1/15+4/27+3/15-1/27

=(1/15+3/15)+(4/27-1/27)

=4/15+3/27

=.......

= 1/15+3/15+4/27-1/27

=4/15+4/27-1/27

=56/135 - 1/27 = 17/45

chúc bạn học tốt !

1/15 + 4/27 + 3/15 - 1/27 = 1/15 + 3/15 + 4/27 -1/27

                                        = 4/15 + 3/27

                                         = 17/45

a) 27.(15-12)-15.(27-12)

= 27.15-27.12-15.27-15.12

=405 - 324 - 405 - 180

= -504

\(\frac{1\cdot3\cdot9+2\cdot6\cdot18+3\cdot9\cdot27}{1\cdot5\cdot18+2\cdot10\cdot36+3\cdot15\cdot54}\)

\(=\frac{1\cdot3\cdot9+2\left(1\cdot3\cdot9\right)+3\left(1\cdot3\cdot9\right)}{1\cdot5\cdot18+2\left(1\cdot5\cdot18\right)+3\left(1\cdot5\cdot18\right)}\)

\(=\frac{\left(1\cdot3\cdot9\right)\left(1+2+3\right)}{\left(1\cdot5\cdot18\right)\left(1+2+3\right)}\)

\(=\frac{3}{10}\)

\(b)4\cdot(-5)^2+2\cdot(-5)-20\)

\(=4\cdot25+2\cdot(-5)-20\)

\(=100+(-10)-20=70\)

\(c)27\cdot(15-12)-15\cdot(27-12)\)

\(=27\cdot15-27\cdot12-15\cdot27-15\cdot12\)

\(=(27\cdot15-15\cdot27)-27\cdot12-15\cdot12\)

\(=0-(27-15)\cdot12=0-12\cdot12=0-144=-144\)

a)

4.25+2.(-5)-20

=100+-10-20

=90-20

=70

c)

=27.15 - 27.12- 15.27 + 15.12

=(27.15-15.27)-27.12+15.12

=0-12.(27+15)

=0-12.42

=0-504

=-504

/////////

Hok tốt

\(b,4\cdot\left(-5\right)^2+2\cdot\left(-5\right)-20\)

\(=\left(-5\right)\cdot\left[4\cdot\left(-5\right)+2+\left(-4\right)\right]\)

\(=\left(-5\right)\cdot\left(-22\right)=110\)

\(A=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{83.85}\)

\(\Rightarrow2A=\frac{2}{25.27}+\frac{2}{27.29}+\frac{2}{29.31}+...+\frac{2}{83.85}\)

\(2A=\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{83}-\frac{1}{85}\)

\(2A=\frac{1}{25}-\frac{1}{85}\)

\(2A=\frac{12}{425}\)

\(A=\frac{12}{425}:2\)

\(A=\frac{6}{425}\)

\(C=\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+...+\frac{2}{399}\)

\(C=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{19.21}\)

\(C=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\)

\(C=\frac{1}{3}-\frac{1}{21}\)

\(C=\frac{2}{7}\)

CÂU B LÀM TƯƠNG TỰ NHA 

HOK TOT

Sai môn rồi

Mk thấy bài 1 và 2 dễ nên bạn tự làm nha

3

+)Ta có n-2 \(⋮\)n-2

=>2.(n-2)\(⋮\)n-2

=>2n-4\(⋮\)n-2(1)

+)Theo bài ta có:2n+1\(⋮\)n-2(2)

+)Từ (1) và (2)

=>(2n+1)-(2n-4)\(⋮\)n-2

=>2n+1-2n+4\(⋮\)n-2

=>5\(⋮\)n-2

=>n-2\(\in\)Ư(5)={\(\pm\)1;\(\pm\)5}

+)Ta có bảng:

Vậy n\(\in\){1;3;-3;7}

Chúc bn học tốt

a. 5.(–8).( –2).(–3)                                                       b. 4.(–5)2 + 2.(–5) – 20

=(-5).8.(-2).(-3)                                                               ={(-5).2} {4+1}-20

=(-5)(-2)(-3).8                                                                 =(-10).5-20=-50-20=-70

=10.(-24)=-240