(\(\frac{1313}{1414}\)+\(\frac{10}{160}\))-(\(\frac{130}{140}\)-\(\frac{1515}{1616}\))
G= (1313/1414+10/160)-(130/140-1515/1616)
G = \(\left(\dfrac{1313}{1414}+\dfrac{10}{160}\right)-\left(\dfrac{130}{140}-\dfrac{1515}{1616}\right)\)
= \(\left(\dfrac{13}{14}+\dfrac{1}{16}\right)-\left(\dfrac{13}{14}-\dfrac{15}{16}\right)\)
= \(\dfrac{13}{14}+\dfrac{1}{16}-\dfrac{13}{14}+\dfrac{15}{16}\)
= \(\dfrac{1}{16}+\dfrac{15}{16}=1\)
thực hiện phép tính bằng cách hợp lý :
a/(-2013) . 2014 + 1007 .26
b/(1313/1414 + 10/160) - (130/140 - 1515/1616)
a.(-2013).2014+1007.26
=(-2013).2.1007+1007.26
=(-4026).1007+1007.26
=1007.(-4026+26)
=1007.(-4000)
=-4028000
b.(1313/1414 + 10/160) - (130/140 - 1515/1616)
=(13/14+1/16)-(13/140-(1/16+15/16)
=13/14+1/16-13/14+15/16
=(13/14+13/14)-(1/16+15/16)
=26/14-16/16
=26/14-1
=26/14-14/14
=12/14
=6/7
ấn đúng cho mình nhé
1)tính 1 cách hợp lí: a) A=\(\left(\frac{1313}{1414}+\frac{10}{160}\right)-\left(\frac{130}{140}+\frac{1515}{1616}\right)\)
b)B=\(\left(\frac{2^6.3^5-9^2.4^3}{4^3.9^2-3^4.8^2}\right)\)
2)Chứng minh rằng:C=\(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}>\frac{7}{12}\)
Mình làm luôn
a,A\(=\left(\frac{1313}{1414}-\frac{130}{140}\right)+\left(\frac{1515}{1616}+\frac{10}{160}\right)\)
\(=0+1\)
=1
b,Rút gọn p/s giống nhau ở tử và mẫu :26 với 82, 92 với 92, 35 với 34 thì còn3
Sau khi rút gọn rồi thì ta còn p/s:\(\frac{1.3-1.1}{1.1.1.1}=3\)
Câu 2 mình chịu
so sánh :
\(\frac{111111}{666665}\)và\(\frac{1212+1313+1414+1515+1616}{1717+1818+1919+2020+2121}\)
Ai làm đúng và nhanh nhất mk k cho
cái thứ hai lớn hơn
Ta có : \(\frac{1212+1313+1414+1515+1616}{1717+1818+1919+2020+2121}=\frac{12+13+14+15+16}{17+18+19+20+21}=\frac{28\cdot\frac{5}{2}}{38\cdot\frac{5}{2}}=\frac{14}{19}\)
Dễ thấy \(\frac{111111}{666665}< \frac{1}{2}\) ( do 111111 < 666665/2 ) và \(\frac{14}{19}>\frac{1}{2}\) ( do 14 > 19/2 )
Vậy \(\frac{111111}{666665}< \frac{1212+1313+1414+1515+1616}{1717+1818+1919+2020+2121}\)
bài 1: Tính biểu thức 1 cách hợp lý\(\frac{1010+1111+1212+1313+1414+1515+1616+1717}{2020+2121+2222+2323+2424+2525+2626+2727}\)
bài 2: Tím y là số tự nhiên
\(2< \)( \(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{4}{96}\)):5 x y \(< \frac{5}{6}\)
\(\frac{1010+1111+1212+1313+1414+1515+1616+1717}{2020+2121+2222+2323+2424+2525+2626+2727}\)
\(=\frac{101.10+101.11+...+101.17}{101.20+101.21+...+101.27}\)
\(=\frac{101.\left(10+11+...+17\right)}{101.\left(20+21+...+27\right)}\)
\(=\frac{108}{188}\)
\(=\frac{27}{47}\)
\(2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{4}{96}\right)\cdot5.y>\frac{5}{6}\)
\(\Rightarrow2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{1}{24}\right):5.y>\frac{5}{6}\)
\(\Rightarrow2>\left(\frac{20}{120}+\frac{16}{120}+\frac{9}{120}+\frac{5}{120}\right):5.y>\frac{5}{6}\)
\(\Rightarrow2>\frac{5}{12}:5.y>\frac{5}{6}\)
\(\Rightarrow2>\frac{1}{12}.y>\frac{5}{6}\)
Đặt :\(\frac{1}{12}.y=2\Rightarrow y=2:\frac{1}{12}=24\)
\(\frac{1}{12}.y=\frac{5}{6}\Rightarrow y=\frac{5}{6}:\frac{1}{12}=10\)
\(\Rightarrow24>y>10\)
\(\Rightarrow y\in\left\{11;12;...;23\right\}\)
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}=\frac{9999}{13635}=\frac{11}{15}\)
tính nhanh
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)
\(=\frac{101\times\left(14+15+16+17+18+19\right)}{101\times\left(20+21+22+23+24+25\right)}\)
\(=\frac{14+15+16+17+18+19}{20+21+22+23+24+25}\)
+) Tử số :
Số các số hạng là : ( 19 - 14 ) : 1 + 1 = 6 ( số )
Tổng là : ( 19 + 14 ) x 6 : 2 = 99
+) Mẫu số :
Số các số hạng là : ( 25 - 20 ) : 1 + 1 = 6 ( số )
Tổng là : ( 25 + 20 ) x 6 : 2 = 135
\(\Leftrightarrow\frac{99}{135}=\frac{11}{15}\)
Bài 1: Tính nhanh
a) \(\frac{1111+1212+1313+1414+1515+1616}{2020+2121+2222+2323+2424+2525}\)
b) \(\frac{5,4:0,4\cdot1420+4,5\cdot780\cdot3}{3+6+9+12+......+24+27}\)
c) \(\frac{7,2:2\cdot28,6+1,43\cdot2\cdot64}{2+2+4+6+10+16+......+110}\)
Bài 2: Tính tổng
D = 1 x 2 + 2 x 3 + 3 x 4 + ...... +99 x 100
Thực hiện phép tính:
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)
\(=\frac{101\left(14+15+16+17+18+19\right)}{101\left(20+21+22+23+24+25\right)}\)
\(=\frac{\left(19+14\right)\left(19-14+1\right):2}{\left(25+20\right)\left(25-20+1\right):2}\)
=\(\frac{33.6:2}{45.6:2}=\frac{33}{45}=\frac{11}{15}\)