}}{\frac{5}{7}+\frac{5}{103}+\frac{5}{17}}=?\)
Cho A= \(\frac{101}{102}\)+\(\frac{102}{103}\)+\(\frac{103}{104}\) B=\(\frac{101+102+103}{102+103+104}\)HÃY SO SÁNH A và B
A= 101+ 102 +103 B= 101+ 102 +103
102 + 103 + 104 102 + 103 + 104
= 102 phần 104 = 101 phần 104
vậy a = b
