\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{15}+2^9.3^9.8.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{15}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(6-1\right)}\)

\(=\frac{2^{10}.3^{10}\left(2^2.3^5+2^2.5\right)}{5.6^{11}}=\frac{6^{10}\left[4\left(243+5\right)\right]}{6^{10}.30}=\frac{4\left(243+5\right)}{30}\)

\(=\frac{992}{30}\)

đợi mình xíu 

\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)

\(\Leftrightarrow\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{13}.3^{13}-2^{11}.3^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.2^{12}-2^{11}.2^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}.\left(1+5\right)}{6^{12}-6^{11}}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}.6}{6^{11}.\left(6-1\right)}\)

\(\Leftrightarrow\frac{2^{12}.3^{10}.2.3}{6^{11}.\left(6-1\right)}\)

\(\Leftrightarrow\frac{2^{13}.3^{11}}{6^{11}.5}\)

\(\Leftrightarrow\frac{2^{11}.3^{11}.2^2}{6^{11}.5}\)

\(\Leftrightarrow\frac{6^{11}.4}{6^{11}.5}\Leftrightarrow\frac{4}{5}\)

nhân chia trc cộng trừ sau nhé bạn

làm bài này đc thì chỉ có bạn mới tính ra

ủng hộ mình lên 360 điểm nha các bạn

trả lời đi đã

4^{6 .}9⁵ +69.120−8⁴.3¹²−6¹¹

=2¹² .3¹0+2⁹.3⁹.2³.3.5−2¹².3¹²−2¹¹.3¹¹

=2¹².3¹⁰+2¹⁰.3¹⁰.5−2¹².3¹²−3¹¹.2¹¹

=2¹¹.310.(2+2.5)2¹¹.3¹⁰.(−2.32−3)

=−47 +x=1

=>x=48

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9

= ( 1 +9 ) + ( 2 + 8 ) + ( 3 + 7 ) + ( 4 + 6 ) + 5

= 10 + 10 + 10 + 10 + 5

= 40 + 5

= 45

k mk nha , 

mk cảm ơn bạn nhiều

Thank you very much

( ^ _ ^ )

1+2+3+4+5+6+7+8+9=45

tk tui tui tk lại

\(1+2+3+4+5+6+7+8+9\)

\(=\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5\)

\(=10+10+10+10+5\)

\(=45\)

k nha