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Hà Đức Thọ
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Em cũng xin gửi lời chúc mừng 20/11 đến các thầy cô giáo nhân ngày Nhà giáo Việt Nam. Chúc các thầy cô luôn mạnh khỏe, thành đạt, hạnh phúc và công tác tốt. Trẻ mãi không già , ăn mãi không béo .

456
Hôm qua lúc 10:05

Em chúc các thầy cô khỏe mạnh để tiếp tục cho sự việc trồng người ạ !

Phan Văn Toàn
Hôm qua lúc 11:15

Nhân ngày 20/11 em chúc thầy cô luôn tràn đầy năng lượng và sức khỏe. Cảm ơn thầy cô đã dành cả trái tim và tâm huyết để truyền dạy kiến thức cho chúng em. Chúng em sẽ luôn nhớ mãi những bài học quý giá từ thầy cô."

Ẩn danh
Nguyễn Lê Phước Thịnh
22 giờ trước (18:20)

Oa là phân giác của góc mOt

=>\(\widehat{mOa}=\dfrac{\widehat{mOt}}{2}=\dfrac{40^0}{2}=20^0\)

Ta có: \(\widehat{mOa}+\widehat{nOa}=180^0\)(hai góc kề bù)

=>\(\widehat{nOa}=180^0-20^0=160^0\)

Nguyễn Ngọc Tiên
Xem chi tiết
Tui hổng có tên =33
22 giờ trước (18:04)

Sửa đề: \(7,2:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Rightarrow7,2:\left[41-\left(2x-5\right)\right]=8.5\)
\(\Rightarrow7,2:\left[41-\left(2x-5\right)\right]=40\)
\(\Rightarrow41-\left(2x-5\right)=7,2:40\)
\(\Rightarrow41-\left(2x-5\right)=0,18\)
\(\Rightarrow2x-5=41-0,18\)
\(\Rightarrow2x-5=40,82\)
\(\Rightarrow2x=40,82+5\)
\(\Rightarrow2x=45,82\)
\(\Rightarrow x=45,82:2\)
\(\Rightarrow x=22,91\)
Vậy ...

Ẩn danh
Tui hổng có tên =33
Hôm qua lúc 15:23

4. In spite of my sickness, my mother told me to go to school.
5. Because of a big storm, I stayed at home.
6. Despite Tom's bad grades, he was admitted to the university.
7. Despite having a physical handicap, she has become a successful woman.
8. Although his salary was good,Tom gave up his job.
9. In spite of not being finished the paper,he went to sleep.
10. Even though the prices are high , my daughter insists on going to the movies.

Sinh Viên NEU
13 giờ trước (3:35)

4 In spite of my sickness, my mother told me to go to school 

5 Because of a big storm, I stayed at home

6 Despite his bad grades, Tom was admitted to the university 

7 Despite having a physical handicap, she has become a successful woman

8 Although his salary was good, he gave up his job

9 In spite of not having finished the paper, he went to sleep

10 Eventhough the prices are high, my sister insists on going to the movies

Ẩn danh
Tui hổng có tên =33
Hôm qua lúc 16:23

1. What do people say about the film?
2. My favourite film is Annabelle, a horror film directed by John R. Leonetti.
3. Let's go to the cinema tonight.
4. What kind of film is it?
5. He doesn't like that kind of film.
6. Many people cried when they saw the scenes in the film.
7. The film last night was so boring that we fell asleep.
8. There were many fights in the film. It was too violent.
9.  What film did you see recently?
10. Put your earphones near here.

Sinh Viên NEU
13 giờ trước (3:37)

1 What do people say about the film?

2 My favorite film is Annabelle, a horror film directed ny John R. Leonetti

3 Let's go to the cinema tonight

4 What kind of film is it?

5 He doesn't like that kind of film

Sinh Viên NEU
13 giờ trước (3:44)

6 Many people cried when they saw the scenes in the film

7 The film was so boring that we fell asleep last night

8 There were too many fights in the film. It was violent

9 What film did you see recently?

10 Put your earphones near here

Ẩn danh
NeverGiveUp
Hôm qua lúc 15:19

1 are-->is

2 them-->it

3 Who--->What

4 liked-->like

   it is-->they are

5 leaves---left

   carly-->early

6 have supernatural --->has supernatural elements

7 an--> a

8 in-->at

9 review-->reviews

10 interested-->interesting

Sinh Viên NEU
13 giờ trước (3:46)

1 are => is

2 them => it

3 who => what

4 liked => like, it is => they are

5 leaves => left

Sinh Viên NEU
13 giờ trước (3:46)

6 have => is

7 an => a

8 in => At

9 review => reviews

10 interested => interesting

『Lê』 Gia Bảo
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Nguyễn Lê Phước Thịnh
23 giờ trước (16:55)

a: Xét ΔABD và ΔAED có

AB=AE

\(\widehat{BAD}=\widehat{EAD}\)

AD chung

Do đó: ΔABD=ΔAED

b: ΔABD=ΔAED

=>\(\widehat{ABD}=\widehat{AED}\)

Để DE\(\perp\)AC thì \(\widehat{AED}=90^0\)

=>\(\widehat{ABD}=90^0\)

hay \(\widehat{ABC}=90^0\)

c: Xét ΔAEK và ΔABC có

\(\widehat{AEK}=\widehat{ABC}\)

AE=AB

\(\widehat{EAK}\) chung

Do đó: ΔAEK=ΔABC

=>\(\widehat{AKE}=\widehat{ACB}\)

d: Ta có: ΔAEK=ΔABC

=>AK=AC

Ta có: AB+BK=AK

AE+EC=AC

mà AB=AE và AK=AC

nên BK=EC

ΔAEK=ΔABC

=>EK=BC

Xét ΔEBK và ΔBEC có

BE chung

BK=EC

EK=BC

Do đó: ΔEBK=ΔBEC

『Lê』 Gia Bảo
Xem chi tiết
Nguyễn Lê Phước Thịnh
23 giờ trước (16:53)

a: Xét ΔABE và ΔAME có

AB=AM

\(\widehat{BAE}=\widehat{MAE}\)

AE chung

Do đó: ΔABE=ΔAME

b: ΔABM có AB=AM

nên ΔABM cân tại A

Ta có: ΔABM cân tại A

mà AI là đường phân giác

nên I là trung điểm của BM

=>IB=IM

c: ΔABE=ΔAME

=>EB=EM

Xét ΔEBN và ΔEMC có

EB=EM

\(\widehat{BEN}=\widehat{MEC}\)(hai góc đối đỉnh)

EN=EC

Do đó: ΔEBN=ΔEMC

d: ΔEBN=ΔEMC

=>\(\widehat{EBN}=\widehat{EMC}\)

ΔABE=ΔAME

=>\(\widehat{ABE}=\widehat{AME}\)

\(\widehat{ABE}+\widehat{EBN}=\widehat{AME}+\widehat{CME}=180^0\)

=>A,B,N thẳng hàng

Han Yujin
Xem chi tiết
Tui hổng có tên =33
Hôm qua lúc 15:44

\(a,\dfrac{4}{5}.\left(\dfrac{7}{2}+\dfrac{1}{4}\right)^2\)
\(=\dfrac{4}{5}\left(\dfrac{14}{4}+\dfrac{1}{4}\right)^2\)
\(=\dfrac{4}{5}.\left(\dfrac{15}{4}\right)^2\)
\(=\dfrac{4}{5}.\dfrac{225}{16}\)
\(=\dfrac{45}{4}\)
\(b,\left|\dfrac{-3}{8}\right|.27\dfrac{1}{5}-51\dfrac{1}{5}.\dfrac{3}{8}+19\)
\(=\dfrac{3}{8}.\dfrac{136}{5}-\dfrac{256}{5}.\dfrac{3}{8}+19\)
\(=\dfrac{3}{8}.\left(\dfrac{136}{5}-\dfrac{256}{5}\right)+19\)
\(=\dfrac{3}{8}.\dfrac{-120}{5}+19\)
\(=\dfrac{3}{8}.\left(-24\right)+19\)
\(=-9+19\)
\(=10\)
\(c,\left(\dfrac{2}{3}-\dfrac{7}{15}\right):\left(\dfrac{2}{3}-\dfrac{2}{5}\right)^2\)
\(=\left(\dfrac{10}{15}-\dfrac{7}{15}\right):\left(\dfrac{10}{15}-\dfrac{6}{15}\right)^2\)
\(=\dfrac{3}{15}:\left(\dfrac{4}{15}\right)^2\)
\(=\dfrac{1}{5}:\dfrac{16}{225}\)
\(=\dfrac{45}{16}\)
\(d,\dfrac{-19}{3}.\dfrac{14}{4}-\dfrac{25}{4}.\left|\dfrac{-19}{3}\right|+4\dfrac{4}{3}\)
\(=\dfrac{19}{3}.\dfrac{-14}{4}-\dfrac{25}{4}.\dfrac{19}{3}+\dfrac{16}{3}\)
\(=\dfrac{19}{3}.\left(\dfrac{-14}{4}-\dfrac{25}{4}\right)+\dfrac{16}{3}\)
\(=\dfrac{19}{3}.\dfrac{-39}{4}+\dfrac{16}{3}\)
\(=\dfrac{-247}{4}+\dfrac{16}{3}\)
\(=\dfrac{-741}{12}+\dfrac{64}{12}\)
\(=\dfrac{-677}{12}\)

Han Yujin
Xem chi tiết
Tui hổng có tên =33
Hôm qua lúc 15:32

\(a,\dfrac{3}{8}.19\dfrac{1}{3}-\dfrac{3}{8}.33\dfrac{1}{3}\)
\(=\dfrac{3}{8}.\left(19\dfrac{1}{3}-33\dfrac{1}{3}\right)\)
\(=\dfrac{3}{8}.\left(\dfrac{58}{3}-\dfrac{100}{3}\right)\)
\(=\dfrac{3}{8}.\dfrac{-42}{3}\)
\(=\dfrac{-42}{8}=\dfrac{-21}{4}\)
\(b,\dfrac{21}{47}+\dfrac{9}{45}+\dfrac{26}{47}+\dfrac{4}{5}\)
\(=\left(\dfrac{21}{47}+\dfrac{26}{47}\right)+\left(\dfrac{9}{45}+\dfrac{4}{5}\right)\)
\(=\dfrac{47}{47}+\left(\dfrac{9}{45}+\dfrac{36}{45}\right)\)
\(=1+\dfrac{45}{45}\)
\(=1+1\)
\(=2\)
\(c,\dfrac{13}{25}+\dfrac{6}{41}-\dfrac{38}{25}+\dfrac{35}{41}-\dfrac{1}{2}\)
\(=\left(\dfrac{13}{25}-\dfrac{38}{25}\right)+\left(\dfrac{6}{41}+\dfrac{35}{41}\right)-\dfrac{1}{2}\)
\(=\dfrac{-25}{25}+\dfrac{41}{41}-\dfrac{1}{2}\)
\(=-1+1-\dfrac{1}{2}\)
\(=0-\dfrac{1}{2}\)
\(=\dfrac{-1}{2}\)
\(d,12,5.\left(\dfrac{-5}{7}\right)+1,5.\left(\dfrac{-5}{7}\right)\)
\(=\dfrac{-5}{7}.\left(12,5+1,5\right)\)
\(=\dfrac{-5}{7}.14\)
\(=-10\)

Nguyễn Đức Trí
Hôm qua lúc 10:18

\(60=2^2.3.5\)

Để \(\dfrac{x+2}{60}\) viết được dưới dạng số thập phân hữu hạn

\(\Rightarrow x+2\) không được chứa ước nguyên tố nào khác \(2\) và \(5\)

\(\Rightarrow x+2\in U\left(2^2.5=20\right)=\left\{1;2;4;5;10;20\right\}\)

\(\Rightarrow x\in\left\{-1;0;2;3;8;18\right\}\)

mà \(x\in N;x< 15\)

\(\Rightarrow x\in\left\{0;2;3;8\right\}\)

\(\Rightarrow\) Có \(4\) số tự nhiên \(x< 15\) thỏa mãn đề bài

\(\Rightarrow\) Trả lời có \(4\) số