Ta có:

10A=10¹⁶+10/10¹⁶+1=1+​​(9/10¹⁶+1)

10B=10¹⁷+10/10¹⁷+1=1+(9/10¹⁷+1)

Vì 9/10¹⁶+1 > 9/10¹⁷+1 nên 10A>10B,do đó A>B

Ta có:

10A=10^16+10/10^16+1=1+﴾9/10^16+1﴿

10B=10^17+10/10^17+1=1+﴾9/10^17+1﴿

Vì 9/10^16+1 > 9/10^17+1 nên 10A>10B,do đó A>B 

Ta có:

10A= 10^16+10  / 10^16+1

       =1+ 9 / 10^16 + 1

10B= 10^17+10 / 10^17+1

       =1+ 9 / 10^17 + 1

Vì 9 / 10^16 + 1 > 9 / 10^17 + 1 nên 10A>10B

Do đó A > B

TRƯỚC TIÊN TA SO SÁNH 10 VỚI 10B

10A=10^16+10/10^16+1=1\(\frac{9}{16+1}\) 

10B=10^17+10/10+17+1=1\(\frac{9}{17+1}\) 

VÌ 9/16+1>9/17+1

=>10A>10B

=>A>B

AI TÍCH MK ;MK TÍCH LẠI

A>B chac 1oo% lu0n

A=10^15+1/10^16+1

=>10A=1+9/10^16+1

B=10^16+1/10^17+1

=>10B=1+9/10^17+1

=>10A>10B=>A>B

Vậy:A>B

Cảm ơn bạn nhé

\(10A=\frac{10^{16}+10}{10^{16}+1}=\frac{10^{16}+1+9}{10^{16}+1}=1+\frac{9}{10^{16}+1}\)

\(10B=\frac{10^{17}+10}{10^{17}+1}=\frac{10^{17}+1+9}{10^{17}+1}=1+\frac{9}{10^{17}+1}\)

Nhận thấy: \(\frac{9}{10^{17}+1}< \frac{9}{10^{16}+1}\)=> 10B < 10A

=> A > B

A = ( 10^15+1 ) / ( 10^16+1 ) => 10A = ( 10^16+10 ) / ( 10^16+1 ) = 1 + ( 9/10^15+1 )

B = ( 10^16+1 ) / ( 10^17+1 ) => 10B = ( 10^17+10 ) / ( 10^17+1 ) = 1 + ( 9/10^16+1 )

Vì 10^15+1 < 10^16+1 nên 9/10^15+1 > 9/10^16+1 => 1 + ( 9/10^15+1 ) > 1 + ( 9/10^16+1 )

Vậy A > B

theo đè bài 

A>B

hok tốt

\(A=\frac{10^{15}+1}{10^{16}+1}\)

\(\Rightarrow10A=\frac{10^{16}+10}{10^{16}+1}=\frac{\left(10^{16}+1\right)+9}{10^{16}+1}=1+\frac{9}{10^{16}+1}\)

\(A=\frac{10^{16}+1}{10^{17}+1}\)

\(\Rightarrow10B=\frac{10^{17}+10}{10^{17}+1}=\frac{\left(10^{17}+1\right)+9}{10^{17}+1}=1+\frac{9}{10^{17}+1}\)

Vì \(\frac{9}{10^{16}+1}>\frac{9}{10^{17}+1}\left(Do10^{16}+1< 10^{17}+1\right)\)

\(\Rightarrow10A>10B\)

\(\Rightarrow A>B\)

Ta có :

\(10A=\frac{10^{16}+10}{10^{16}+1}=\frac{\left(10^{16}+1\right)+9}{10^{16}+1}=1+\frac{9}{10^{16}+1}\)

\(10B=\frac{10^{17}+10}{10^{17}+1}=\frac{\left(10^{17}+1\right)+9}{10^{17}+1}=1+\frac{9}{10^{17}+1}\)

Vì \(10^{16}+1< 10^{17}+1\) nên \(\frac{9}{10^{16}+1}>\frac{9}{10^{17}+1}\) \(\Rightarrow1+\frac{9}{10^{16}+1}>1+\frac{9}{10^{17}+1}\)

=> 10A > 10B Do đó A > B

Vậy A > B

\(A=\frac{10^{15}+1}{10^{16}+1}\)

\(B=\frac{10^{16}+1}{10^{17}+1}\)

Ta có:

\(A=\frac{10^{15}+1}{10^{16}+1}=\frac{\left(10^{15}+1\right).10}{\left(10^{16}+1\right).10}=\frac{10^{16}+10}{10^{17}+10}=\frac{10^{16}+1+9}{10^{17}+1+9}\)

Vì \(B=\frac{10^{16}+1}{10^{17}+1}< 1\)

\(\Rightarrow B=\frac{10^{16}+1}{10^{17}+1}< \frac{10^{16}+1+9}{10^{17}+1+9}=A\)

Vậy B < A

A=1/10

B=1/10

Vậy hai phân số A và B bằng nhau