20112-(304+2012)+(2013+304)

=20112-304-2012+2013+304

=20112+(-2012+2013)+(-304+304)

=20112+1+0=20113

\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}=\frac{\left(3^2\right)^{14}.25^5.\left(2^3\right)^7}{2^{12}.\left(3^2\right)^{12}.\left(25^2\right)^3.\left(2^3\right)^3.3^3}=\)\(\frac{3^{28}.25^5.2^{21}}{2^{12}.2^9.3^{24}.3^3.25^6}=\frac{3^{28}.25^5.2^{21}}{2^{21}.3^{27}.25^6}\)\(=\frac{3}{25}\)

a) 2012 - ( 304 + 2012 ) + ( 2013 + 304 )

= 2012 - 304 - 2012 + 2013 + 304 

= 2012 + ( - 304 ) + ( - 2012 ) + 2013 + 304

= [ 2012 + ( - 2012 ) ] + [ ( - 304 ) + 304 ] + 2013

= 0 + 0 + 2013

= 2013

b) \(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}\)

\(=\frac{\left(3^2\right)^{14}.\left(5^2\right)^5.\left(2^3\right)^7}{\left(3^2.2\right)^{12}.\left(5^4\right)^3.\left(2^3.3\right)^3}\)

\(=\frac{3^{28}.5^{10}.2^{21}}{3^{24}.2^{12}.5^{12}.2^9.3^3}\)

\(=\frac{3^{28}.5^{10}.2^{21}}{3^{27}.5^{12}.2^{21}}\)

\(=\frac{3}{5^2}=\frac{3}{25}\)

a) 2012 - ( 304 + 2012 ) + (2013 + 304 )

= 2012 - 304 +2012 + 2013 + 304

= ( 2012 - 2012 ) + ( 304 + 304 ) + 2013

= 0 + 608 + 2013

= 2621

Chờ một chút để minh suy nghĩ 

ok bạn

2012-304-2012+2013+304

=(2012-2012)+(304-304)+2013

=0+0+2013

=2013

2012 - ( 304 + 2012 ) + ( 2013 + 304 )

= 2012 - 2316 + 2317

= -304 + 2317

= 2013

80 + ( 4,52 - 3,24 )= 80 + 1,28 = 81,28

80 + ( 4.52 - 3.24) = 81.28 

80 + ( 4.52 - 3.24)

80 + ( 208 - 72 )

80 + 136 

= 216 

MK làm đúng thì k  nha 

\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}\)

\(=\frac{\left(3^2\right)^{14}.\left(5^2\right)^5.\left(2^3\right)^7}{\left(2.3^2\right)^{12}.\left(5^4\right)^3.\left(2^3.3\right)^3}\)

\(=\frac{3^{28}.5^{10}.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3}\)

\(=\frac{3^{28}.5^{10}.2^{21}}{2^{21}.3^{25}.5^{12}}\)

\(=\frac{3^3.1.1}{1.1.5^2}\)

\(=\frac{27}{25}\)