* ĐK: \(x\ne0\)

Đề ra ...<=> \(\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+...+\frac{1}{x\left(x+1\right)}=\frac{2}{9}\)

<=> \(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{2}{x\left(x+1\right)}=\frac{1}{9}\)

<=> \(\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{x\left(x+1\right)}+\frac{1}{x\left(x+1\right)}=\frac{1}{9}\)

<=>\(\frac{1}{6}-\frac{1}{x+1}+\frac{1}{x\left(x+1\right)}=\frac{1}{9}\)

<=>\(\frac{1}{x+1}\left(1-\frac{1}{x}\right)=\frac{1}{6}-\frac{1}{9}\)

<=> \(\frac{x-1}{x\left(x+1\right)}=\frac{1}{36}\)

<=> \(\frac{x-1}{x\left(x-1\right)}=\frac{x-1}{36.\left(x-1\right)}\)

=> x(x-1) = 36. (x-1) => x =36

\(\frac{2}{2}.\left(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x+\left(x+1\right)}\right)=\frac{2}{9}\)

\(2\left(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{x.\left(x+1\right)}\right)=\frac{2}{9}\)

\(\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{x.\left(x+1\right)}=\frac{1}{9}\)

\(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{1}{9}\)

\(\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)

\(\frac{1}{x+1}=\frac{1}{6}-\frac{1}{9}\)

\(\frac{1}{x+1}=\frac{1}{18}\)

x+1=18

x=18-1

x=17

$4n+5):3-121:11=4$

$\iff (4n+5):3-11=4$

$\iff (4$n$+5):3=4+11$

$\iff (4$n$+5):3=15$

$\iff (4$n$+5)=15.3$

$\iff 4$n$+5=45$

$\iff 4$n$=45-5$

$\iff 4$n$=40$

$\iff$n$=40:4$

$\iff$n$=$

Bạn ơi, 1 x 21 chứ có phải  121 đâu

\(\left(4n+5\right):3-1.21:11=4\)

\(\Rightarrow\left(4n+5\right):3-1.21=44\)

\(\Rightarrow\left(4n+5\right):3-21=44\)

\(\Rightarrow\left(4n+5\right):3=65\)

\(\Rightarrow4n+5=195\)

\(\Rightarrow4n=190\)

\(\Rightarrow n=47,5\)

Câu 1.

ta có: 63/72 =7/8

=>x +3 =7

=>x=...

Câu 2.

=>x +4<11

=>x=0;1;2;3;4;5;6

=>x +4>9

=>x=6;7;8;9;...

=> x=6

Câu 3 như câu 2

Ta có : 6² = 36 = 2² x 3²

Số ước của 3ⁿ x 2² x 3² = (n + 1) x (2 + 1) x (2 + 1) = 21

                                     => (n+1) x 3 x 3 = 21

=> (n + 1) x 9 = 21

=> n + 1 = \(\frac{7}{3}\)

=> n = \(\frac{4}{3}\)

1/21 + 1/28 + 1/36 + ...+ 1/x(x+1)

=> 2/42 + 2/56 + 2/72 +....+ 2/x(x+1)

=> 2.(1/42 + 1/56 + 1/72 + ... + 1/x.(x+1))

=> 2 .(1/6.7 + 1/7.8 + 1/8.9 + ..+ 1/x.(x+1))

=> 2. ( 1/6 - 1/7 + 1/7-1/8 + ...+ 1/x - 1/x+1

=> 2 . (1/6 - 1/x+1)

=>1/3 - 2/x+1

  x = 5    y = 36

  ( 18 / 21 + 3 / 21 ) + ( 19 / 32 + 13 / 32 ) + ( 75 / 100 + 1 / 4 )

= 1 + 1 + 1 = 3

2008/2009 >  2010/2011 ; 1999/2001 < 12/11 ;2007/2006>  2006/2007 ; 101/100 >100/101

1. 

    x = 5

    y = 36

2.

  ( 18 / 21 + 3 / 21 ) + ( 19 / 32 + 13 / 32 ) + ( 75 / 100 + 1 / 4 ) = 1 + 1 + 1 = 3

3.

   >     ;    <       ;    >        ;        >

  x = 5    y = 36

  ( 18 / 21 + 3 / 21 ) + ( 19 / 32 + 13 / 32 ) + ( 75 / 100 + 1 / 4 )

= 1 + 1 + 1 = 3

2008/2009 >  2010/2011 ; 1999/2001 < 12/11 ;2007/2006>  2006/2007 ; 101/100 >100/101

a) 2115 : x = 21

=> x = 2115 : 21 = \(\frac{705}{7}\) ( sai đề )
b) \(\left(9\times x-21\right):3=2\)

=> \(\left(9\times x-21\right)=2\times3=6\)

=> \(9\times x=6+21=27\)

=> \(x=27:9=3\)

Vậy x = 3

c) 231 + ( 312 - x ) = 531

=> 231 + 312 - x = 531

=>. 543 - x = 531

=> x = 543 - 531 = 12

Vậy x = 12

a) 2115 : x = 21

x= 705/7

b) ( 9 * x - 21) : 3 = 2

9 * x  - 21 = 6

9 * x = 27

x = 3

c) 231 + ( 312 - x) = 531

231 + 312 - x = 531

543 - x = 531

x =12

a. 2115 : x = 21

               x = 2115 : 21

               x = 705/7

b. ( 9 . x - 21 ) : 3 = 2

      9x : 21 = 6

      9x = 27

        x = 3

c. 231 + ( 312 - x ) = 531

                312 - x = 300

                         x= 12