a \(\frac{7}{6}\)

b \(\frac{5}{3}\)

\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)

\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)

\(=1+\frac{1}{6}\)

\(=\frac{7}{6}\)

Hok tốt!~

\(\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)

\(=\frac{2}{5}+\frac{3}{5}+\frac{1}{6}\)

\(=\frac{5}{5}+\frac{1}{6}\)

\(=1+\frac{1}{6}\)

\(=1\frac{1}{6}=\frac{7}{6}\)

 \(=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+...+\frac{1}{10}\)có 9 p/số

\(=\frac{1}{10}.9=\frac{9}{10}\)

= 1/10 + 1/10 + ...................... + 1/10 có 9 phân số

= 1/10 x 9

= 9/10

ai tk mình mình đang bị âm điểm

9 / 12 bn nha

tk mk nha các bn

thanks nhiêu

2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222225444444455555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555

a \(\frac{4}{18}+\frac{5}{13}+\frac{7}{9}+\frac{21}{13}\)

= \(\left(\frac{4}{18}+\frac{7}{9}\right)+\left(\frac{5}{13}+\frac{21}{13}\right)\)

= \(1+2\)

= \(3\)

b \(\frac{4}{3}-\frac{2}{7}-\frac{5}{7}+\frac{2}{3}\)

= \(\left(\frac{4}{3}-\frac{2}{3}\right)-\left(\frac{2}{7}+\frac{5}{7}\right)\)

= \(\frac{2}{3}-1\)

= \(-\frac{1}{3}\)

Kết quả của bài 1/5+1/10+1/20+1/40+1/80+1/160 là gì

=\(\frac{3}{4}\times\left(\frac{8}{9}+\frac{2}{3}\right)\)

\(=\frac{3}{4}\times\frac{14}{9}\)

\(=\frac{7}{6}\)

a)\(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{1}{3}\right)+3\)

\(=1+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3\)

\(=1+3+\frac{7}{9}\)

\(=4\frac{7}{9}\)

\(=\frac{43}{9}\)

b)\(\frac{8}{5}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{2}{5}-1\)

\(=\frac{4}{7}\cdot\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}\cdot2-1\)

\(=\frac{8}{7}-1\)

\(=\frac{1}{7}\)

a) \(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3=4\frac{7}{9}\)

b)\(\frac{8}{5}.\frac{4}{7}+\frac{4}{7}.\frac{2}{5}-1\)

\(=\frac{4}{7}.\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}.2-1\)

\(=\frac{8}{7}-\frac{7}{7}=\frac{1}{7}\)

a) 8/13+5/13+4/9+1/3+3=1+4/9+1/3+3=1+7/9+3=43/9

b)2x4/7-1=8/7-1=1/7

= \(x^8.\frac{1}{10}.\frac{2}{9}.\frac{3}{8}.\frac{4}{7}.\frac{5}{6}.\frac{6}{5}.\frac{7}{4}.\frac{8}{3}.\frac{9}{2}\)

= \(x^8.\frac{1}{10}.\left(\frac{2}{9}.\frac{9}{2}\right).\left(\frac{3}{8}.\frac{8}{3}\right).\left(\frac{4}{7}.\frac{7}{4}\right).\left(\frac{5}{6}.\frac{6}{5}\right)\)

= \(x^8.\frac{1}{10}.1.1.1.1\)

= \(x^8.\frac{1}{10}\)

Mk ko pik co dung ko nua

=4/10

\(\frac{x^8}{10}\)