Tính
D= (-2)^10.3^31+2^40.(-3)^6/(-2)^11 .(-3)^31+2^41.3^6
tính nhanh : D=(2^10.3^31.2^40.3^6)/(2^11.3^31+2^41.3^6)
BẠN NÀO LÀM NHANH GIÙM MIK VÀ CHÍNH XÁC NHẤT MIK HỨA SẼ TICK ĐÚNG CHO BẠN 10 TICK TRONG TUẦN NÀY MIK HỨA !
B1: tính nhanh
a) 4. (-1/2)^3+1/2 ( viết cho các bạn dễ nhìn -> ) \(4\left(-\frac{1}{2}\right)^3+\frac{1}{2}\)
b)2^10.3^31+2^40.3^6/2^11.3^31+2^41.3^6 ( viết cho dễ nhìn ->) \(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}\)
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}\)
Tính
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}=\frac{2}{2+2}=\frac{2}{4}=\frac{1}{2}\)
2^10 .3^6 .3^25 + 2^10 .2^30 .3^6
2 ^11 .3^6 . 3^25 + 2^ 11 . 2^ 30 .3 ^6
2^ 10 . 3^ 6 .(2^ 30 + 3^ 25 )
2^11.3 ^ 6. ( 3^ 25 +2^ 30 )
2 ^ 10. 3^ 6
2^ 11 . 3^6
1
2
Tính:
f)
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}\)
Bài làm
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{11}+2^{41}.3^6}\)
\(=\frac{2^{10}.\left(3^{11}+2^{30}.3^6\right)}{2^{11}.\left(3^{11}+2^{30}.3^6\right)}\)
\(=\frac{1}{2}\)
~ K chắc ~
# Học tốt #
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}=\frac{2^{10}.3^6\left(3^{25}+2^{30}\right)}{2^{11}.3^6\left(3^{25}+2^{30}\right)}=\frac{1}{2}\)
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{11}.3^6}\)
Tính: 210.331 + 240.36 / 211.331 + 241.36 . Giúp mình nhé, tks !
\(=\frac{2^{10}\left(3^{31}+2^{30}.3^6\right)}{2^{11}\left(3^{31}+2^{30}.3^6\right)}=\frac{1}{2}\)
\(\frac{2^{10}.2^{31}+2^{40}.3^6}{2^{11}.2^{31}+2^{41}.3^6}\)
\(\frac{2^{10}.2^{31}+2^{40}.3^6}{2^{11}.2^{31}+2^{41}.3^6}\)
\(=\frac{2^{41}+2^{40}.3^6}{2^{42}+2^{41}.3^6}\)
\(=\frac{2^{40}\left(2+3^6\right)}{2^{41}\left(2+3^6\right)}\)
\(=\frac{1}{2}\)
thực hiện phép tính :
\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{99.101}\)
\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}\)
Đặt \(A=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+...+\frac{1}{99\cdot101}\)
\(2A=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-...+\frac{1}{99}-\frac{1}{101}\)
\(2A=\frac{100}{101}\)
\(A=\frac{50}{101}\)
b) \(\frac{2^{10}+3^{31}+2^{40}+3^6}{2^{11}\cdot3^{31}+2^{41}\cdot3^6}=\frac{2^{10}+2^{40}}{2^{11}+2^{41}}\)
\(\frac{2^{10}+2^{40}}{2^{11}+2^{41}}=\frac{1}{2}\)
=1/2x(1/1.3+1/3.5+...+1/99.101)
=1/2.(1-1/3+1/3-1/5+1/5-1/7+...+1/99-1/101)
=1/2.(1-1/101)
=1/2.100/101
=50/101
chúc bạn học tốt
Tính:
a/\(\frac{3^{17}\cdot81^{11}}{27^{10}\cdot9^{15}}\)
b/\(\frac{9^2\cdot2^{11}}{16^2\cdot6^3}\)
c/\(\frac{2^{10}\cdot3^{31}+2^{40}\cdot3^6}{2^{11}\cdot3^{31}+2^{41}\cdot3^6}\)
\(\frac{3^{17}\cdot81^{11}}{27^{10}\cdot9^{15}}\)
\(=\frac{3^{17}\cdot\left(3^4\right)^{11}}{\left(3^3\right)^{10}\cdot\left(3^2\right)^{15}}\)
\(=\frac{3^{17}\cdot3^{44}}{3^{30}\cdot3^{30}}\)
\(=\frac{3^{61}}{3^{60}}\)
\(=3\)
\(\frac{9^2\cdot2^{11}}{16^2\cdot6^3}\)
\(=\frac{\left(3^2\right)^2\cdot2^{11}}{\left(2^4\right)^2\cdot\left(2\cdot3\right)^3}\)
\(=\frac{3^4\cdot2^{11}}{2^8\cdot2^3\cdot3^3}\)
\(=\frac{3^4\cdot2^{11}}{2^{11}\cdot3^3}\)
\(=\frac{3^4}{3^3}\)
\(=3\)
\(\frac{2^{10}\cdot3^{31}+2^{40}\cdot3^6}{2^{11}\cdot3^{31}+2^{41}\cdot3^6}\)
\(=\frac{2^{10}\cdot3^{31}+2^{40}\cdot3^6}{2\cdot\left(2^{10}\cdot3^{31}+2^{40}\cdot3^6\right)}\)
\(=\frac{1}{2}\)