ghi gt kl cua cac dinh li sau , ve hinh
a, neu 2 dg thang phan biet // dg thang thu 3 thi chung // voi nhau
b, neu 2 tia phan giac cua 2 goc ke bu thi vuong foc voi nhau
can gap ngay bay gio
cho 2 duong thang xy//mn ,duong thang A cat 2 duong thang xy va mn lan luot tai A va B. ke tia phan giac cua foc xAB va phan giac cua goc ABM chung cat nhau tai C. Ke tia phan giac cua BAI va tia phan giac cua ABN chung cat nhau tai D.chung minh: a)AC vuong goc voi AD, BD vuong goc voi BC
CMR : neu 1 dg thang cat 2 dg thang song song thi 2 tia phan giac cua 1 cap goc dong vi song song voi nhau
cho 2 duong thang xy//mn ,duong thang A cat 2 duong thang xy va mn lan luot tai A va B. ke tia phan giac cua foc xAB va phan giac cua goc ABM chung cat nhau tai C. Ke tia phan giac cua BAI va tia phan giac cua ABN chung cat nhau tai D.chung minh: a)AC vuong goc voi AD, BD vuong goc voi BC
Cau 5: Trong cac khang dinh sau, khang dinh nao dung, khang dinh nao sai?
1.Ba diem phan biet la ba diem thang hang.
2.Voi ba diem phan biet luon co hai diem nam ve cung phia doi voi diem con lai.
3.Voi ba diem thang hang phan biet luon co hai diem nam khac phia voi diem con lai.
4.Voi ba diem A,B,C thang hang thi diem B luon nam giua hai diem A,C.
5.Co mot va chi mot duong thang di qua hai diem (phan biet) cho truoc.
6.Hai duong thang phan biet thi song song voi nhau.
7.Hai tia chung goc thi cung nam tren mot duong thang.
8.Hai tia chung goc thi doi nhau
9.Neu diem M nam giua diem A,B thi no la trung diem cua doan thang AB.
10.Neu MA=MB thi M la trung diem cua doan thang AB.
11.Neu MA+MB= AB va MA=MB thi M la trung diem cua doan thang AB.
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Cho 1 duong thang cat 2 duong thang song song,Hay chung minh rang:
a,Cac tia phan giac cua 1 cap goc so le (hoac so le ngoai thi song song voi nhau
b,Cac tia phan giac cua 1 cap goc dong vi thi song song voi nhau.
c,Cac tia phan giac cua 1 cap goc trong cung phia(hoac ngoai cung phia) thi vuong goc voi nhau.
Chung minh: Trong 1 hinh thang, cac tia phan giac cua 2 goc ke 1 canh ben vuong goc voi nhau
chung minh rang hai tia phan giac cua 2 goc ke bu thi vuong goc voi nhau
* Gọi góc xOz, góc zOy là 2 góc kề bù ; và tia Ou, Ov lần lượt là tia phân giác của góc xOz, zOy.
* Để chứng minh 2 tia phân giác của 2 góc kề bù vuông góc với nhau, ta sẽ chứng minh tia Ou vuông góc tia Ov.
* Vì tia Ou, Ov lần lượt là tia phân giác của góc xOz, zOy
nên:
{ góc uOz = 1/2 góc xOz
{ góc zOv = 1/2 góc zOy
Suy ra:
{ 2 góc uOz = góc xOz
{ 2 góc zOv = góc zOy
Ta lại có:
góc xOz + góc zOy = 180 độ (vì 2 góc xOz, góc zOy kề bù)
=> 2 góc uOz + 2 góc zOv = 180 độ
=> 2(góc uOz + góc zOv) = 180 độ
=> góc uOz + góc zOv = 90 độ
=> góc uOv = 90 độ (vì 2 góc uOz, góc zOv kề nhau)
=> Tia Ou vuông góc Tia Ov
Do đó, 2 tia phân giác của 2 góc kề bù thì vuông góc với nhau.
*Gọi góc x Oz ,góc zOy là 2 góc kề bù ;và tiaOu ,Ov lần lượt là tia phân giác của góc x Oz ,zOy .
*Để chứng minh 2 tia phân giác của 2 góc bề bù vuông góc với nhau ,ta sẽ chứng minhtia Ou vuông góc tia Ov
*Vì tia Ou ,Ov lần lượt là tia phân giác của góc xOz ,zOy nên :
(góc u =1/2 góc x xOz.
(góc zOv = 1/2 góc zOy.
Suy ra
(2 góc uOz = góc xOz
(2 góc zOv = góc zOy
Ta lại có :
góc xOz + góc zOy =180 độ (vì 2 góc xOz , góc zOy kề bù)
=> 2goc uOz + 2 góc zOv =180 độ
=>2 (góc uOz + góc xOv ) =180 độ
=>góc uOz + góc zOv = 90 độ
=>góc uOv = 90 độ (vì 2 góc uOz, góc zOv kề nhau)
=>Tia Ou vuông góc tia Ov
Do đó ,2 tia phân giác của 2 góc bù thì vuông góc với nhau.
1. Cho hinh thang ABCD , phan giac cua goc A cat duong cheo BD tai E va phan giac goc B cat AC tai F . Chung minh EF //AB?
2.Cho tam giac ABC , cac tia phan giac cua goc B va goc C cat nhau tai O . Tu A ve duong thang vuong goc voi OA cat BO , CO lan luot tai M va N . Chung minh BM vuong goc voi BN , CM vuong goc voi CN?
3.Cho goc vuong xOy ,vaf tam giac ABC vuong tai A (B thuoc Ox ,AC thuoc Oy,A va O nam tren hai nua mat phang doi nhau co bo la BC ).chung minh OA la tia phan gic cua xOy ?
cac ban giup mik nha
chung to 2 tia phan giac cua 2 goc ke bu thi vuong goc vou nhau
giup minh voi minh dang di thi
* Hình vẽ mang tính chất minh họa *
Ta có O1 = O2
=> O2 = \(\frac{\widehat{mOz}}{2}\)
Ta có O3 = O4
=> O3 = \(\frac{\widehat{nOz}}{2}\)
=> O2 + O3 = \(\frac{\widehat{mOz}+\widehat{nOz}}{2}=\frac{180}{2}=90\left(đpcm\right)\)