5.(1/5+1/17)-(2/5+2/17+9/15+12/68)

=5.22/85-22/17

=22/17-22/17

=0

Ta có : \(5\cdot\left(\frac{1}{5}+\frac{1}{17}\right)-\left(\frac{2}{5}+\frac{2}{17}+\frac{9}{15}+\frac{12}{68}\right)\)

\(=\) \(5\cdot\frac{1}{5}+5\cdot\frac{1}{17}-\left(\frac{2}{5}+\frac{2}{17}+\frac{3}{5}+\frac{3}{17}\right)\)

\(=\) \(1+\frac{5}{17}-\left[\left(\frac{2}{5}+\frac{3}{5}\right)+\left(\frac{2}{17}+\frac{3}{17}\right)\right]\)

\(=\) \(1+\frac{5}{17}-\left(1+\frac{5}{17}\right)\)

\(=\) \(1+\frac{5}{17}-1-\frac{5}{17}\)

\(=\)\(0\)

     Vậy ... 

                  Tk ủng hộ mk nha các bn ❣❣ C.ơn nhiều ^^

\(\frac{-5}{7}x\left(\frac{2}{11}+\frac{9}{14}\right)+\frac{13}{7}=\frac{-5}{7}x\frac{127}{154}+\frac{13}{7}=\frac{-635}{1078}+\frac{13}{7}=\frac{1367}{1078}\)

Mình không chắc đâu

My name is Overwatch

131 . x - 942 = 2^7 . 2^3 

131 . x - 942 = 2^10

131 . x - 942 = 1024

131 . x = 1024 + 942 

131 . x = 1966

x = 1966 : 131 

x \(\approx15\)

b ) [ ( x + 32 ) - 17 ] . 2 = 42 

     [ ( x + 32 ) - 17 ] = 42 : 2

     ( x + 32 ) - 17  = 21

     x + 32 = 21 + 17

     x + 32 = 38

     x = 38 - 32

    x = 6

A. 131.x-942=2^7.2^3

    131.x-942=1024

    131.x       =1966

       x           =1966/131

B. [(x+32)-17].2=42

     (x+32-17) .2 =42

     (x+15).2       =42

      x+15           = 21

     x                 =6

\(a,\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{2017\cdot2018}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2017}-\frac{1}{2018}\)

\(=1-\frac{1}{2018}\)

\(=\frac{2017}{2018}.\)

\(b,\left[x\cdot\frac{5}{3}-1\right]:9=3\frac{1}{2}:2,25\)

\(\Leftrightarrow\left[x\cdot\frac{5}{3}-1\right]:9=\frac{7}{2}:\frac{9}{4}\)

\(\Leftrightarrow\left[x\cdot\frac{5}{3}-1\right]:9=\frac{7}{2}\cdot\frac{4}{9}\)

\(\Leftrightarrow\left[x\cdot\frac{5}{3}-1\right]:9=\frac{14}{9}\)

\(\Leftrightarrow x\cdot\frac{5}{3}-1=\frac{14}{9}\cdot9\)

\(\Leftrightarrow x\cdot\frac{5}{3}-1=14\)

\(\Leftrightarrow x\cdot\frac{5}{3}=14+1\)

\(\Leftrightarrow x\cdot\frac{5}{3}=15\)

\(\Leftrightarrow x=15:\frac{5}{3}\)

\(\Leftrightarrow x=15\cdot\frac{3}{5}\)

\(\Leftrightarrow x=9.\)

a)\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2017.2018}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2017}-\frac{1}{2018}\)

\(=\frac{1}{1}-\frac{1}{2018}\)

\(=\frac{2017}{2018}\)

b)\(\left[x.\frac{5}{3}-1\right]:9=3\frac{1}{2}:2,25\)

\(\Leftrightarrow\left[x.\frac{5}{3}-1\right]:9=3\frac{1}{2}:\frac{9}{4}=1\frac{5}{9}\)

\(\Rightarrow x.\frac{5}{3}-1=1\frac{5}{9}.9=14\)

\(\Rightarrow x.\frac{5}{3}=14+1=15\)

\(\Rightarrow x=15:\frac{5}{3}=9\)

a) \(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{2017\cdot2018}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2017}-\frac{1}{2018}\)

\(=\frac{1}{1}-\frac{1}{2018}\)

\(=\frac{2018}{2018}-\frac{1}{2018}\)

\(=\frac{2017}{2018}\)

b) \(\left(x\cdot\frac{5}{3}-1\right):9=3\frac{1}{2}:2,25\)

\(\left(x\cdot\frac{5}{3}-1\right):9=\frac{7}{2}:\frac{9}{4}\)

\(\left(x\cdot\frac{5}{3}-1\right):9=\frac{14}{9}\)

\(x\cdot\frac{5}{3}-1=\frac{14}{9}\cdot9\)

\(x\cdot\frac{5}{3}-1=14\)

\(x\cdot\frac{5}{3}=14+1\)

\(x\cdot\frac{5}{3}=15\)

\(x=15:\frac{5}{3}\)

\(x=9\)

Vậy \(x=9\)

\(3-x\times\frac{1}{2}=\frac{3}{4}\)

\(x\times\frac{1}{2}=3-\frac{3}{4}\)

\(x\times\frac{1}{2}=\frac{12}{4}-\frac{3}{4}\)

\(x\times\frac{1}{2}=\frac{9}{4}\)

\(x=\frac{9}{4}\div\frac{1}{2}\)

\(x=\frac{9}{4}\times\frac{2}{1}\)

\(x=\frac{18}{4}=\frac{9}{2}\)

Vậy x = 9/2

ik r mk làm tiếp cho

ta có x.1=21(vì 2017:2017=1 nên triệt  tiêu)

        x    =21:1=21

\(\frac{2017}{2017\cdot\left(x\cdot1\right)}=21\)

\(\Leftrightarrow\frac{1}{x}=21\)

\(\Leftrightarrow x=\frac{1}{21}\)

\(\frac{2017}{2017.\left(x.1\right)}=21\)

\(\frac{1}{x}=21\)

\(x=\frac{1}{21}\)

Giúp mình với các bạn ơi!!!!!!!!!!!!!!!!!!!!!!!!!!!!