Question

Answer 1

a: =>|x-1|=1

=>x-1=1 hoặc x-1=-1

=>x=2 hoặc x=0

b: =>|x-3|=x

\(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\x-3=-x\end{matrix}\right.\Leftrightarrow x=\dfrac{3}{2}\)

Answer 2

\(a,đkx\ge1\\ \sqrt{\left(x-1\right)^2}=1\\ x-1=1\\ x=2\left(thoaman\right)\\ b,đkx\le3\sqrt{\left(3-x\right)^2}=x\\ 3-x=x\\ 3-x-x=0\\ -2x+3=0\\ -2x=-3\\ x=\dfrac{3}{2}\left(thoaman\right)\)

Answer 3

`a, x - 1 = 1`

`-> x = 2`

`b, 3 - x = x`

`-> x = 3/2`