tap hop cac so nguyen x thoa man 15-|x-2|=12
tap hop cac so nguyen x thoa man 15-/x-2\=12 la
15- |x - 2| = 12
|x - 2| = 3
x - 2 = 3 => x= 5
x - 2= -3 => x = -1
{-1 ; 5}
so phan tu cua tap hop cac so nguyen x thoa man:15-lx-2l bang 12
tap hop cac so nguyen x thoa man -3 x |2x - 3 |= -12
tap hop cac so nguyen x thoa man |x+2| = 10
tap hop cac so nguyen x thoa man |x+2|=10
Nếu x + 2 = 10
=> x = 10 - 2 = 8
Nếu x + 2 = -10
=>x = -10 - 2 = -12
Vậy x = 8 ; -12
Nếu x + 2 = 10
=> x = 10 - 2 = 8
Nếu x + 2 = -10
=>x = -10 - 2 = -12
Vậy x thuộc {8; -12}
x=-12 hoặc 8
đúng không ? k cho mình nhé.
Tap hop cac so nguyen x thoa man /+2/ = 10 la
tap hop cac so nguyen x thoa man /(x-23)(x+12)/=0
nhap theo thu tu tang dan
|(x-23)(x+12)|=0
=>(x-23)(x+12)=0
=>x-23=0 hoặc x+12=0
x=0+23 x=0-12
x=23 x=-12
=>xE{-12;23}
tap hop tat ca cac so nguyen x thoa man ( 2- x ).(x+7) = 0
\(\orbr{\begin{cases}2-x=0\\x+7=0\end{cases}}\)
\(\orbr{\begin{cases}x=0+2\\x=0-7\end{cases}}\)
\(\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
rồi kết luận nhé bạn
\(\Leftrightarrow\orbr{\begin{cases}2-x=0\\x+7=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
Vay.........
\(\left(2-x\right)\left(x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2-x=0\\x+7=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
Vậy\(x\in\left\{-7;2\right\}\)
tap hop cac so nguyen x thoa man(|x -2013|+2014)(x^2+5)(9-x^2)