\(a)\frac{9}{4}\times y=\left[\frac{5}{7}-\frac{3}{14}\right]\times\frac{4}{7}\)

\(\Rightarrow\frac{9}{4}\times y=\left[\frac{10}{14}-\frac{3}{14}\right]\times\frac{4}{7}\)

\(\Rightarrow\frac{9}{4}\times y=\frac{1}{2}\times\frac{4}{7}\)

\(\Rightarrow\frac{9}{4}\times y=\frac{2}{7}\)

\(\Rightarrow y=\frac{2}{7}:\frac{9}{4}=\frac{8}{63}\)

b, Tương tự câu a

a. x=4/9

b. x=0,4

\(a,\frac{9}{14}\cdot y=\left[\frac{5}{7}-\frac{3}{14}\right]\cdot\frac{4}{7}\)

\(\Rightarrow\frac{9}{14}\cdot y=\left[\frac{10}{14}-\frac{3}{14}\right]\cdot\frac{4}{7}\)

\(\Rightarrow\frac{9}{14}\cdot y=\frac{1}{2}\cdot\frac{4}{7}\)

\(\Rightarrow\frac{9}{14}\cdot y=\frac{2}{7}\)

\(\Rightarrow y=\frac{2}{7}:\frac{9}{14}=\frac{2}{7}\cdot\frac{14}{9}=\frac{2}{1}\cdot\frac{2}{9}=\frac{4}{9}\)

\(\Leftrightarrow y=\frac{4}{9}\)

b, tương tự

a, Ta có : \(14⋮2x-3\)

\(\Rightarrow2x-3\inƯ\left(14\right)=\left\{\pm1;\pm2;\pm7;\pm14\right\}\)

Vì \(2x-3\)là số lẻ

\(\Rightarrow2x-3\in\left\{\pm1;\pm7\right\}\)

...   (tự làm)

\(b,\left(x-3\right)\left(y+2\right)=-7\)

\(x+3\)và \(y+2\)là số nguyên

\(\Rightarrow x+3,y+2\inƯ\left(-7\right)=\left\{\pm1;\pm7;\right\}\)

...  

\(c,x\left(y-1\right)=9\)

\(x\)và \(y-1\)là số lẻ

\(\Rightarrow x,y-1\inƯ\left(9\right)=\left\{\pm1;\pm3;\pm9\right\}\)

...

bó tay luôn