\(\frac{11.12+33.36+55.60}{22.24+66.72+110.120}=\frac{11.12+33.36+55.60}{2.11.2.12+2.33.2.36+2.55.2.60}=\frac{11.12+33.36+55.60}{4.11.12+4.33.36+4.55.60}=\frac{11.12+33.36+55.60}{4.\left(11.12+33.36+55.60\right)}=\frac{1}{4.1}=\frac{1}{4}\)

= 200,4642086 nha

18508

sai hết rồi

\(\frac{10.11+55.60+70.77}{11.12+55.60+77.84}=\frac{10.11+5.11.6.10+7.10.7.11}{11.12+5.11.5.12+7.11.7.12}=\frac{10.11+30.10.11+49.10.11}{11.12+25.11.12+49.11.12}=\frac{10.11\left(1+30+49\right)}{11.12\left(1+25+49\right)}=\frac{5.80}{6.75}=\frac{8}{9}\)

A= \(\dfrac{10.11.\left(1+5.5+7.7\right)}{11.12.\left(1+5.5+7.7\right)}=\dfrac{10}{12}=\dfrac{5}{6}\)

11 x 12 + 33 x 36 + 55 x 60

= 11 x 12 + 11 x 3 x 12 x 3 + 11 x 5 x 12 x 5

= 11 x 12 x (3 + 3 + 5 + 5)

= 11 x 12 x 16

= 9112

65/681

k giúp mk 1 k với

=110+110.25+110.49/132+132.25+132.49

=110(1+25+49)/132(1+25+49)

=110/132=5/6

\(a,\frac{7}{x}=\frac{x}{28}=>x\cdot x=28\cdot7=>x^2=196=>x^2=14^2\)\(=>x=14\)

\(b,\frac{10+x}{x+17}=\frac{3}{4}=>\left(10+x\right)\cdot4=\left(x+17\right)\cdot3=>40+x4=x3+51\)\(=>x4-x3=51-40=>x=11\)