Question

tìm đkxđ của \(\dfrac{\sqrt{2x+1}}{2x-1}\)

Answer 1

ĐKXĐ: \(\left\{{}\begin{matrix}2x+1\ge0\\2x-1\ne0\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{1}{2}\\x\ne\dfrac{1}{2}\end{matrix}\right.\)

Answer 2

ĐK: \(\left\{{}\begin{matrix}2x+1\ge0\\2x-1\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{1}{2}\\x\ne\dfrac{1}{2}\end{matrix}\right.\)

Answer 3

ĐKXĐ: \(\left\{{}\begin{matrix}x\ge-\dfrac{1}{2}\\x\ne\dfrac{1}{2}\end{matrix}\right.\)

Answer 4

Answer 5

ĐKXĐ: \(\left\{{}\begin{matrix}x\ge-\dfrac{1}{2}\\x\ne\dfrac{1}{2}\end{matrix}\right.\)