\(A=\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x......x\left(1-\frac{1}{2013}\right)x\left(1-\frac{1}{2014}\right)\)

\(A=\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x...............x\frac{2012}{2013}x\frac{2013}{2014}\)

\(A=\frac{1}{2014}\)

\(\left[1-\frac{1}{2}\right]\left[1-\frac{1}{3}\right]...\left[1-\frac{1}{2014}\right]\)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}...\cdot\frac{2013}{2014}\)

\(=\frac{1\cdot2\cdot3\cdot...\cdot2013}{2\cdot3\cdot4\cdot5\cdot...\cdot2014}=\frac{1}{2014}\)

Mình ko viết lại đề nữa nha

A= 1/2 x 2/3 x 3/4 x ...........x 2012/2013 x 2013/2014    (loại bỏ những số giống nhau)

A= 1/2014

A=1/2*2/3*3/4*...*2012/2013*2013/2014

Ta gạch bỏ các chữ số giống nhau còn lại 1/2014

Vậy A= 1/2014

1/1 x2 + 1/ 2 x 3 + 1/ 3 x 4 + ................. + 1/ 2013 x 2014

= 1/1 – 1/2 + 1/2 – 1/3 + 1/3 – 1/4 + ........................ + 1/2013 – 1/2014

= 1 – 1/2014 = 2013/2014

A= 1/2 x 2/3 x 3/4 x ... x 2013/2014 x 2014/2015

A=1/2015

\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2014}{2015}\)

Khử hết các số giống nhau trên tử và mẫu, ta còn: \(\frac{1}{2015}\)

\(A=\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}+.....+\frac{1}{\left(x+2013\right)\left(x+1014\right)}\)

\(\Leftrightarrow A=\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}+....+\frac{1}{x+2013}-\frac{1}{x+2014}\)

\(\Leftrightarrow A=\frac{1}{x}-\frac{1}{x+2014}\)

\(\Leftrightarrow A=\frac{x+2014-x}{x\left(x+2014\right)}=\frac{2014}{x\left(x+2014\right)}\)