\(-\frac{12}{35}\div\frac{7}{11}-\frac{23}{35}\div\frac{7}{11}-\frac{5}{11}\)

\(=\left(-\frac{12}{35}-\frac{23}{35}\right)\div\frac{7}{11}-\frac{5}{11}\)

\(=-1\div\frac{7}{11}-\frac{5}{11}\)

\(=-\frac{11}{7}-\frac{5}{11}\)

\(=-\frac{156}{77}\)

\(2-\frac{11}{9}\div\frac{5}{14}-\frac{7}{9}\times\frac{14}{5}\)

\(=2-\frac{154}{45}-\frac{98}{45}\)

\(=-\frac{64}{45}-\frac{98}{45}\)

\(=-\frac{18}{5}\)

Mình làm câu này  các câu khác tương tự 

Mấu chốt làm bài này là đưa về thừa số nguyên tố

\(\frac{12^7.3^{35}.14^{21}}{9^{21}.7^{21}.2^{35}}=\frac{3^7.4^7.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{2.7}.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{14}.3^{35}.2^{21}.7^{21}}{3^{42}.7^{21}.2^{35}}=\frac{3^{42}.2^{35}.7^{21}}{3^{42}.7^{21}.2^{35}}=1\)

a) 2763 + 1522763 + 152

= 1 525 678

b) (-7) + (-14).(-7) + (-14)

= 77

c) (-35) + (-9).(-35) + (-9)

= 271

a) 2763 + 1522763 + 152

= 1 525 678

b) (-7) + (-14).(-7) + (-14)

= 77

c) (-35) + (-9).(-35) + (-9)

= 271

7 . ( x - 14 ) + 35 = 25 + 297 : 9

7 . ( x - 14 ) + 35 = 25 + 33

7 . ( x - 14 ) + 35 = 58

7 . ( x - 14 ) = 58 - 35

7 . ( x - 14 ) = 23

x - 14 = 23 : 7 

x - 14 = \(\frac{23}{7}\)

x = \(\frac{23}{7}+14\)

x = \(\frac{121}{7}\)

a) 2763 + 152 = 2915

b) Ta có : |–7| = 7; |–14| = 14.

Do đó: (–7) + (–14) = – ( |–7| + |–14| ) = – (7 + 14) = –21.

c) (–35) + (–9) = – (|–35| + |–9|) = – (35 + 9) = –44.

a = 302 / 105

b = 98/9

c= 6/5

tick nha

a=302/105

b 98 /9

c6/5

k nha và học tốt