giup minh nhe

\(\frac{1+2y}{18}=\frac{1+4y}{24}\Rightarrow\left(1+2y\right).24=\left(1+4y\right).18\)

\(\Rightarrow24+48y=18+72y\)

\(\Rightarrow24-18=-48y+72y\Rightarrow6=24y\Rightarrow y=\frac{24}{6}=4\)

\(\Rightarrow\frac{1+2y}{18}=\frac{1+8}{18}=\frac{9}{18}=\frac{1}{2}\)

\(\frac{1+2y}{18}=\frac{1+6y}{6x}=\frac{1+24}{6x}=\frac{25}{6x}=\frac{1}{2}\Rightarrow6x=30\Rightarrow x=5\)

vậy x=5,y=4

eeeeeeeeeiiiiiiiiiiii 

\(6=24y\Rightarrow y=\frac{6}{24}=\frac{1}{4}thayvaoroitinh\)

\(\frac{1+2y}{18}=\frac{1+4y}{24}\Rightarrow24.\left(1+2y\right)=18.\left(1+4y\right)\)

\(24+48y=18+72y\)

\(6=24y\Rightarrow y=\frac{6}{24}\)

thay y vào \(\frac{1+2y}{18}\Rightarrow\frac{1+2y}{18}=\frac{1+\frac{6}{12}}{18}=\frac{\frac{18}{12}}{18}=\frac{1}{12}\)

tính đc y rồi thì tự tìm x nha =)

oh -------------------------tín lộn đoạn nhỏ nha :> thông củm =)

\(6=24y\Rightarrow y=\frac{24}{6}=4\)

\(\Rightarrow\frac{1+2y}{18}=\frac{1+8}{18}=\frac{1}{2}\)

\(\frac{1+2y}{18}=\frac{1+6y}{6x}=\frac{1+24}{6x}=\frac{25}{6x}=\frac{1}{2}\Rightarrow6x=30\Rightarrow x=5\)

-_-" -----------cứ để nhưu lúc tr nha 

soryr 

Áp dụng dãy tỉ số bằng nhau, ta có:

\(\frac{1+2y}{18}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}=\frac{2+8y}{18+6x}=\frac{2.1+4y}{2.9+3x}=\frac{1+4y}{9+3x}\)

\(\Rightarrow\frac{1+4y}{9+3x}=\frac{1+4y}{24}\Rightarrow9+3x=24\)

\(3x=15\)

Vậy: \(x=5\)

Ta có: \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}\)

\(\Rightarrow\) 24 . (1 + 2y) = 18 . (1 + 4y)

\(\Rightarrow\) 24 + 48y = 18 + 72y

\(\Rightarrow\) 24 - 18 = 72y - 48y

\(\Rightarrow\) 6 = 24y

\(\Rightarrow\) y = \(\dfrac{1}{4}\)

Thay y = \(\dfrac{1}{4}\) ta có:

\(\dfrac{1+1}{24}=\dfrac{1+\dfrac{3}{2}}{6x}\)

\(\Rightarrow\) \(\dfrac{1}{12}=\dfrac{\dfrac{5}{2}}{6x}\)

\(\Rightarrow\) \(6x=\dfrac{5}{2}.12\)

\(\Rightarrow\) \(6x=30\)

\(\Rightarrow\) \(x=5\)

Vậy x = 5 và y = \(\dfrac{1}{4}\)

a, => (x^2/y):(x/y) = 2:16 

=> 1/y = 1/8 => y=8 ; x = 128

b, 1+2y/18 = 1+4y/24

<=> (1+2y).24 = (1+4y).18

<=> 24+48y = 18+72y

<=> 72y+18-24-48y=0

<=>24y-6=0

<=> 24y=6

<=> y=6:24 = 1/4

Khi đó : 1+2y/18 = 1+6y/6x

<=> 1+1/2/18 = 1+3/2 / 6x

<=> 1/12 = 5/12x

<=> 12x = 5: 1/12 = 60

<=> x = 60:12 = 5

Vậy .......

k mk nha

Ta có \(\frac{1+2y}{18}\)=\(\frac{1+4y}{24}\)

\(\Rightarrow\)(1+2y)24=(1+4y)18

\(\Rightarrow\)24+48y=18+72y

\(\Rightarrow\)24-18=72y-48y

\(\Rightarrow\)6=24y

\(\Rightarrow\)y=\(\frac{6}{24}\)

\(\Rightarrow\)y=\(\frac{1}{4}\)

Thay y=\(\frac{1}{4}\) vào đề ta có:

1 + 2\(\frac{1}{4}\) / 18 = 1 + 4\(\frac{1}{4}\) / 24 = 1 + 6\(\frac{1}{4}\) / 6x

=>\(\frac{1}{12}\)=\(\frac{\frac{5}{2}}{\frac{6}{x}}\)

=>12.\(\frac{5}{2}\)=6x

=>30=6x

=>x=5

Vậy x=5;y=\(\frac{1}{4}\)

ta co : 1+2y/18=1+4y/24

=> 24(1+2y)=18(1+4y)

=>24+48y=18+72y

=>24-18=72y-48y

=>6=24y

=>y=1/4 

thay y thanh 1/4 vao de bai ta co : 

1+1/2/18=1+1/24=(1+3/2)/6x

=>1/12=(5/2)/6x

=>12/(5/2)=6x

=>30=6x/x=5

vay x=5 va y=1/4

Ta có =

(1+2y)24=(1+4y)18

24+48y=18+72y

24-18=72y-48y

6=24y

y=

y=

Thay y= vào đề ta có:

1 + 2 / 18 = 1 + 4 / 24 = 1 + 6 / 6x

=>=

=>12.=6x

=>30=6x

=>x=5

Vậy x=5;y=

ta co : 1+2y/18=1+4y/24

=> 24(1+2y)=18(1+4y)

=>24+48y=18+72y

=>24-18=72y-48y

=>6=24y

=>y=1/4 

thay y thanh 1/4 vao de bai ta co : 

1+1/2/18=1+1/24=(1+3/2)/6x

=>1/12=(5/2)/6x

=>12/(5/2)=6x

=>30=6x/x=5

vay x=5 va y=1/4

Ta có : \(\frac{1+2y}{18}=\frac{1+4y}{24}\)

\(\Rightarrow24\left(1+2y\right)=18\left(1+4y\right)\)

\(\Leftrightarrow24+48y=18+72y\)

\(\Leftrightarrow72y-48y=24-18\)

\(\Leftrightarrow24y=6\Leftrightarrow y=\frac{1}{4}\)

Thay \(y=\frac{1}{4}\) vào biểu thức ( 1 + 2y ) / 18 = ( 1  + 4y ) / 24 = ( 1 + 6y ) /6x , ta có :

\(\frac{1+2.\frac{1}{4}}{18}=\frac{1+6.\frac{1}{4}}{6x}\Rightarrow x=5\)

Vậy \(\hept{\begin{cases}x=5\\y=\frac{1}{4}\end{cases}}\)