tinh rut gon
\(625^5:25^7\)
tinh rut gon
\(2003^{2^{0^{1^0}}}\)
\(625^5:25^7\)
giup minh
20032^0^1^0 = 20032^0^1 = 20032^0 = 20031 = 2003
NHỚ TIK f.t THEO DÕI NHA
Rut gon phan so sau
\(\frac{9^9.225^5.8^7}{18^{12}.625^3.24^3}\)
\(\frac{9^9\cdot225^5\cdot8^7}{18^{12}\cdot625^3\cdot24^3}=\frac{9^9\cdot\left(\left(3\cdot5\right)^2\right)^5\cdot8^7}{\left(9\cdot2\right)^{12}\cdot\left(\left(5^2\right)^2\right)^3\cdot\left(8\cdot3\right)^3}\)
\(=\frac{1}{9^3\cdot2^{12}}\cdot\frac{9^5\cdot5^{10}}{5^{12}}\cdot\frac{8^7}{8^3\cdot3^3}\)
\(=\frac{9^2\cdot8^4}{2^{12}\cdot5^2\cdot3^3}\)
\(=\frac{9\cdot\left(2^4\right)^3}{\left(2^4\right)^3\cdot5^2}\)
\(=\frac{9}{25}\)
rut gon roi tinh :
15/25+6/21
\(\frac{15}{25}=\frac{15:5}{25:5}=\frac{3}{5}\); \(\frac{6}{21}=\frac{6:3}{21:3}=\frac{2}{7}\)
\(\frac{3}{5}+\frac{2}{7}=\frac{31}{35}\)
\(\frac{15}{25}+\frac{6}{21}=\frac{3}{5}+\frac{2}{7}=\frac{21}{35}+\frac{10}{35}=\frac{31}{35}\)
15/25+6/21
ta có:
15/25=15:5/25:5=3/5
6/21=6:3/21:3=2/7
3/5+2/7=31/35
tick nha
tinh roi rut gon
a}12/20 - 6/18
b}8/24-5/25
c) 18/21-12/27
giup minh voi nha!
rut gon phan so
914 x 2255 x 87
1812 x 6253 x 243
cho bieu thuc A = /x-1/ + 3x-7
a. rut gon bieu thuc
b. tinh A khi x=3;x=-5
rut gon roi tinh:
28/35*15/72*1 va 7/49.
miru
Rút gọn rồi tính:
\(\frac{28}{35}.\frac{15}{72}.1\frac{7}{49}\)
\(=\frac{4}{5}.\frac{5}{24}.\frac{56}{49}\)
\(=\frac{4.5.8}{5.24.7}=\frac{4}{21}\)
\(\frac{28}{35}.\frac{15}{72}.1\frac{7}{49}\)
\(=\frac{4}{5}.\frac{5}{24}.\frac{7}{49}\)
\(=\frac{4}{21}\)
k mk nha, cảm ơn những người đã k
Tinh roi rut gon (theo mau)
a,1/8 + 5/8 b,5/9 + 7/9
\(a,\frac{1}{8}+\frac{5}{8}=\frac{1+5}{8}=\frac{6}{8}=\frac{6:2}{8:2}=\frac{3}{4}\)
\(b,\frac{5}{9}+\frac{7}{9}=\frac{5+7}{9}=\frac{12}{9}=\frac{12:3}{9:3}=\frac{4}{3}\)
Tính roi rut gon:
A).2/7:4/5 b).3/8:9/4 c).8/21:4/7
D).5/8:15/8
Ai lam day du phep tinh va cach rug gon mik tick 2 cai lan
A)2/7:4/5=2/7*5/4=10/28=5/14
b)3/8:9/4=3/8*4/9=12/72=1/6
c)8/21:4/7=8/21*7/4=56/84=2/3
D)5/8:15/8=5/8*8/15=40/120=1/3
k nha