cho a^3+b^3=c(3ab-c^2) và a+b+c=3 tính giá trị của: K=675(a^2016+b^2016+c^2016)+1
Những câu hỏi liên quan
Cho a3 + b3 = c*(3ab-c2) và a + b + c = 0
Tính giá trị biểu thức A = 675 * ( a2016 + b2016 + c2016 ) + 1
Cho a3 + b3 = c*(3ab-c2) và a + b + c = 0
Tính giá trị biểu thức A = 675 * ( a2016 + b2016 + c2016 ) + 1
Cho a + b + c = 1; a2 + b2 + c2 = 1; a3 + b3 + c3 = 1. Tính giá trị của biểu thức:
D = a2016 + b2016 + c2016
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Ta có
(m+n+p)^q >= m^q+n^q+p^q
=>a+b+c=1
=>(a+b+c)^2016=1 >= a2016 + b2016 + c2016
Mà a2016 + b2016 + c2016 >=0
=> a2016 + b2016 + c2016=1
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Cho a,b,c là 3 số thỏa mãn a+b+c = 1 ; a^3 + b^3 + c^3 =1
Tìm giá trị biểu thức M = a^2016 + b^2016 + c^2016
Đố bạn nào làm hết đc các câu này mik cho 5 tick hoặc 1 câu 1 tick cố lên nha :)) HELP MECâu 1: Cho x^2+xy+y^25Tính giá trị biểu thức: Ax^4+y^4left(x+yright)^4Câu 2: Cho a+b+c+d0.CMR:a^3+b^3+c^3+d^33left(ab-cdright)left(c+dright)Câu 3:Cho x+ya;x^2+y^2b;x^3+y^3cCM: a^3-3ab+2c0Câu 4: Cho a,b,c0 thỏa mãn a^{2016}+b^{2016}+c^{2016}a^{1008}b^{1008}+b^{1008}c^{1008}+c^{1008}a^{1008}Tính giá trị biểu thức Aleft(a-bright)^{15}+left(b-cright)^{2015}+left(a-cright)^{2016}
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Đố bạn nào làm hết đc các câu này mik cho 5 tick hoặc 1 câu 1 tick cố lên nha :)) HELP ME
Câu 1: Cho \(x^2+xy+y^2=5\)
Tính giá trị biểu thức: A=\(x^4+y^4\left(x+y\right)^4\)
Câu 2: Cho a+b+c+d=0.CMR:
\(a^3+b^3+c^3+d^3=3\left(ab-cd\right)\left(c+d\right)\)
Câu 3:Cho \(x+y=a;x^2+y^2=b;x^3+y^3=c\)
CM: \(a^3-3ab+2c=0\)
Câu 4: Cho a,b,c>0 thỏa mãn \(a^{2016}+b^{2016}+c^{2016}=a^{1008}b^{1008}+b^{1008}c^{1008}+c^{1008}a^{1008}\)
Tính giá trị biểu thức A=\(\left(a-b\right)^{15}+\left(b-c\right)^{2015}+\left(a-c\right)^{2016}\)
2. Đặt c + d = x
Ta có: \(a+b+c+d=0\Rightarrow a+b+x=0\Rightarrow a^3+b^3+c^3+d^3=3abx\)
\(\Rightarrow a^3+b^3+c^3+d^3+3cd\left(c+d\right)=3ab\left(c+d\right)\)
\(\Rightarrow a^3+b^3+c^3+d^3=3ab\left(c+d\right)-3cd\left(c+d\right)=3\left(ab-cd\right)\left(c+d\right)\)
Câu 4:
\(a^{2016}+b^{2016}+c^{2016}=a^{1008}b^{1008}+b^{1008}c^{1008}+c^{1008}+a^{1008}\)
\(\Rightarrow2a^{2016}+2b^{2016}+2c^{2016}-2a^{1008}b^{1008}-2b^{1008}c^{1008}-2c^{1008}a^{1008}=0\)
\(\Rightarrow\left(a^{1008}-b^{1008}\right)^2+\left(b^{1008}-c^{1008}\right)^2+\left(c^{1008}-a^{1008}\right)^2=0\)
\(\Rightarrow a^{1008}=b^{1008},b^{1008}=c^{1008},c^{1008}=a^{1008}\)
\(\Rightarrow a=b,b=c,c=a\) (vì a,b,c > 0 nên \(a\ne-b,b\ne-c,c\ne-a\) )
\(\Rightarrow a-b=0,b-c=0,a-c=0\)
Thay vào A ta tính được A = 0
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Bài 1: Cho a,b,c thỏa mãn (a+b-c)/c(b+c-a)/a(c+a-b)/b tính P(1+b/a)*(1+c/b)*(1+a/c)Bài 2: Cho a+b+c0 tính B((a^2+b^2-c^2)*(b^2+c^2-a^2)*(c^2+a^2-b^2))/(10*a^2*b^2*c^2)Bài 3: cho a^3*b^3+b^3*c^3+c^3*a^33*a^3*b^3*c^3tính M(1+a/b)*(1+b/c)*(1+c/a)Bài 4: cho 3 số a,b,c TM a*b*c2016tính P2016*a/(a*b+2016*a+2016) + b/(b*c+b+2016) + c/(a*c+c+1)Bài 5: cho a+b+c0tính Q1/(a^2+b^2-c^2) + 1/(b^2+c^2-a^2) + 1/(a^2+c^2-b^2)
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Bài 1: Cho a,b,c thỏa mãn (a+b-c)/c=(b+c-a)/a=(c+a-b)/b
tính P=(1+b/a)*(1+c/b)*(1+a/c)
Bài 2: Cho a+b+c=0
tính B=((a^2+b^2-c^2)*(b^2+c^2-a^2)*(c^2+a^2-b^2))/(10*a^2*b^2*c^2)
Bài 3: cho a^3*b^3+b^3*c^3+c^3*a^3=3*a^3*b^3*c^3
tính M(1+a/b)*(1+b/c)*(1+c/a)
Bài 4: cho 3 số a,b,c TM a*b*c=2016
tính P=2016*a/(a*b+2016*a+2016) + b/(b*c+b+2016) + c/(a*c+c+1)
Bài 5: cho a+b+c=0
tính Q=1/(a^2+b^2-c^2) + 1/(b^2+c^2-a^2) + 1/(a^2+c^2-b^2)
Cho a;b;c thỏa mãn: a + b+ c = 2016 và A^2 + b^2 + c^2 = 3abc. tính giá trị của biểu thức P = ( a - 671)^2 + ( b-672)^4 + (c - 673)^2016
Cho a+b+c=0 và ab+ac+bc=0
Tính giá trị của biểu thức:
M=(a-2016)2016+(b-2016)2016-(c+2016)2016
Cho a+b+c=0 và ab+ac+bc=0
Tính giá trị của biểu thức:
M=(a-2016)2016+(b-2016)2016-(c+2016)2016
a+b+c=0 => a^2+b^2+c^2+2ab+2bc+2ca = 0 => a^2+b^2+c^2=0
=> a^2+b^2+c^2 = ab+bc+ca
=> 2a^2+2b^2+2c^2 = 2ab+2bc+2ca
=> (a-b)^2 + (b-c)^2 + (c-a)^2 = 0
=> a=b=c, mà a+b+c=0 => a=b=c=0
thay vào
M=(0-2016)2016+(0-2016)2016-(0-2016)2016=(-2016)2016=20162016
Chúc bạn hoc tốt ùng hộ nha
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