tìm x biết
\(\left[\left(7+0,004.x\right):0,9\right]:24,7-12,3=77,7\)
[(7+0,004.X):0,9]:24,7-12,3=77,7
[(7+0,004.x):0,9]:24,7-12,3=77,7
[(7+0,004.x):0,9]:24,7=77,7+12,3
[(7+0,004.x):0,9]:24,7=90
(7+0,004.x):0,9=90.24,7
(7+0,004.x):0,9=2223
7+0,004.x=2223.0,9
7+0,004.x=2000,7
0,004.x=2000,7-7
0,004.x=1993,7
x=1993,7:0,004
x=498425
Tìm x, biết:
a) 2 1 3 + 3 1 2 : x + 3 1 7 + 7 1 2 = 1 69 86
b) 7 + 0 , 004. x : 0 , 9 : 24 , 7 − 12 , 3 = 77 , 7
c) 6 3 7 − 0 , 75 x − 2 0 , 35 .2 , 8 + 1 , 75 : 0 , 05 = 235
d) 5 4 7 : x : 1 , 3 + 8 , 4. 6 7 . 6 − 2 , 3 + 5 : 6 , 25 .7 8.0 , 0125 + 6 , 9 = 1 1 14
Tìm x,biết:
\(a,\)\(\left(2\frac{1}{3}+3\frac{1}{2}\right):\left(x+3\frac{1}{7}\right)+7\frac{1}{2}=1\frac{69}{86}\)
\(b,\left(7+0,00.x\right):24,7-12,3=77,7\)
\(c,\left(\left(6\frac{3}{7}-\frac{0,75-2}{0,35}\right).2,8+1,75\right):0,05=2,35\)
Gía trị nào của x thỏa mãn
[(7+0,004x):0,9]: 24,7-12,3 = 77,7
A. x = 49842
B. x = 498
C. x = 498420
D. x = 498425
giúp mình bài này nha mn
tìm x biết [(7 + 0,004x ) :0,9] :24,7 -12,3 = 77,7
[(7 + 0,004x ) :0,9] :24,7 -12,3 = 77,7
= [(7 + 0,004x ) :0,9] :24,7 = 77,7 + 12,3 = 90
=> ( 7 + 0,004x ) : 0,9 = 90 . 24,7 = 2223
=> 7 + 0,004x = 2223 . 0,9 = 2000,7
=> 0,004 = 2000,7 - 7 = 1993,7
=> x = 1993,7 : 0,004 = 498 425
Ta có
[(7+0,004x):0,9]:24,7−12,3=77,7
[(7+0,004x):0,9]:24,7=77,7+12,3
[(7+0,004x):0,9]:24,7=90
(7+0,004x):0,9=90.24,7
(7+0,004x):0,9=2223
7+0,004x=2223.0,9
7+0,004x=2000,7
0,004x=1993,7
x=498425
Vậy x=498425
\(\left[\left(7+0,004x\right):0,9\right]:24,7-12,3=77,7\)
\(\Leftrightarrow\left[\left(7+0,004x\right):0,9\right]:24,7=90\)
\(\Leftrightarrow\left(7+0,004x\right):0,9=2223\)
\(\Leftrightarrow7+0,004x=2000,7\)
\(\Leftrightarrow0,004x=1993,7\)
\(\Leftrightarrow x=498425\)
#H
Tính nhanh
a) \(\frac{3,06:7,5+3,4\text{x}0,38}{19-2,6\text{x}0,5}x\frac{\left(1,6-1-0,6\right)x\left(2,29-0,76\right)}{1,6+2,53}\)=
b) \(\frac{17,8\text{x}3,7-7,8\text{x}4,8+5,7\text{x}17,8-4,2\text{x}7,8}{11,2+12,3+13,4-12,6-11,5-10,4}=\)
Tìm X
x . 4 - x : 4 - 24,7 = 190,48 : 2
Tìm x biết: \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Ta có: \(\frac{3}{\left(x+2\right)\left(x+5\right)}=\frac{1}{x+2}-\frac{1}{x+5}\); \(\frac{5}{\left(x+5\right)\left(x+10\right)}=\frac{1}{x+5}-\frac{1}{x+10}\)
\(\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{1}{x+10}-\frac{1}{x+17}\);
=> Phương trình tương đương:
\(\frac{1}{x+2}-\frac{1}{x+5}+\frac{1}{x+5}-\frac{1}{x+10}+\frac{1}{x+10}-\frac{1}{x+17}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
\(\frac{1}{x+2}-\frac{1}{x+17}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)<=> \(\frac{x+17-x-2}{\left(x+2\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
<=> \(\frac{15}{\left(x+2\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
=> x=15
Đáp số: x=15
tìm x biết:
a, \(\left(x+4\right)^2-\left(x+1\right)\left(x-1\right)=16\)
b, \(\left(2x-1\right)^2-\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\)
a,\((x+4)^2-(x+1)(x-1)=16\)
\(\Rightarrow x^2+8x+16-x^2+1=16\)
\(\Rightarrow 8x=-1\Rightarrow x=-\dfrac{1}{8}\)
b,\((2x-1)^2-(x+3)^2-5(x+7)(x-7)=0\)
\(\Rightarrow 4x^2-4x+1-(x^2+6x+9)-5(x^2-49)=0\)
\(\Rightarrow 4x^2-4x+1-x^2-6x-9-5x^2-245=0\)
\(\Rightarrow -x^2-10x-244=0\)
\(\Rightarrow -(x^2-10x+25)-219=0\)
\(\Rightarrow -(x-5)^2-219=0\)
\(\Rightarrow (x-5)^2+219=0\)
Mà \((x-5)^2+219>0\) suy ra PT vô nghiệm
Mình cần gấp bài này !!!
1/Tìm x, biết :
a/ \(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{11}{\left(x+10\right)\left(x+21\right)}+\frac{13}{\left(x+21\right)\left(x+34\right)}+\frac{x}{\left(x+3\right)\left(x+34\right)}\)
b/ \(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)