Question

Answer 1

\(\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}+\sqrt{\dfrac{2+\sqrt{3}}{2-\sqrt{3}}}=\sqrt{\dfrac{\left(2-\sqrt{3}\right)^2}{4-3}}+\sqrt{\dfrac{\left(2+\sqrt{3}\right)^2}{4-3}}=2-\sqrt{3}+2+\sqrt{3}=4\)

Answer 2

.

Answer 3

\(\sqrt{\dfrac{2-\sqrt{3}}{2+\sqrt{3}}}+\sqrt{\dfrac{2+\sqrt{3}}{2-\sqrt{3}}}\)

\(=2-\sqrt{3}+2+\sqrt{3}\)

=4