\(\sqrt{150\cdot27\cdot96}\)
Những câu hỏi liên quan
thực hiện phép tính và rút gọn: Asqrt{3-sqrt{5}} * sqrt{3+sqrt{5}} ; B sqrt{150cdot27cdot96}; C [sqrt{27}+sqrt{48} ]^2-[ sqrt{27} -sqrt{48} ]^{^{ }2} ; D sqrt{137^2-88^2} -sqrt{192^2-111^2} ;E sqrt{frac{225}{4}cdotfrac{81}{25}cdotfrac{49}{64}} ; F sqrt{frac{27}{25}} *sqrt{frac{44}{189}} *sqrt{frac{700}{99}} ; H sqrt{105} *[sqrt{frac{15}{7}} -sqrt{frac{35}{5}} +sqrt{frac{21}{5}} ] ;K sqrt{64cdot14cdot21cdot54} -sqrt{35cdot45cdot12}
Đọc tiếp
thực hiện phép tính và rút gọn: A=\(\sqrt{3-\sqrt{5}}\) * \(\sqrt{3+\sqrt{5}}\) ; B= \(\sqrt{150\cdot27\cdot96}\); C= [\(\sqrt{27}\)+\(\sqrt{48}\) ]\(^2\)-[ \(\sqrt{27}\) -\(\sqrt{48}\) ]\(^{^{ }2}\) ; D= \(\sqrt{137^2-88^2}\) -\(\sqrt{192^2-111^2}\) ;E= \(\sqrt{\frac{225}{4}\cdot\frac{81}{25}\cdot\frac{49}{64}}\) ; F= \(\sqrt{\frac{27}{25}}\) *\(\sqrt{\frac{44}{189}}\) *\(\sqrt{\frac{700}{99}}\) ; H= \(\sqrt{105}\) *[\(\sqrt{\frac{15}{7}}\) -\(\sqrt{\frac{35}{5}}\) +\(\sqrt{\frac{21}{5}}\) ] ;K= \(\sqrt{64\cdot14\cdot21\cdot54}\) -\(\sqrt{35\cdot45\cdot12}\)
\(A=\sqrt{3+\sqrt{5}}.\sqrt{3-\sqrt{5}}=\sqrt{3^2-\left(\sqrt{5}\right)^2}=\sqrt{4}=2\)
\(B=\sqrt{150.27.96}=\sqrt{150}.\sqrt{27}.\sqrt{96}=5\sqrt{6}.3\sqrt{3}.4\sqrt{6}=360\sqrt{3}\)
\(C=\left(\sqrt{27}+\sqrt{48}\right)^2-\left(\sqrt{27}-\sqrt{48}\right)^2\)\(=\left[\left(\sqrt{27}+\sqrt{48}-\sqrt{27}+\sqrt{48}\right)\left(\sqrt{27}+\sqrt{48}+\sqrt{27}-\sqrt{48}\right)\right]\)
\(=2\sqrt{27}.2\sqrt{48}=2.3\sqrt{3}.2.4\sqrt{3}=144\)
\(D=\sqrt{137^2-88^2}-\sqrt{192^2-111^2}=\sqrt{\left(137+88\right)\left(137-88\right)}-\sqrt{\left(192+111\right)\left(192-111\right)}\)
\(=\sqrt{225.49}-\sqrt{303.81}=15.7-9.\sqrt{303}=9\left(\frac{35}{3}-\sqrt{303}\right)\)
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\(E=\sqrt{\frac{225}{4}.\frac{81}{25}.\frac{49}{64}}=\frac{15}{2}.\frac{9}{5}.\frac{7}{8}=\frac{189}{16}\)
\(F=\sqrt{\frac{27}{25}}.\sqrt{\frac{49}{189}}.\sqrt{\frac{700}{99}}=\frac{3\sqrt{3}}{5}.\frac{7}{3\sqrt{21`}}.\frac{10\sqrt{7}}{3\sqrt{11}}=\frac{14}{3\sqrt{11}}\)
\(H=\sqrt{105}.\left[\sqrt{\frac{15}{7}}-\sqrt{\frac{35}{5}}+\sqrt{\frac{21}{5}}\right]=\sqrt{105}.\left[\sqrt{\frac{15}{7}}-\sqrt{7}+\sqrt{\frac{21}{5}}\right]\)
\(=\sqrt{105}.\left[\frac{\sqrt{75}-\sqrt{49}+\sqrt{147}}{\sqrt{35}}\right]=\sqrt{3}\left(12\sqrt{3}-7\right)=36-7\sqrt{3}\)
\(K=\sqrt{64.14.21.54}-\sqrt{35.45.12}=8.\sqrt{14}.\sqrt{21}.3\sqrt{6}-\sqrt{35}.3\sqrt{5}.2\sqrt{3}\)
\(=24.\sqrt{14.21.6}-6\sqrt{35.5.3}=24.42-30\sqrt{21}=30\left(\frac{168}{5}-\sqrt{21}\right)\)
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\(\frac{12^2\cdot4^{16}}{11\cdot2^{13}\cdot4^{11}-16^9}+\frac{7\cdot9+14\cdot27+21\cdot36}{21\cdot27+42\cdot81+63\cdot108}\)
thực hiện phép tính
\(\frac{1}{100\cdot99}-\frac{1}{99\cdot98}-\frac{1}{98\cdot96}-...-\frac{1}{3\cdot2}-\frac{1}{2\cdot1}\)
\(\frac{1}{100.99}-\left(\frac{1}{99.98}+\frac{1}{98.97}+...+\frac{1}{2.1}\right)\)
\(=\frac{1}{100}-\frac{1}{99}-\left(\frac{1}{99}-\frac{1}{98}+\frac{1}{98}-\frac{1}{97}+...+\frac{1}{2}-1\right)\)
\(=\frac{1}{100}-\frac{1}{99}-\left(\frac{1}{99}-1\right)\)
\(=\frac{1}{100}-\frac{1}{99}-\frac{1}{99}+1\)
\(=\frac{9799}{9900}\)
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rút gọn \(B=\frac{1+\left(1+2\right)+\left(1+2+3\right)+.........+\left(1+2+3+.......+98\right)}{1\cdot98+2\cdot97+3\cdot96+........+98\cdot1}\)
\(\frac{27\cdot18+27\cdot103-120\cdot27}{15\cdot33+33\cdot12}\)
=27.(18+103-120)/33.(15+12)
= 27.1/33.27
=1/33
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\(=\frac{27\left(18+103-120\right)}{33\left(15+12\right)}\)
\(=\frac{27\times1}{33\times27}\)
\(=\frac{1}{33}\)
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Tính :
\(27\cdot75+25\cdot27-150\)
\(12:\left\{390:\left[500-\left(125+35\cdot7\right)\right]\right\}\)
27.75+25.27-150=27.(75+25)-150
=27.100-150
=2700-150
=2550
12:{390:[500-(125+37.5)]}=12:{390:[500-(125+245)]}
=12:[390:(500-370)]
=12:(390:130)
=12:3
=4
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27 . 75 + 25 . 27 - 150 = 27. ( 75+ 25 ) - 150 12 : { 390 : [ 500 - (125 + 35 . 7 ) ] }
= 27. 100 - 150 12 : { 390 : [ 500 - ( 125 + 245 ) ] }
= 2700 - 150 12 : { 390 : [ 500 - 370 ] }
= 2550 12 : { 390 : 130 }
12 : 3 = 4
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tính giá trị biểu thức
\(B=\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}\)
\(C=\frac{2181\cdot729+243\cdot81\cdot27}{3^2\cdot9^2\cdot243+18\cdot54\cdot162\cdot9+723\cdot729}\)
lời giải nữa nhé
\(A=2000\)
\(B=\frac{-2}{11}\)
\(C=1\)
\(D=\frac{11}{10}\)
Nát óc mới làm được
k ủng hộ nhá
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\(\frac{3}{9\cdot15}+\frac{3}{15\cdot21}+\frac{3}{21\cdot27}+.....+\frac{3}{99\cdot105}\)
=\(\frac{1}{2}\cdot\left(\frac{6}{9\cdot15}+\frac{6}{15\cdot21}+\frac{6}{21\cdot27}+...+\frac{6}{99\cdot105}\right)\)
=\(\frac{1}{2}\cdot\left(\frac{1}{9}-\frac{1}{15}+\frac{1}{15}-\frac{1}{21}+\frac{1}{21}-\frac{1}{27}+...+\frac{1}{99}-\frac{1}{105}\right)\)
=\(\frac{1}{2}\cdot\left(\frac{1}{9}-\frac{1}{105}\right)\)
=\(\frac{1}{2}\cdot\left(\frac{35}{315}-\frac{3}{315}\right)\)
=\(\frac{1}{2}\cdot\left(\frac{32}{315}\right)\)
=\(\frac{1\cdot16}{1\cdot315}\)
=\(\frac{16}{315}\)
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Tính \(A=\left(\frac{1}{4\cdot9}+\frac{1}{9\cdot14}+\frac{1}{14\cdot19}+...+\frac{1}{44\cdot49}\right)\cdot\frac{1-3-5-7-...-49}{89}\)
\(B=\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}-\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
bài này không khó. Nhưng đánh máy để giải cho bạn thì thực sự khó
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