a ) 13/20

B)

C..........................................................

minh dang tính

lấy máy tính mà bấm

trả lời kiểu gì vậy hả bạn lê thế trung

\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)

\(\frac{3}{4}:\left(4x-3\right)^2=\frac{25}{12}\)

\(\left(4x-3\right)^2=\frac{9}{25}=\left(\frac{\pm3}{5}\right)^2\)

+) 4x - 3 = 3/5

4x = 18/5

x = 9/10

+) 4x - 3 = -3/5

4x = 12/5

x = 3/5

Vậy,.........

\(\frac{7}{12}-0,75:\left(4x-3\right)^2=-\frac{3}{2}\)

\(\Leftrightarrow\frac{7}{12}.12\left(4x-3\right)^2-\frac{0,75}{\left(4x-3\right)^2}.12\left(4x-3\right)^2=-\frac{3}{2}.12\left(4x-3\right)^2\)

\(\Leftrightarrow7\left(4x-3\right)^2-9=-18\left(4x-3\right)^2\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{10}\\x=\frac{3}{5}\end{cases}}\)

\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)

\(0,75:\left(4x-3\right)^2=\frac{7}{12}-\frac{-3}{2}\)

\(0,75:\left(4x-3\right)=\frac{7+18}{12}\)

\(0,75:\left(4x-3\right)=\frac{25}{12}\)

\(\frac{3}{4}:\left(4x-3\right)=\frac{25}{12}\)

\(4x-3=\frac{3}{4}:\frac{25}{12}\)

\(4x-3=\frac{3.12}{4.25}=\frac{9}{25}\)

\(4x=\frac{9}{25}+3\)

\(4x=\frac{9+75}{25}\)

\(4x=\frac{84}{25}\)

\(x=\frac{84}{25}:4\)

\(x=\frac{84.1}{25.4}\)

\(x=\frac{21}{25}\)

Vậy \(x=\frac{21}{25}\)

(2,5x - 4/3)² - 5/6 = -7/18

=> (2,5x - 4/3)² = -7/18 + 5/6

=> (2,5x - 4/3)² = 4/9

=> (2,5x - 4/3)² = (2/3)²

=> \(\orbr{\begin{cases}2,5x-\frac{4}{3}=\frac{2}{3}\\2,5x-\frac{4}{3}=-\frac{2}{3}\end{cases}}\)

=> \(\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{4}{15}\end{cases}}\)

\(\left(2,5x-\frac{4}{3}\right)^2-\frac{5}{6}=-\frac{7}{18}\)

\(\left(2,5x-\frac{4}{3}\right)^2=-\frac{7}{18}+\frac{5}{6}\)

\(\left(2,5x-\frac{4}{3}\right)^2=\frac{4}{9}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{4}{15}\end{cases}}\)

\(\left|-\frac{2}{5}x-\frac{4}{3}\right|=\left|4x-\frac{5}{6}\right|\)

\(=-\frac{2x}{5}-\frac{4}{3}=4x-\frac{5}{6}\)

\(=-\frac{2x}{5}-\frac{4}{3}=-\left(4x-\frac{5}{6}\right)\)

\(=x=-\frac{5}{44};\frac{65}{108}\)

\(\Rightarrow x=\orbr{\begin{cases}x=-\frac{5}{44}\\x=\frac{65}{108}\end{cases}}\)

|−25 x−43 |=|4x−56 |

=−2x5 −43 =4x−56 

=−2x5 −43 =−(4x−56 )

=x=−544 ;65108 

⇒x=[

mình thiếu dấu gạch p/s sorry

G=3

bn có cần lời giải ko?

để G lớn nhất thì :

\(|4x-1|\);\(|xy-3|\)nhỏ nhất và bằng 0

=> 4x-1 =0                                                        1/4 . y-3=0

          x= (1+0) :4                                                y=(0+3) :1/4

         x=1/4   =>x=1/4                                         y=12

=> G= 3 - \(|4x-1|\)-  \(|xy-3|\)

=> G=3-0-0=3

vậy maxG=3

em ko giai duoc ,em lop 2

-3/2 - | 3x + 4 |.2/5= 2

<=> | 3x + 4 | = (2+3/2)/(2/5)

<=>  | 3x + 4 | = 35/4

<=>3x + 4 =35/4

Hoặc 3x + 4 = - 35/4

Tự giải nốt nha

\(|3x+4|.\frac{2}{5}=\frac{-3}{2}-2\)

\(|3x+4|.\frac{2}{5}=\frac{-7}{2}\)

\(|3x+4|=\frac{-7}{2}:\frac{2}{5}\)

\(|3x+4|=\frac{-35}{4}\)

\(\Leftrightarrow3x+4=\frac{-35}{4}\)        hoặc          \(3x+4=\frac{35}{4}\)

         x=\(\frac{-17}{4}\)                                                x=\(\frac{19}{12}\)

Vậy x=\(\frac{-17}{4}\) hoặc    x= \(\frac{19}{12}\)

đợi mình xíu 

\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)

\(\Leftrightarrow\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{13}.3^{13}-2^{11}.3^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.2^{12}-2^{11}.2^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}.\left(1+5\right)}{6^{12}-6^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}.6}{6^{11}.\left(6-1\right)}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}.2.3}{6^{11}.\left(6-1\right)}\)

\(\Leftrightarrow\frac{2^{13}.3^{11}}{6^{11}.5}\)

\(\Leftrightarrow\frac{2^{11}.3^{11}.2^2}{6^{11}.5}\)

\(\Leftrightarrow\frac{6^{11}.4}{6^{11}.5}\Leftrightarrow\frac{4}{5}\)

A= 2/3+2/5-2/9/4/3+4/5-4/9

  = 2/3+2/5-8/27+4/5-4/9

  = (2/3-8/27-4/9)+(2/5+4/5)

  = -2/27+6/5 = 152/135

Ta có: 2/3+2/5-2/9

          4/3+4/5-4/9

=2/4.1/3+1/5-1/9

        1/3+1/5-1/9

=2/4=1/2

=>A=1/2