tim x y z biet x-1/2=y-2/3=z-3/4 biet x-2y+3z=14
Tim x,y,z biet:
(2|x|+5)/3=(3|y|-1)/5=(3-z)/7 va 2|x|+7|y|+3z=-14
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}vax-2y+3z=14\)
de bai la tim x, y, z biet
giup mk
mk tk
mk dag voi
\(\frac{x-1}{2}\)= \(\frac{2y-4}{6}\)=\(\frac{3z-9}{12}\)=\(\frac{x-1-2y+4+3z-9}{2-6+12}\)= \(\frac{14-1+4-9}{8}\)= 1
=> x =2+1=3
y= (6+4) : 2=5
z=(12+9) : 3=7
biet x;y;z thoa man: (x-1)/2 = (y-2)/3 = (z-3)/4 va x-2y+3z = -10
khi do x+y+z = ?
suy ra x-1/2+1=y-2/3+1=z-3/4+1 suy ra x+1/2=y+1/3=z+1/4 = K Ta có x=2K-1;y=3K-1;z=4k-1 mà x-2y+3z =-10
Tim cac sox y z biet x-1/2=y-2/3=z-3/4 va x-2*y+3*z=14
Tim x, y, z biet x, y, z > 0 , x-y/z = y-z/x = z-x/y va x+2y+3z=30
tim x,y,z biet 3x/8=3y/64=3z/216va 2x^2+2y^2-z^2=1
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\); x-2y+3z=14
tim x y z
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) \(\Rightarrow\frac{x-1}{2}=\frac{2y-4}{6}=\frac{3z-9}{12}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x-1}{2}=\frac{2y-4}{6}=\frac{3z-9}{12}=\frac{x-1-2y-4+3z-9}{2-6+12}=\frac{\left(x-2y+3z\right)-\left(1+4+9\right)}{8}=\frac{14-14}{8}=0\)
\(x=0.2+1=1\) ; \(y=\left(0.6+4\right):2=2\) ; \(z=\left(0.12+9\right):3=3\)
tìm x,y,z biết x/-3=y/-7=z/12 và -2x-4y+5z=146
bài 2
tim x, y z biet 4x/-5=2y/7=-3z/8 và x+3y-2z=-273
giai nhanh dung minh tick
tìm x,y,z biet:
x+1/2=y-2/-1=z+5/3 va x+2y+3z+28=0
giúp mình nha