cach lam bai : giup minh voi
tim x thuoc Z biet:
a, /x/+/y/=0
b, /x/ + /y/= 1
cac ban oi giup minh voi
1.tim a,b thuoc Z,biet:a.(2b-3)=-6
2.cho x,y thuoc Z thoa man x mu 2 +y mu 2 chia het cho 3.chung to x va y chia het cho 3.
Tim cac so nguyen x,y biet:a)*x2 -3*x+1 chia het cho x+2 b)x2-xy = 5x-4y-9 c) (x2-8)*(x2-15)<0 d) (x+1)2+(y+1)2+(x-y)2=2 e) (x2-4)x2>0 ai lam truoc minh tick,mai minh di hoc rui,lam giup minh di pls Thank ban truoc ne ;(
Tim x , y , z biet: x /y+z+1 = y/ z+x+2 = z/ x+y−3 =x+y+z Cach lam ho minh voi
1+2+3+......+x=y
giai giup mk nha moi nguoi !!!! neu ro cach lam bai
gia su x=a/m, y=b/m (a,b,m thuoc z, m>0) va x<y.hay chung to rang neu chon z=a+b/2m thi ta co x<z<y.
minh moi hoc lop 7 minh ko hieu bai nay ai giai giup minh voi
tim x thuoc Z biet:
|x-5|+x+3=16
|x-4|>x+2
||x+5|-4|=3
Cach lam nua nhe
minh chua biet cach lam,cac ban phaiviet cach lam vao minh moi tick
ko bat buoc lam tat ca cac cau
1/x+1/y=1/2(x,y thuoc z)
giup minh voi
Tim x biet:
a, 25-y2=4(x-2016)2 (x , y thuoc Z)
b, \(2016^{\left|x^2-y\right|-8}\)\(+y^2-1=1\)
Trinh bay cach lam ho minh nhe
Tim x , y , z biet:
\(\frac{x}{y+z+1}=\frac{y}{z+x+2}=\frac{z}{x+y-3}=x+y+z\)
Cach lam ho minh voi