dễ 

ợt

lớp 5 còn làm ra

tíc mình nha

a) \(\frac{-3}{5}.y=\frac{21}{10}\)

          \(y=\frac{21}{10}:\frac{-3}{5}\)

         \(y=\frac{-7}{2}\)

vậy \(y=\frac{-7}{2}\)

b) \(y:\frac{3}{8}=-1\frac{31}{33}\)

  \(y:\frac{3}{8}=\frac{-64}{33}\)

\(y=\frac{-64}{33}.\frac{3}{8}\)

\(y=\frac{-8}{11}\)

vậy \(y=\frac{-8}{11}\)

c) \(1\frac{2}{5}.y+\frac{3}{7}=\frac{-4}{5}\)

\(\frac{7}{5}.y+\frac{3}{7}=\frac{-4}{5}\)

\(\frac{7}{5}.y=\frac{-4}{5}-\frac{3}{7}\)

\(\frac{7}{5}.y=\frac{-43}{35}\)

\(y=\frac{-43}{35}:\frac{7}{5}\)

\(y=\frac{-43}{49}\)

vậy \(y=\frac{-43}{49}\)

d) \(\frac{-11}{12}.y+0,25=\frac{5}{6}\)

\(\frac{-11}{12}.y=\frac{5}{6}-0,25\)

\(\frac{-11}{12}.y=\frac{7}{12}\)

\(y=\frac{7}{12}:\frac{-11}{12}\)

\(y=\frac{-7}{11}\)

vậy \(y=\frac{-7}{11}\)

a) \(y=\frac{21}{10}:\left(-\frac{3}{5}\right)=-\frac{7}{2}\)

b) \(y=-1\frac{31}{33}.\frac{3}{8}=-\frac{8}{11}\)

c) \(1\frac{2}{5}.y=-\frac{4}{5}-\frac{3}{7}=-\frac{43}{35}\Rightarrow y=-\frac{43}{35}:1\frac{2}{5}=-\frac{43}{49}\)

d) \(-\frac{11}{12}.y=\frac{5}{6}-0,25=\frac{7}{12}\Rightarrow y=\frac{7}{12}:\left(-\frac{11}{12}\right)=-\frac{7}{11}\)

sao bạn tự đăng tự giải thế? hay là bạn giải cho ai à?

ukm bn

ta co : \(\frac{x}{12}=\frac{y}{9}=\frac{z}{5}\) va x.y.z=20

Dat : \(\frac{x}{12}=\frac{y}{9}=\frac{z}{5}=k\)

x=12k³

y=9k³

z=5k³

x.y.z=540k³

20    = 540k³

k³     =27

k       = +-3

Voi : \(k=3\Rightarrow x=36;y=27;z=15\)

Voi :\(k=-3\Rightarrow x=-36;y=-27;z=-15\)

a) Đặt \(\frac{x}{12}=\frac{y}{9}=\frac{z}{5}=k\)

=>x=12k;y=9k;z=5k

Thay x=12k;y=9k;z=5k vào biểu thức x.y.z=20 ta được

(12k)(9k)(5k)=20

    12k.9k.5k=20

    540.\(k^3\)=20

           k\(^3\)=\(\frac{1}{27}\)

=>k=\(\frac{1}{3}\)

=>\(x=\frac{1}{3}.12=4\)

    \(y=\frac{1}{3}.9=3\)

   \(z=\frac{1}{3}.5=\frac{5}{3}\)

Vậy x=4;y=3;z=\(\frac{5}{3}\)

b)Ta có:

\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{2}z\)=>\(\frac{6x}{11}=\frac{9y}{2}=\frac{18z}{5}\)=>\(\frac{6x}{11.18}=\frac{9y}{2.18}=\frac{18z}{5.18}\)=>\(\frac{6x}{198}=\frac{9y}{36}=\frac{18z}{90}\)

=>\(\frac{x}{33}=\frac{y}{4}=\frac{z}{5}\)

Áp dụng tính chất của dãy tỉ số bằng nhau ta có:

\(\frac{x}{33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{-120}{-24}=5\)

=>\(\frac{x}{33}=5\)=>\(x=5.33=165\)

     \(\frac{y}{4}=5\)=>\(y=5.4=20\)

     \(\frac{z}{5}=5\)=>\(z=5.5=25\)

Vậy x=165;y=20;z=25

a, 5x = 8y => \(\frac{x}{8}=\frac{y}{5}\)

8y = 20z => 2y = 5z => \(\frac{y}{5}=\frac{z}{2}\)

=> \(\frac{x}{8}=\frac{y}{5}=\frac{z}{2}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có :

\(\frac{x}{8}=\frac{y}{5}=\frac{z}{2}=\frac{x-y-z}{8-5-2}=\frac{3}{1}=3\)

=> x = 24,y = 15,z = 6

b, \(\frac{6}{11}x=\frac{9}{2}y\)=> \(\frac{12x}{22}=\frac{99y}{22}\)=> 12x = 99y => 4x = 33y => \(\frac{x}{33}=\frac{y}{4}\)

\(\frac{9}{2}y=\frac{18}{5}z\)=> \(\frac{45y}{10}=\frac{36z}{10}\)=> 45y = 36z => 5y = 4z => \(\frac{y}{4}=\frac{z}{5}\)

=> \(\frac{x}{33}=\frac{y}{4}=\frac{z}{5}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có :

\(\frac{x}{33}=\frac{y}{4}=\frac{z}{5}\Rightarrow\frac{-x}{-33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{120}{-24}=-5\)

=> x = -165 , y = -20 , z = -25

c, Đặt : \(\frac{x}{12}=\frac{y}{9}=\frac{z}{5}=k\)=> x = 12k , y = 9k , z = 5k

=> xyz = 12k . 9k . 5k

=> xyz = 540k³

=> 540k³ =20

=> k³ = 20/540

=> k³ = 1/27

=> k = 1/3

Do đó : x= 4 , y = 3 , z = 5/3

Ta có: \(\frac{y}{3}+y\cdot\frac{2}{3}=\frac{y}{12}+\frac{11}{6}\)

=> \(\frac{y}{3}+\frac{2y}{3}=\frac{y}{12}+\frac{22}{12}\)

=> \(\frac{y+2y}{3}=\frac{y+22}{12}\)

=> \(\frac{3y}{3}=\frac{y+22}{12}\)

=> \(y=\frac{y+22}{12}\)

=> y + 22 = 12y

=> y - 12y = 22

=> -11y = 22

=> y = 22 : (-11) = -2

Vậy y = -2