Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)
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Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang tong sau lon hon 1
N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)
Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)
Khong thuc hien phep tinh de tim ket qua.Hay chung minh rang cac tong sau lon hon 1
M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)
Chứng minh tổng sau lớn hơn 1 : \(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)
\(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}=\frac{41}{36}>\frac{36}{36}=1\)
Vậy P > 1.
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khong thuc hien phep tinh,hay tim y trong tung phep tinh sau day(nho giai thich do nha)
y+17,28=17,28\(\frac{18}{9}\)x y =2y:6=0\(5\frac{2}{8}\):y=\(5\frac{2}{8}\)
1.y+17,28=17,28
=>y=0
2.18/9x y=2 (chịu)
3.y:6=0
=>y=0
4.\(5\frac{2}{8}:y=5\frac{2}{8}\)
=>\(\frac{5}{4}:y=\frac{5}{4}\)
=>y=1
Nhớ k mk nha
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Chứng minh rằng : Các tổng sau lớn hơn 1
a) \(\frac{3}{8}+\frac{3}{7}+\frac{3}{15}\)
b) \(\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)
khong thuc hien phep tinh o mau , hay so sanh cac phan so sau
a) A = \(\frac{244.395-151}{244+395.243}\)va B=\(\frac{423134.846267-423133}{4423133.846267+423134}\)
Ai giup minh voi
ban cu chon hen xui di 50xui va 50mayman
Khong thuc hien phep tinh o mau, hay so sanh cac phan so sau
b) M = \(\frac{53.71-18}{71.555552+53}\); N=\(\frac{54.107-53}{53.107+54}\)va P=\(\frac{135.269-133}{134.269+135}\)
Tinh nhanh:
\(\frac{6}{2.5}+\frac{6}{5.8}+\frac{6}{8.11}+......+\frac{6}{299.302};\)
So sanh cac phan so sau ma khong can thuc hien cac phep tinh o mau
\(A=\frac{54.107-53}{53.107+54}\) \(B=\frac{135.269-133}{134.269+135}\)
\(\frac{6}{2.5}+\frac{6}{5.8}+\frac{6}{8.11}+...+\frac{6}{299.302}\)
\(=2\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+..+\frac{3}{299.302}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{299}-\frac{1}{302}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{302}\right)=2.\frac{75}{151}=\frac{150}{151}\)
\(A=\frac{54.107-53}{53.107+54}=\frac{\left(53+1\right).107-53}{53.107+54}\)
\(=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)
\(B=\frac{135.269-133}{134.269+135}=\frac{\left(134+1\right)269-133}{134.269+135}\)
\(=\frac{134.269+269-133}{134.269+135}=\frac{134.269+136}{134.269+135}>1\)
\(\Rightarrow B>A\)
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