x+1+2+3+....+100 = 250000

x + 5050 = 250000

x = 250000 - 5050

x = 2244950

x+1+2+3+....+100 = 250000
x + 5050 = 250000
x = 250000 - 5050
x = 2244950

@@ hacker

x+1+2+3+4+5+6+7+.....+100=250000

suy ra x+(1+100)x100:2=250000

suy ra x+101x50=250000

suy ra x+5050=250000

suy ra x=250000-5050

x=244950

x(2511+2489)=250000
x*5000=250000
x=50

X=50000

kết bạn với mjk nhé nguyen_huu_the

X : 5 = 250000

X = 250000 x 5

X=1250000

X : 5=250 000

     X=250 000 x 5

     X=1 250 000

1, đúng òi

2, đúng òi

3, sai òi

4, đúng òi

5, s

x = -4 hoặc x = 23 

 20 . 2^x + 1 = 10.4^2 + 1 

 20 . 2^x + 1 = 10 . 16 + 1

20 . 2^x + 1 = 161

20 . 2^x = 161 - 1

20 . 2^x = 160

2^x = 8

2^x = 2^3

=> x = 3

Ban co giai dc phan 2 ko ?

( 4 - x : 2 )^3 - 1 = 2 . ( 2^3 - 5 : 2^0 )

( 4 - x : 2 )^3 - 1 = 2 . ( 8 - 5 : 1 )

( 4 - x : 2 )^3 - 1 = 2 . 3

( 4 - x : 2 )^3 - 1 = 6

( 4 - x : 2 )^3  = 7

=> ko tìm đc x

1) \(M=\frac{x^2+y^2+7}{x^2+y^2+5}=1+\frac{2}{x^2+y^2+5}\)

Ta có: \(x^2+y^2\ge0,\forall x;y\)

=> \(x^2+y^2+5\ge5\) với mọi x; y 

=> \(\frac{2}{x^2+y^2+5}\le\frac{2}{5}\)

=> \(M\le1+\frac{2}{5}=\frac{7}{5}\)

Dấu "=" xảy ra <=> x = y = 0 

Vậy max M = 7/5 đạt tại x = y = 0 

2) \(f\left(x-1\right)=x^2-3x+5=x^2-x-2x+2+3\)

\(=x\left(x-1\right)-2\left(x-1\right)+3=x\left(x-1\right)-\left(x-1\right)-\left(x-1\right)+3\)

\(=\left(x-1\right)\left(x-1\right)-\left(x-1\right)+3\)

=> \(f\left(x\right)=x.x-x+3=x^2-x+3\)