tìm x:
\(\frac{37-x}{x+13}=\frac{3}{7}\)
xin giúp dùm
tìm x:
\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Leftrightarrow3.\left(x+13\right)=7.\left(37-x\right)\)
\(\Leftrightarrow3.x+13.3=7.37-7.x\)
\(\Leftrightarrow3x+39=-7x+259\)
\(\Leftrightarrow3x+7x=259-39\)
\(\Leftrightarrow10x=220\)
\(\Leftrightarrow x=22\)
37−xx+13=3737−xx+13=37
⇔3.(x+13)=7.(37−x)⇔3.(x+13)=7.(37−x)
⇔3.x+13.3=7.37−7.x⇔3.x+13.3=7.37−7.x
⇔3x+39=−7x+259⇔3x+39=−7x+259
⇔3x+7x=259−39⇔3x+7x=259−39
⇔10x=220⇔10x=220
⇔x=22
Tìm x
\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\frac{3x-y}{x+y}=\frac{3}{4}\)
\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Leftrightarrow\left(37-x\right).7=3.\left(x+13\right)\)
\(\Leftrightarrow259-7x=3x+39\)
\(\Leftrightarrow10x=220\)
\(\Leftrightarrow x=22\)
Vậy ...
Bài còn lại tương tự
tìm x:
\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Leftrightarrow7\left(37-x\right)=3\left(x+13\right)\Leftrightarrow259-7x=3x+39\Leftrightarrow259-39=3x+7x\)
\(10x=220\Leftrightarrow x=22\)
Tìm x
\(\frac{37-x}{x+13}=\frac{3}{7}\)
(37-x) . 7 =3. (x+13)
=>259 -7x=3x+39
=>.259-39=3x+7x
=>220=10x
=>x=22
Tìm x biết \(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\frac{37-x}{x+13}=\frac{3}{7}\)
=> 3.(x+13)=7.(37-x)
=> 3x+39= 259-7x
=> 3x+7x=259-39
=> 10x= 220
=> x=22
\(\frac{a}{b}\) ai bày mk viết phân số với
Tìm x, biết:
\(\frac{37-x}{x+13}=\frac{3}{7}\)
=> (37 - x) . 7 = (x + 13) . 3
259 - 7x = 3x + 39
-7x - 3x = 39 - 259
-10x = -220
x =22
Tìm x biết :
\(\frac{37-x}{x+13}=\frac{3}{7}\)
=> (37-x).7=(x+13).3
=> 259-7x=3x+39
=> -7x-3x=39-259
=> -10x=-220
=> x=-220:(-10)
=> x=22
A=\(\frac{\sqrt{x}-3}{\sqrt{x}+2}+\frac{\sqrt{x}+2}{\sqrt{x}-3}-\frac{4\sqrt{x}+13}{x-\sqrt{x}-6}\)
tìm x để A đạt giá trị nhỏ nhất
giúp dùm mình
tìm x biết :
a , 0,4 : x = x : 0,9
b, \(b,13\frac{1}{3}:1\frac{1}{3}=26:\left(2x-1\right)\)
c, \(c,\frac{37-x}{x+13}=\frac{3}{7}\)
a) 0,4:x=x:0,9
0,4.0,9=x2
0,36 =x2
\(\sqrt{0,36}\)=x
0,6 =x
a) 0,4 : x = x : 0,9 x^2=0,9 . 0,4 x^2=(0,6)^2 =>x=+_6