A = 2002/ 15.2000 + 2000 -1970 = 2002/ 15. 2000+ 30= 2002/15.(2+2000)=2002/2002.15=1/15

A= 780 phần 2085

B= 139 phần 2085

\(\frac{5^2.3^{11}.2^{11}.2^8+2^2.3^2.3^2.5^2}{2.2^{12}.3^{12}.2^4.5^4-3^8.2^{18}.3^3.5^3}\)

\(=\frac{5^2.3^{11}.2^{19}+2^2.3^4.5^2}{2^{17}.3^{12}.5^4-3^{11}.2^{18}.5^3}\)

\(=\frac{5^2.3^4.2^2.\left(3^7.2^{17}+1\right)}{2^{17}.3^{11}.5^3.\left(3.5-2\right)}=\frac{3^7.2^{17}}{2^{15}.3^7.5}+\frac{1}{2^{15}.3^7.5}=\frac{4}{5}+\frac{1}{2^{15}.3^7.5}\)

A = 2002 2000.16 − 1970 = 2002 ( 2002 − 2 ) .16 − 1970 = 2002 2002. ( 16 − 1 ) = 1 15

và  B = 12.3 + 2.4.6 + 4.8.12 + 7.14.21 1.3.6 + 2.6.12 + 4.12.24 + 7.21.42 = 12.3 + 2.4.6 + 4.8.12 + 7.14.21 1.3.2.3 + 2.6.3.4 + 4.12.3.8 + 7.21.14.3 = 12.3 + 2.4.6 + 4.8.12 + 7.14.21 3. ( 12.3 + 2.4.6 + 4.8.12 + 7.14.21 ) = 1 3 = 5 15

Vậy B > A

câu hỏi hay......nhưng tui xin nhường cho các bn khác

Hãy tích đúng cho tui nha

THANKS

\(B=\frac{16\cdot64\cdot8^2}{4^3\cdot2^5\cdot16}=\frac{16\cdot64\cdot64}{64\cdot32\cdot16}=\frac{64}{32}=2\)

\(B=\frac{16.64.8^2}{4^3.2^5.16}\)

\(=\frac{2^6.\left(2^3\right)^2}{\left(2^2\right)^3.2^5}\)

\(=\frac{2^6.2^6}{2^6.2^5}\)

\(=2\)

2.27²/6⁴.8⁴

=2.(3³)²/(6.8)⁴

=2.3⁶/48⁴

=2.3⁶/(3.2⁴)⁴

=2.3⁶/3⁴.2¹⁶

=3²/2¹⁵

24³.25²/15³.16²

=(3.2³)³.(5²)²/(3.5)³.(2⁴)²

=3³.2⁹.5⁴/3³.5³.2⁸

=5.2

=10

\(\frac{2.27^2}{6^4.8^4}=\frac{9}{32768}\)

\(\frac{24^3.25^2}{15^3.16^2}=10\)

TK MÌNH NHA !!!  ^-^

tử số : 2.4 + 4.8 + 8.12 + 12.16 + 16.20 

= 2.(1.2+2.4+4.6+6.8+8.10) 

ta được 2. A=( 1.2+2.4+4.6+6.8+8.10) / ( 1.2+2.4+4.6+6.8+8.10) 

=> A=2 

A=4 nha bạn

TA ĐƯỢC A=4

K CHO MÌNH VỚI NHA