tìm x biết
a,\(|5x+\frac{3}{4}|-\frac{5}{4}=2\)
b,\(\frac{3}{2}-|\frac{1}{2}x+1|=\frac{1}{4}\)
cac ban lam on giup minh lam nhanh nhe
cac ban ho minh bai nay nha
\(A=\sqrt{x+2}+\frac{3}{11};B=\frac{5}{7}-3\cdot\sqrt{x-5}\)
giup minh lam bai nay nhe
cam on cac ban nhieu
a. Giá trị nhỏ nhất của A=\(\sqrt{2}+\frac{3}{11}\)
không có giá trị lớn nhất
b. Giá trị lớn nhất của B là \(\frac{5}{7}\) khi x=5 không có GTLN
dùng phần mềm viết không chuẩn do chưa quen
GTNN của A là 3/11 khi x=-2
GTLN của B la 5/7 khi x=-5
bài 1 cho >=0, b>=0
CMR: \(\frac{a^3+b^3}{2}>=\left(\frac{a+b}{2}\right)^3\)
cac ban oi lam on giup minh di chieu minh di hoc roi. nhanh nhe
Ta có: (a-b)2 (a+b)>=0
=> (a-b)(a2-b2) >=0
=> a 3 +b3- a2b -ab2 >=0
=> 3a3+3b3-3a2b-3ab2>=0
=> 4a3+4b3>= (a^3+b^3+3a2b+3ab2)
=> 4a3+ 4b3 >= (a+b)3 => đpcm, tích cho mình nhé
Tìm a,b,c sao cho
a, \(\frac{1}{x\left(x+1\right).\left(x+2\right)}=\frac{a}{x}+\frac{b}{x+1}+\frac{c}{x+2}\)
cac ban oi giup minh di. minh dang can gap lam. lam on
tick đi giải cho
đáp án là a=4.............
a)\(x-\frac{4}{5}=\frac{5}{7}\);b)\(5x=\frac{-1}{5}+\frac{11}{5}\); c)\(\frac{5}{3}-x=7+\frac{4}{5}\);d)\(\frac{-5}{11}+2x=\frac{7}{22}\)
CAC BAN GIUP MINH NHE MINH DANG CAN GAP
a) \(x-\frac{4}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{4}{5}=\frac{53}{35}\)
b) \(5x=-\frac{1}{5}\)
\(x=-\frac{1}{5}:5=-\frac{1}{25}\)
c) \(\frac{5}{3}-x=7+\frac{4}{5}\)
\(\frac{5}{3}-x=\frac{39}{5}\)
\(x=\frac{5}{3}-\frac{39}{5}=-\frac{92}{15}\)
d) \(-\frac{5}{11}+2x=\frac{7}{22}\)
\(2x=\frac{7}{22}+\frac{5}{11}\)
\(2x=\frac{17}{22}\)
\(x=\frac{17}{22}:2\)
\(x=\frac{17}{44}\)
\(x=-\frac{1}{5}:5\)
NÈ BẠN!!!
a) \(x-\frac{4}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{4}{5}=\frac{25}{35}+\frac{28}{35}=\frac{53}{35}\)
b) \(5x=-\frac{1}{5}+\frac{11}{5}\)
\(5x=2\)
\(x=\frac{2}{5}\)
c)\(\frac{5}{3}-x=7\)
\(x=\frac{5}{3}-7=\frac{5}{3}-\frac{21}{3}=-\frac{16}{3}\)
d) \(-\frac{5}{11}+2x=\frac{7}{22}\)
\(2x=\frac{7}{22}-\frac{-5}{11}=\frac{7}{22}-\frac{-10}{22}=\frac{17}{22}\)
\(x=\frac{17}{22}:2=\frac{17}{22}\cdot\frac{1}{2}=\frac{17}{44}\)
K CHO MÌNH NHA!!!
\(\frac{\text{3}}{\text{4}}+\frac{\text{1}}{\text{4}}:x=\frac{\text{2}}{5}\)
biet x thuoc Q
cac ban giup mik nhe cam on nhieu :3
\(\frac{1}{4}:x=-\frac{7}{20}\)
\(x=\frac{1}{4}:-\frac{7}{20}\)
\(x=-\frac{5}{7}\)
\(\frac{3}{4}+\frac{1}{4}\div x=\frac{2}{5}\)
\(\Rightarrow\frac{1}{4}\div x=-\frac{7}{20}\)
\(\Rightarrow x=\frac{1}{4}\div\left(-\frac{7}{20}\right)\)
\(\Rightarrow x=-\frac{5}{7}\)
1/4 : x=2/5 - 3/4
1/4 : x= - 7/20
x=1/4 : - 7/20
x=-5/7
k ủng hộ mk nha mọi người
k mk , mk k lại
bài 1 cho a,b,c>0: CMR
a, \(\frac{1}{a}+\frac{1}{b}>\frac{4}{a+b}\)
b, \(\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right).\left(a+b+c\right)>=9\)
cac ban giup minh di minh k hieu bai nay lam kieu j. minh dang can. cac ban oi lam on giup minh
bai 1 :thuc hien phep tinh
a)\(\frac{-5}{2}:\left(\frac{3}{4}-\frac{1}{2}\right)\) b) \(11\frac{3}{13}-\left(2\frac{4}{7}+5\frac{3}{13}\right)\) c)\(\left(\frac{-5}{24}+0,75+\frac{7}{12}\right):\left(-2\frac{1}{4}\right)^2\)
AI LAM NHANH VA DUNG THI MK SE TICK CHO NHA
MK DAG CAN GAP !!!!!!! CAC BAN LAM NHANH LEN NHA
Bài 1: Cho A=\(\left(\frac{1}{3}+\frac{3}{x^2-3x}\right):\left(\frac{x^2}{27-3x^2}+\frac{1}{x+3}\right)\)
a, Rút gọn A
b, Tìm x để A<-1
cac ban oi giup minh di minh dang can gap lam. ai giup minh hên nhat nam 2016
a. \(A=\left[\frac{1}{3}+\frac{3}{x.\left(x-3\right)}\right]:\left[\frac{x^2}{3.\left(9-x^2\right)}+\frac{1}{x+3}\right]\)
\(=\left[\frac{x.\left(x-3\right)}{3.x.\left(x-3\right)}+\frac{3.3}{x\left(x-3\right).3}\right]:\left[\frac{x^2}{3.\left(3-x\right)\left(3+x\right)}+\frac{1}{x+3}\right]\)
\(=\left[\frac{x^2-3x+9}{3x.\left(x-3\right)}\right]:\left[\frac{x^2}{3.\left(3-x\right)\left(3+x\right)}+\frac{\left(3-x\right).3}{\left(x+3\right).\left(3-x\right).3}\right]\)
\(=\frac{x^2-3x+9}{3x.\left(x-3\right)}:\left[\frac{x^2+9-3x}{3.\left(3-x\right)\left(3+x\right)}\right]\)
\(=\frac{x^2-3x+9}{3x.\left(x-3\right)}.\frac{3.\left(3-x\right)\left(3+x\right)}{x^2-3x+9}\)
\(=\frac{-\left(x-3\right)\left(3+x\right)}{x-3}=-\left(3+x\right)\)
b. Để A < -1 thì:
-(3+x) < -1
=> -3 - x < -1
=> x < -3 - (-1) = -2
Vậy x < -2 thì A < -1.
\(\frac{x^2+3x+2}{x^2+3}\)=\(\frac{x^2+7+6}{x^2+7x+4}\)tim x nguyen cac ban lam giupminh nhe