\(X-\left(\frac{31}{5}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\right)=\frac{9}{13}\)

\(X-\left(\frac{31}{5}+\frac{31}{3\cdot5}+\frac{31}{5\cdot7}+\frac{31}{7\cdot9}+\frac{31}{9\cdot11}+\frac{31}{11\cdot13}\right)=\frac{9}{13}\)

\(X-\left[\frac{31}{2}\cdot\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)+\frac{31}{5}\right]=\frac{9}{13}\)

\(X-\left[\frac{31}{2}\cdot\left(\frac{1}{3}-\frac{1}{13}\right)+\frac{31}{5}\right]=\frac{9}{13}\)

\(X-\left[\frac{31}{2}\cdot\frac{10}{39}+\frac{31}{5}\right]=\frac{9}{13}\)

\(X-\frac{1984}{195}=\frac{9}{13}\)

\(\Rightarrow X=\frac{9}{13}+\frac{1984}{195}=\frac{163}{15}\)

163 / 15

mk nghĩ v

\(A=17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)=\left(17\frac{2}{31}-6\frac{2}{31}\right)-\frac{15}{17}=11-\frac{15}{17}=10+\left(1-\frac{15}{17}\right)=10\frac{2}{17}\)

\(B=\left(31\frac{6}{13}-36\frac{6}{13}\right)+5\frac{9}{41}=-5+5\frac{9}{41}=\frac{9}{41}\)

C=\(\left(27\frac{51}{59}-7\frac{51}{59}\right)+\frac{1}{3}=20+\frac{1}{3}=20\frac{1}{3}\)

\(D=\left(13\frac{29}{31}-2\frac{28}{31}\right)+\left(4-3\frac{7}{8}\right)=11\frac{1}{31}+\frac{1}{8}=11\frac{8+31}{31.8}=11\frac{39}{248}\)

a, \(\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}=31\frac{6}{16}+5\frac{9}{41}-36\frac{6}{13}\)

\(=\left(31\frac{6}{16}-31\frac{6}{16}\right)+5\frac{9}{41}\)

\(=0+5\frac{9}{41}=5\frac{9}{41}\)

b, \(\left(17\frac{29}{31}-3\frac{7}{8}\right)-\left(2\frac{28}{31}-4\right)=17\frac{9}{31}-3\frac{7}{8}-2\frac{28}{31}+4\)

Ta có : 

Đặt \(A=\frac{31}{3}+\frac{31}{15}+...+\frac{31}{143}\)

\(A=\frac{31}{1.3}+\frac{31}{3.5}+...+\frac{31}{11.13}\)

\(\frac{2}{31}A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{11.13}\)

\(\frac{2}{31}A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{13}\)

\(\frac{2}{31}A=1-\frac{1}{13}\)

\(A=\frac{12}{13}:\frac{2}{31}\)

\(A=\frac{186}{13}\)

\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\)

\(x=\frac{9}{13}+\frac{186}{13}\)

\(x=\frac{195}{13}=15\)

Ủng hộ mk nha !!! ^_^

\(\text{Đặt }A=\frac{31}{3}+\frac{31}{15}+...+\frac{31}{143}\)

\(\Rightarrow A=\frac{31}{1.3}+\frac{31}{3.5}+...+\frac{31}{11.13}\)

\(\Rightarrow\frac{2}{31}A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{11.13}\)

\(\Rightarrow\frac{2}{31}A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{13}\)

\(\Rightarrow\frac{2}{31}A=1-\frac{1}{13}\Rightarrow A=\frac{12}{13}:\frac{2}{31}=\frac{186}{13}\)

\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\)

\(\Rightarrow x=\frac{9}{13}+\frac{186}{13}\)

\(\Rightarrow x=\frac{195}{13}=15\)

\(17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)\)

\(17\frac{2}{31}=\frac{529}{31};6\frac{2}{31}=\frac{188}{31}\)

\(17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)\)

\(=\frac{529}{31}-\left(\frac{15}{17}+\frac{188}{31}\right)\)

\(=\frac{529}{31}-\frac{3661}{527}\)

\(=\frac{172}{17}\)

\(\left(\frac{29}{31}-\frac{7}{8}\right)-\left(\frac{28}{31}-4\right)\)

\(=\frac{15}{248}-\left(-\frac{96}{31}\right)\)

\(=\frac{783}{248}\)