Giải Phương Trình Sau :
\(\frac{x}{2x-6}-\frac{x}{2x+2}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
Những câu hỏi liên quan
GIẢI PHƯƠNG TRÌNH SAU
A) \(\frac{X^2+2X+1}{X^2+2X+2}+\frac{X^2+2X+2}{X^2+2X+3}=\frac{7}{6}\)
B) \(\frac{\left(X^2-3X-4\right)^4}{\left(X-3\right)^5\left(X+2\right)^3}+\frac{\left(X^2+4X+3\right)^6}{\left(X-3\right)^3\left(X+2\right)^5}=0\)
GIẢI PHƯƠNG TRÌNH\(\frac{x}{2x-6}+\frac{x}{2x+2}-\frac{2x}{\left(x+1\right)\left(x-3\right)}=0\)
\(\frac{x}{2\left(x-3\right)}+\frac{x}{2\left(x+1\right)}-\frac{2x}{\left(x+1\right)\left(x+3\right)}=0\)
\(\frac{x\left(x+1\right)}{2\left(x-3\right)\left(x+1\right)}+\frac{x\left(x-3\right)}{2\left(x-3\right)\left(x+1\right)}-\frac{2.2x}{2\left(x-3\right)\left(x+1\right)}=0\)
\(\frac{x^2+x}{2\left(x-3\right)\left(x+1\right)}+\frac{x^2-3x}{2\left(x-3\right)\left(x+1\right)}-\frac{4x}{2\left(x-3\right)\left(x+1\right)}=0\)
\(\frac{x^2+x+x^2-3x-4x}{2\left(x-3\right)\left(x+1\right)}=0\)
\(\frac{2x^2-6x}{2\left(x-3\right)\left(x+1\right)}=0\)
=>\(2x^2-6x=0\)
\(2x\left(x-3\right)=0\)
=>\(x=0\)
\(x=3\)
Giải phương trình
\(\frac{13}{\left(2x+7\right)\left(x-3\right)}+\frac{1}{2x+7}=\frac{6}{x^2-9}\)
\(\left(1-\frac{2x-1}{x+1}\right)+6\left(1-\frac{2x-1}{x+1}\right)^2=\frac{12\left(2x-1\right)}{x+1}-20\)
13(x+3)+(x+3)(x-3)=6(2x+7)
13x+39+x^2-9-12x-42=0
x^2+x-12=0
x=3 và x=-4
**** cho mk nha!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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a,Giải phương trình sau : (2x + 3)(x-5)=42 +6x
b, Gải phương trình sau: \(\frac{x}{2x-6}-\frac{x}{2x+2}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
c,Gải bất phương trình sau và biểu diễn nghiệm trên trục số : \(\frac{12x+1}{12}\le\frac{9x+1}{3}-\frac{8x+1}{4}\)
Giải các phương trình sau:a)frac{left(9x-0.7right)}{4}-frac{left(5x-1.5right)}{7}frac{left(7x-1.1right)}{3}-frac{5left(0.4-2xright)}{6}b)frac{3x-1}{x-1}-frac{2x+5}{x+3}1-frac{4}{left(x-1right)left(x+3right)}c)frac{3}{4left(x-5right)}+frac{15}{50-2x^2}-frac{7}{6left(x+5right)}d)frac{8x^2}{3left(1-4xright)^2}frac{2x}{6x-3}-frac{1+8x}{4+8x}
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Giải các phương trình sau:
a)\(\frac{\left(9x-0.7\right)}{4}-\frac{\left(5x-1.5\right)}{7}=\frac{\left(7x-1.1\right)}{3}-\frac{5\left(0.4-2x\right)}{6}\)
b)\(\frac{3x-1}{x-1}-\frac{2x+5}{x+3}=1-\frac{4}{\left(x-1\right)\left(x+3\right)}\)
c)\(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=-\frac{7}{6\left(x+5\right)}\)
d)\(\frac{8x^2}{3\left(1-4x\right)^2}=\frac{2x}{6x-3}-\frac{1+8x}{4+8x}\)
Giải phương trình
2.
a. \(\frac{\left(x-2\right)^2}{3}-\frac{\left(2x-3\right).\left(2x+3\right)}{8}+\frac{\left(x-4\right)^2}{6}=0\)
c. \(x+\frac{2x+\frac{x-1}{5}}{3}=1-\frac{3x-\frac{4-2x}{3}}{5}\)
a, \(\frac{\left(x-2\right)^2}{3}-\frac{\left(2x-3\right).\left(2x+3\right)}{8}+\frac{\left(x-4\right)^2}{6}=0\)
\(\Leftrightarrow\frac{x^2-4x+4}{3}+\frac{9-4x^2}{8}+\frac{x^2-8x+16}{6}=0\)
\(\Leftrightarrow\frac{8\left(x^2-4x+4\right)+3\left(9-4x^2\right)+4\left(x^2-8x+16\right)}{24}=0\)
\(\Leftrightarrow\frac{8x^2-32x+32+27-12x^2+4x^2-32x+64}{24}=0\)
\(\Leftrightarrow\frac{123-64x}{24}=0\Leftrightarrow123-64x=0\Leftrightarrow x=\frac{123}{64}\)
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Giải các phương trình sau :a,6x^2-5x+32x-3xleft(3-2xright)b,frac{2left(x-4right)}{4}-frac{3+2x}{10}x+frac{1-x}{5}c,frac{2x}{3}+frac{3x-5}{4}frac{3left(2x-1right)}{2}-frac{7}{6}d,frac{6x+5}{2}-frac{10x+3}{4}2x+frac{2x+1}{2}e,left(x-4right)left(x+4right)-2left(3x-2right)left(x-4right)^2
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Giải các phương trình sau :
\(a,6x^2-5x+3=2x-3x\left(3-2x\right)\)
\(b,\frac{2\left(x-4\right)}{4}-\frac{3+2x}{10}=x+\frac{1-x}{5}\)
\(c,\frac{2x}{3}+\frac{3x-5}{4}=\frac{3\left(2x-1\right)}{2}-\frac{7}{6}\)
\(d,\frac{6x+5}{2}-\frac{10x+3}{4}=2x+\frac{2x+1}{2}\)
\(e,\left(x-4\right)\left(x+4\right)-2\left(3x-2\right)=\left(x-4\right)^2\)
a) <=> \(6x^2-5x+3-2x+3x\left(3-2x\right)=0\)
<=> \(6x^2-5x+3-2x+9x-6x^2=0\)
<=> \(2x+3=0\)
<=> \(x=\frac{-3}{2}\)
b) <=> \(10\left(x-4\right)-2\left(3+2x\right)=20x+4\left(1-x\right)\)
<=> \(10x-40-6-4x=20x+4-4x\)
<=> \(6x-46-16x-4=0\)
<=> \(-10x-50=0\)
<=> \(-10\left(x+5\right)=0\)
<=> \(x+5=0\)
<=> \(x=-5\)
c) <=> \(8x+3\left(3x-5\right)=18\left(2x-1\right)-14\)
<=> \(8x+9x-15=36x-18-14\)
<=> \(8x+9x-36x=+15-18-14\)
<=> \(-19x=-14\)
<=> \(x=\frac{14}{19}\)
d) <=>\(2\left(6x+5\right)-10x-3=8x+2\left(2x+1\right)\)
<=> \(12x+10-10x-3=8x+4x+2\)
<=> \(2x-7=12x+2\)
<=> \(2x-12x=7+2\)
<=> \(-10x=9\)
<=> \(x=\frac{-9}{10}\)
e) <=> \(x^2-16-6x+4=\left(x-4\right)^2\)
<=> \(x^2-6x-12-\left(x-4^2\right)=0\)
<=> \(x^2-6x-12-\left(x^2-8x+16\right)=0\)
<=> \(x^2-6x-12-x^2+8x-16=0\)
<=> \(2x-28=0\)
<=> \(2\left(x-14\right)=0\)
<=> x-14=0
<=> x=14
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Luffy , cậu sai câu c nhé , kia là -17 ạ => x=17/19
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1 Giải phương trình
\(a.\left(x+3\right)\left(x-2\right)+2\left(x+1\right)^2=\left(x-3\right)^2-2x^2+4x\)
\(b.\left(x+1\right)^3-\left(x+2\right)\left(x-4\right)=\left(x-2\right)\left(x^2+2x+4\right)+2x^2\)
\(c.\frac{x^2+2x+1}{x2+2x+2}+\frac{x^2+2x+2}{x^2+2x+3}=\frac{7}{6}\)
\(a.\Leftrightarrow x^2+x-6+2x^2+4x+2=x^2-6x+9-2x^2+4x\)
\(\Leftrightarrow4x^2+7x-13=0\)(pt vô nghiệm)
\(b.\Leftrightarrow x^3+3x^2+3x+1-x^2+2x+8=x^3-8+2x^2\)
\(\Leftrightarrow5x=-17\Rightarrow x=\frac{-17}{5}\)
Đặt \(t=x^2+2x+2\left(t\ge1\right)\)
\(c.\Leftrightarrow\frac{t-1}{t}+\frac{t}{t+1}=\frac{7}{6}\)\(\Leftrightarrow\frac{t^2-1+t^2}{t^2+t}=\frac{7}{6}\)\(\Leftrightarrow12t^2-6=7t^2+7t\)
\(\Leftrightarrow5t^2-7t-6=0\Rightarrow\orbr{\begin{cases}t=2\left(tm\right)\\t=\frac{-3}{5}\left(l\right)\end{cases}}\)
\(\Rightarrow x^2+2x+2=2\Rightarrow x=-2\)
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Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
\(a,\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
\(b,\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)