Question

Answer 1

\(B=\dfrac{\sqrt{3}-1+\sqrt{3}+1}{3-1}=\dfrac{2\sqrt{3}}{2}\)

Answer 2

\(B=\dfrac{1}{\sqrt{3}+1}+\dfrac{1}{\sqrt{3}-1}\)

\(B=\dfrac{\sqrt{3}-1+\sqrt{3}+1}{3-1}\)

\(B=\dfrac{2\sqrt{3}}{2}\)

\(B=\sqrt{3}\)

Answer 3

\(B=\dfrac{1}{\sqrt{3}+1}+\dfrac{1}{\sqrt{3}-1}=\dfrac{\sqrt{3}-1+\sqrt{3}+1}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}\)

\(=\dfrac{2\sqrt{3}}{\sqrt{3^2}-1}=\dfrac{2\sqrt{3}}{2}=\sqrt{3}\)

Answer 4

 

\(B=\dfrac{1}{\sqrt{3}+1}+\dfrac{1}{\sqrt{3}-1}\)

\(=\dfrac{\sqrt{3}-1+\sqrt{3}+1}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}\)

\(=\dfrac{2\sqrt{3}}{3-1}\) \(=\dfrac{2\sqrt{3}}{2}\) \(=\sqrt{3}\)