Tìm x biet x thuộc so tự nhien :
a) 2x-15=17
b) (7.x-11)=2^5.5^2+200
c) (2x-15)5=(2x-15)3
tìm số tự nhiên x biết
a)2^x-15=17
b)(7^x-11)^3=2^5.5^2+200
c)2.3^x=10.3^12+8.27^4
d)(2x-150^5=(2x-15)^3
2\(^x\)- 15 = 17
\(\Rightarrow\)2\(^x\) = 32
\(\Rightarrow\)x = 5
2^x-15=17
=>2^x=17+15
=2^x=32
=>2^x=2^5
=>x=5
TÌM X
(7x-11)^3=2^5.5^2+200
x^10=x
(2x-15)^5=(2x-15)^3
b) x^10=1x
=> x=0 ; 1
c)(2x-15)^5=(2x-15)^3
=> (2x-15)^4 = (2x-15)^2
=> (2x-15)^2 =1
=> 2x-15=1
=> x=8
tim \(x\in\)N biet
a . \(x^{10}=x\)
b . \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
c . \(\left(7\times n-11\right)=2^5.5^2+200\)
a) \(x^{10}=x\)
\(\Rightarrow x^{10}-x=0\)
\(\Rightarrow x\left(x^9-1\right)=0\)
=> x=0 HOẶC \(x^9-1=0\)
=>x=0 HOẶC x=1
Tìm x biet:
a,5/2x+x=32/15
b,x-7/2x=-32/15
c,-7/3x-7/4x+11/3=18/5
d,-5/6-3x=2/3
e,2x-5/9=-2/3
f,1/2-2/3x=7/12
g,7-|2x-3|=4
h,(19x+2.5^2):14=(13-8)^2-4^2
i,3/4x-2/3=2/7.1/6+5/7.1/6
k,(x+1/2).(2/3-2x)=0
l,x/2013-1/10-1/15-1/21-........-1/120=5/8
Tìm x
720 : [41-(2x-5)] =2^3 . 5
2^x = 15 = 17
(7x-11)^3= 2^5.5^2+200
720 : [41-(2x-5)] =2^3 . 5
<=> 41-(2x-5)=720:40=18
<=> 2x-5=41-18=23
<=>2x=23+5=28
<=> x=28:2=14
2^x-15=17
<=> 2^x=17+15=32
<=> 2^x=2^5
<=> x=5
(7x-11)^3= 2^5.5^2+200
<=> (7x-11)^3=1000
<=> (7x-11)^3=10^3
<=> 7x-11=10
<=> 7x=10+11=21
<=> x=21:7=3
chứng minh giá trị k phụ thuộc vào biến
A=(3-2x)x3x-8+(2x+5)(3x-2)-20x
B=(3-5x)(2x+11)-(2x+3)(3x+7)
tìm x
2x(x-1)-x^2+6=0
(x+3)(x^2-3x+9)-x(x-2)(x+2)=15
Sửa đề bài 1 : k => x P/s : đề sai r :))
\(A=\left(3-2x\right)3x^2-8+\left(2x+5\right)\left(3x-2\right)-20x\)
\(=9x^2-6x^3-8+6x^2-4x+15x-10-20x=15x^2-6x^3-18-9x\)
Vậy biểu thức phụ thuộc biến x
\(B=\left(3-5x\right)\left(2x+11\right)-\left(2x+3\right)\left(3x+7\right)\)
\(=6x+33-10x^2-55x-6x^2-14x-9x-21=-72x+12-16x^2\)
Vậy biểu thức phụ thuộc biến x
Bài 2 :
a, \(2x\left(x-1\right)-x^2+6=0\Leftrightarrow2x^2-2x-x^2+6=0\)
\(\Leftrightarrow x^2-2x+6=0\)( vô nghiệm )
b, \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-2\right)\left(x+2\right)=15\)
\(\Leftrightarrow\left(x+3\right)\left(x-3\right)-x\left(x-2\right)\left(x+2\right)=15\)
\(\Leftrightarrow x^2-9-x\left(x^2-4\right)=15\Leftrightarrow x^2-9-x^3+12=15\)
\(\Leftrightarrow-x^3+x^2-12=0\Leftrightarrow x=2\)
B1:tim cac so nguyenx,y biet:
X,y + 2.x- 3y= 11
B2 tim x biet
A -15.(x+2)+7.(2x-3)=(-5) . (+10)
Giai gap minh nhe
\(-15.\left(\chi+2\right)+7.\left(2\chi-3\right)=\left(-5\right).10\)
\(\Rightarrow-15\chi+\left(-30\right)+14\chi-21=-50\)
\(\Rightarrow\left(-15\chi+14\chi\right)=-50+30+21\)
\(\Rightarrow\chi=1\)
HTDT
1 tìm x thuộc Z
-2x-40=(5-x)-(-15+60)
2.(x-5)-3(x+7)=14
-7.(5-x)-2(x-10)=15
x+18=2-2x
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
\(-2x-40=\left(5-x\right)-\left(-15+60\right)\)
\(\Leftrightarrow\)\(-2x-40=5-x+15-60\)
\(\Leftrightarrow\)\(-2x-40=-x-40\)
\(\Leftrightarrow\)\(-2x+x=40-40\)
\(\Leftrightarrow\)\(x=0\)
Vậy....
\(x+18=2-2x\)
\(2x+x=2-18\)
\(3x=-20\)
\(x=-20:3\)
\(x=\frac{-20}{3}\)
Tình hợp lý nếu có thể :
-5/2x 2/11+-5/7x 9/11+15/7
Tìm x biết:
(2x-15)mũ 5=(2x-15)mũ 3
25/7nha