\(\frac{-3}{4}.26\frac{1}{5}+\frac{3}{4}.44\frac{1}{5}\)
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TÍNH:\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}.44\frac{1}{5}\)
\(\frac{3}{4}\cdot26\frac{1}{5}-\frac{3}{4}\cdot44\frac{1}{5}\)
\(=\frac{3}{4}\cdot\frac{131}{5}-\frac{3}{4}\cdot\frac{221}{5}\)
\(=\frac{3}{4}\cdot\left(\frac{131}{5}-\frac{221}{5}\right)\)
\(=\frac{3}{4}\cdot\left(-18\right)\)
\(=-\frac{27}{2}\)
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\(\frac{3}{4}\).26\(\frac{1}{5}\)-\(\frac{3}{4}\).44\(\frac{1}{5}\)
\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}.44\frac{1}{5}\)
\(=\frac{3}{4}.\left(26\frac{1}{5}-44\frac{1}{5}\right)\)
\(=\frac{3}{4}.\left(-18\right)\)\(=\frac{-27}{2}\)
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\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}.44\frac{1}{5}\)
= \(\frac{3}{4}.\left(26\frac{1}{5}-44\frac{1}{5}\right)\)
= \(\frac{3}{4}\) . (-18)
= \(\frac{-27}{2}\)
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\(\frac{3}{4}\).26\(\frac{1}{5}\)-\(\frac{3}{4}\).44\(\frac{1}{5}\)
\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}44\frac{1}{5}\)
= \(\frac{3}{4}\left(26\frac{1}{5}-44\frac{1}{5}\right)\)
= \(\frac{3}{4}\left(26+\frac{1}{5}-44-\frac{1}{5}\right)\)
=\(\frac{3}{4}.\left(-18\right)\)
=-13,5
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\(\frac{3}{4}\).26\(\frac{1}{5}\)-\(\frac{3}{4}\).44\(\frac{1}{5}\)
Ta có: 3/4. 26/1/5 - 3/4.44/1/5
= 3/4.(26/1/5-44/1/5)
= 3/4.(26-44)
= 3/4. (-18)
= -27/2
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\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)
sư phụ thử làm nha
Tất cả đều trừ 1 vào mỗi thừa số=>tử số là:x-29(cái cuối+3)
=> cả cái đó=0
=> x-29=0
=>x=29
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\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)
\(\Rightarrow\left(\frac{x-2}{27}-1\right)+\left(\frac{x-3}{26}-1\right)+\left(\frac{x-4}{25}-1\right)+\left(\frac{x-5}{24}-1\right)+\left(\frac{x-44}{5}+3\right)=0\)
\(\Rightarrow\frac{x-29}{27}+\frac{x-29}{26}+\frac{x-29}{25}+\frac{x-29}{24}+\frac{x-29}{5}=0\)
\(\Rightarrow\left(x-29\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\right)=0\)
\(\Rightarrow x-29=0\)
\(\Rightarrow x=29\)
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Thực hiên các phép tính (bằng cách hợp lý ,nếu có thể)aleft(frac{3}{7}-frac{5}{2}-frac{3}{5}right)-left(-frac{4}{7}-frac{3}{2}+frac{2}{5}right) c)left(-frac{1}{2}right)^2:frac{1}{4}-2.left(frac{-1}{2}right)^3 e)frac{2^9.4^{10}}{8^8} bleft(frac{2}{5}right)^2+5frac{1}{2}.left(4,5-2right)+frac{2^3}{left(-4right)} d)sqrt{16}.1frac{3}{4}+frac{1}{4}-7 f)frac{3}{4}.26frac{1}{5}-frac{3}{4}.44frac{1}{5}
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Thực hiên các phép tính (bằng cách hợp lý ,nếu có thể)
a\(\left(\frac{3}{7}-\frac{5}{2}-\frac{3}{5}\right)-\left(-\frac{4}{7}-\frac{3}{2}+\frac{2}{5}\right)\) c)\(\left(-\frac{1}{2}\right)^2:\frac{1}{4}-2.\left(\frac{-1}{2}\right)^3\) e)\(\frac{2^9.4^{10}}{8^8}\)
b\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}.\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\) d)\(\sqrt{16}.1\frac{3}{4}+\frac{1}{4}-7\) f)\(\frac{3}{4}.26\frac{1}{5}-\frac{3}{4}.44\frac{1}{5}\)
\(\left(\frac{3}{7}-\frac{5}{2}-\frac{3}{5}\right)-\left(-\frac{4}{7}-\frac{3}{2}+\frac{2}{5}\right)=\frac{3}{7}-\frac{5}{2}-\frac{3}{5}+\frac{4}{7}+\frac{3}{2}-\frac{2}{5}\)
\(=\left(\frac{3}{7}+\frac{4}{7}\right)+\left(-\frac{5}{2}+\frac{3}{2}\right)+\left(-\frac{3}{5}-\frac{2}{5}\right)\)
\(=1+\left(-1\right)+\left(-1\right)\)
\(=-1\)
Hok tốt nha^^
\(3\frac{2}{5}+4\frac{3}{7}-\frac{1}{4}+\frac{44}{77}-2\frac{2}{5}-0,75\)
3 / 2 / 5 + 4 / 3 / 7 - 1 / 4 + 44 / 77 - 2 / 2 / 5 - 0,75
= 17 / 5 + 31 / 7 - 1 / 4 + 4 / 7 - 12 / 5 - 3 / 4
= ( 17 / 5 - 12 / 5 ) + ( 31 / 7 - 4 / 7 ) + ( 1 / 4 + 3 / 4 )
= 1 + 9 + 1
= 11
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Bài làm
=17/5 + 31/7 - 1/4 +4/7 - 12/5 - 3/10
=( 17/5+12/5)-(31/7+4/7)-3/10
=29/5-5/1-3/10
=29/5-3/10-5/1
=61/10
Mình ko chác đâu nhé!
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Xem thêm câu trả lời
\(\frac{x-2}{27}\)+\(\frac{x-3}{26}\)+\(\frac{x-4}{25}\)+\(\frac{x-44}{5}\)=1
\(\frac{x-2}{27}\)+\(\frac{x-3}{26}\)+\(\frac{x-4}{25}\)+\(\frac{x-44}{5}\)=1
<=> \(\frac{x-2}{27}-1\)+\(\frac{x-3}{26}-1\)+\(\frac{x-4}{25}-1\)+\(\frac{x-44}{5}+3\)=1
<=> \(\frac{x-29}{27}\)+\(\frac{x-29}{26}\)+\(\frac{x-29}{25}\)+\(\frac{x-29}{5}\)=1
<=> ( x- 29 ) \(\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{5}\right)\)=1
phần sau tự làm tp nhé!
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Tìm số nguyên x sao cho :
\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)
Giúp mình nhé
pt \(\Leftrightarrow\left(\frac{x-2}{27}-1\right)+\left(\frac{x-3}{26}-1\right)+\left(\frac{x-4}{25}-1\right)+\left(\frac{x-5}{24}-1\right)+\left(\frac{x-44}{5}+3\right)=0\)
\(\Leftrightarrow\frac{x-29}{27}+\frac{x-29}{26}+\frac{x-29}{25}+\frac{x-29}{24}+\frac{x-29}{5}=0\)
\(\Leftrightarrow\left(x-29\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\right)=0\)
Mà \(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\ne0\)
\(\Rightarrow x-29=0\Leftrightarrow x=29\)
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