\(\frac{1999x1999}{1995x1995}>1\)

\(\frac{198519851985x198719871987}{198619861986x198119861986}< 1\)

Chúc bn học tốt

A = 1991x 1999 = (1995-4) x 1999 = 1995x1999-4x1999

B = 1995x1995 = 1995 x (1999-4)=1995=1999-1995x4>1995x1999-4x1999=A

vậy A<B

CHÚC BẠN HỌC GIỎI

TK MÌNH NHÉ

Ta có :

\(\frac{1991.1999}{1995.1995}=\frac{1991.1995+1991.4}{1991.1995+1995.4}\)

Rõ ràng \(\frac{1991.1995+1991.4}{1991.1995+1995.4}< 1\)vì\(1991.1995+1991.4>1991.1995+1995.4\)

1991x1999= 1995x1995

a)\(\frac{34\cdot34}{33\cdot35}=\frac{34\cdot34}{\left(34-1\right)\left(34+1\right)}=\frac{34\cdot34}{34\cdot34-1}>1\)

b) \(\frac{1999\cdot1999}{1995\cdot1995}=\frac{1999}{1995}\times\frac{1999}{1995}< 1\times1=1\)

c) \(\frac{198519851985\cdot198719871987}{198619861986\cdot198619861986}=\frac{1985\cdot1001001001\times1987\cdot1001001001}{1986\cdot1001001001\times1986\cdot1001001001}\)

\(=\frac{1985\cdot1987}{1986\cdot1986}=\frac{1986\cdot1986-1}{1986\cdot1986}< 1\)

Ta có:

A=1991x1999

A=1991x(1995+4)

A=1991x1995+1991x4

B=1995x1995

B=(1991+4)x1995

B=1991x1995+1995x4

Vì 1991x1995+1991x4<1991x1995+1995x4

Nên A<B

a,1991x1999=(1995-4)(1995+4)

=1995²-4x1995+4x1995-16=1995²-16<1995²

Vậy a<b.

a. \(\frac{34\times34}{33\times35}\)

\(=\frac{34\times33+34}{33\times34+33}\)

Vì \(34>33\)nên Tử > Mẫu

\(\Rightarrow\frac{34\times34}{33\times35}>1\)

b. \(\frac{1991\times1999}{1995\times1995}\)

\(=\frac{1991\times\left(1995+4\right)}{1995\times\left(1991+4\right)}\)

\(=\frac{1991\times1995+1991\times4}{1995\times1991+1995\times4}\)

Vì  \(1995\times4>1991\times4\)nên Tử > Mẫu 

\(\Rightarrow\frac{1991\times1999}{1995\times1995}>1\)

A > B nhé

Bạn trình bày bài giải cho mình nhé

Ta có:

\(A=1999\times1999=1999\times\left(1997+2\right)=1999\times1997+1999\times2\)

\(B=1997\times2001=1997\times\left(1999+2\right)=1999\times1997+1997\times2\)

Vì \(1999\times1997+1999\times2>1999\times1997+1997\times2\)Nên \(A>B\)

A = 1991 x 1999 

A = 1991 x ( 1995 + 4 ) 

A = 1991 x 1995 + 1991 x 4 

B = 1995 x 1995 

B = ( 1991 + 4 ) x 1995 

B = 1991 x 1995 + 1995 x 4

Vì 1991 < 1995 nên 1991 x 1995 + 1991 x 4 < 1991 x 1995 + 1995 x 4

Vậy A < B

A va B bang nhau

A= 1991 x 1999 < B =  1995 x 1995

zì 1991X1999<1995X1995

<

A=1995*1995                       B=1994*1996

A=(1994+1)*1995                 B=1994*(1995+1)

A=1994*1995+1*1995           B=1994*1995+1*1994

Vì 1994*1995=1994*1995 ; 1*1995 > 1*1994

Nên 1995*1995 > 1994*1996

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