bạn tách các số ra:

(2*8*16)(a^3*a^2*a^3)(x^2*x^3*x^3)(y*y^4*y^3)

=256a^8x^8y^8=(2axy)^8

CHÚ BẠN HỌC TỐT!!!

(2a³x²y).(8a²x³y⁴).(16a³x³y³) = 256a⁸x⁸y⁸ = (2axy)⁸

2^5.2^4:2^2.1/16=(2^7)/16

\(\frac{32\cdot2^4}{2^2\cdot\frac{1}{16}}\)

\(=\frac{2^5\cdot2^4}{\frac{4}{16}}\)

\(=\frac{2^9}{\frac{1}{4}}\)

\(=2^9\cdot4\)

\(=2^9\cdot2^2\)

\(=2^{11}\)

=32 X 16 : ( 4 X 1/16)=2048

    32 . 2⁴ : ( 2² . 1/16 ) 

=  2⁵ . 2⁴ : 1/2²

=  2⁹ . 2²

= 2¹¹

\(\frac{2^7}{16}\)

\(2^{11}\)

\(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}\)

\(=\frac{3^2}{3^3}\cdot\frac{81\cdot81}{81\cdot3}\)

\(=\frac{1}{3}\cdot\frac{27}{1}\)

\(=9=\left(\pm3\right)^2\)

\(a,3^2\cdot\frac{1}{243}=3^2\cdot\frac{1}{3^5}=\frac{1}{3^3}=\frac{1^3}{3^3}=\left(\frac{1}{3}\right)^3\)

\(b,81^2\cdot\frac{1}{3^3}=\left(3^4\right)^2\cdot\frac{1}{3^3}=3^8\cdot\frac{1}{3^3}=3^5\)

a) \(3^2.\frac{1}{243}=\frac{1.3^3}{243}=\frac{3^2}{243}=\frac{3^2}{3^5}=\frac{1}{3^3}=\frac{1}{27}\)

b) \(81^2.\frac{1}{3^3}=\frac{1.81^2}{3^3}=\frac{81^2}{3^3}=\frac{3^8}{3^3}=3^5=243\)

=(1/2) mu 15*(1/2 mu 2) mu 20

=1/2 mu 15*1/2 mu 40

=1/2 mu 55

Dung thi k ung ho minh nha!Thanks!!!

DỂ QUÁ!!!!!!!!!!!!!!!!!!!!!!!!

tui hk biết làm

\(4x^2y^4-\left(3xy^2-1\right)^2\)

\(=\left(2xy^2-3xy^2+1\right)\left(2xy^2+3xy^2-1\right)\)

\(=\left(1-xy^2\right)\left(5xy^2-1\right)\)

p/s: chúc bạn học tốt