Tim so nguyen n biet: \(\frac{1}{9}\times27^n=3^n\)
1. Cho Phan so B=\(\frac{n}{n-4}\)(voi n \(\in\)Z)
a. Tim So nguyen n de B la Phan so
b. Tim so Nguyen n de B co Gia tri la so tu nhien
2. Tim cac so nguyen x, y biet
a.\(\frac{x}{-3}=\frac{4}{y}\)
b. \(\frac{2}{x}=\frac{y}{-9}\)
tim so nguyen n, biet
a)\(\frac{1}{9}\cdot27^n=3^n\)
b)\(3^{-2}\cdot3^4\cdot3^n=3^7\)
a)\(\frac{1}{3^2}\cdot3^{3n}=3^n\Rightarrow3=3^{3n-2}=3^n\Rightarrow3n-2=n\Rightarrow n=1\)
b)\(\frac{1}{3^2}\cdot3^4\cdot3^n=3^7\Rightarrow3^{n+2}=3^7\Rightarrow n+2=7\Rightarrow n=5\)
Tim cac so nguyen m va n, biet: \(\frac{m}{2}-\frac{2}{n}=\frac{1}{2}\)
bai 1 tim so tu nhien co 4 chu so ab cd biet abcd+abc+ab+a=4321.tim abcd
bai 2 cho m , n la cac so tu nhien va p la so nguyen to thoa man 9/m-1=m+n/p. tinh A= p^2-n
bai 3 tim so co 3 chu so biet abc 1000/a+b+c=abc.
Bài 1: Ký hiệu (abcd) là số tự nhiên có 4 chữ số.
(abcd) + (abc) + (ab) + (a) = 1111.a + 111.b + 11.c + d
Vậy 1111.a + 111.b + 11.c + d = 4321
+ Nếu a < 3 => 111.b + 11.c + d > 2098 (vô lý vì b, c, d < 10)
+ Nếu a > 3 => vế trái > 4321
Vậy a = 3 => 111.b + 11.c + d = 988
+ Nếu b < 8 => 11.c + d > 210 (vô lý vì c, d < 10)
+ Nếu b > 8 => vế trái > 988
Vậy b = 8 => 11.c + d = 100
+ Nếu c < 9 => d > 11 (vô lý)
Vậy c = 9; d = 1
=> (abcd) = 3891
tim so nguyen duong biet:\(\frac{1}{8}\)\(16^n\)\(=2^n\)
\(\frac{1}{8}.16^n=2^n\)
\(\Rightarrow2^n=2^n\)
\(\Rightarrow n\in R\)
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tim abcd biet 9. bcde = 1234a
2, tim n e N biet
a, n+ 4 chia het cho n + 1
b, (n + 7 ) ( n2 + 2n + 3 ) la so nguyen to
1, 9. bcde = 1234a (1)
=> 1234a chia hết cho 9
=> 1 + 2 + 3 + 4 + a chia hết cho 9
=> 10 + a chia hết cho 9
=> a = 8
Khi đó (1) trở thành: 9.bcde = 12348
=> bcde = 1372
=> abcd = 8137
a, tim cac so nguyen n biet -3 nho hon hoac bang n va nho hon 5.
b, tinh tong cac so nguyen tim duoc o cau a.
a, - 3 \(\le\) n < 5
n \(\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)
b, Tổng :
- 3 + ( - 2 ) + ( - 1 ) + 0 + 1 + 2 + 3 + 4
= [ ( - 3 ) + 3 ] + [ ( - 2 ) + 21 ] + [ ( - 1 ) + 1 ] + 0 + 4
= 0 + 0 + 0 + 0 + 4 = 4
thankiu ban nha!!
tim so nguyen n biet
3n - 2 chia het cho 2n - 1
n + 3 chia het cho n - 4
Tim so nguyen n biet 3n-1 chia het cho n-2
3n - 1 ⋮ n - 2
<=> 3n - 6 + 5 ⋮ n - 2
<=> 3(n - 2) + 5 ⋮ n - 2
=> 5 ⋮ n - 2
Hay n - 2 ∈ Ư(5) = { ± 1; ± 5 }
Ta có bảng sau :
n - 2 | - 5 | - 1 | 1 | 5 |
n | - 3 | 1 | 3 | 7 |
Vậy x = { - 3; 1 ; 3 ; 7 }