1: ĐKXĐ: x>=3
\(\sqrt{4\cdot\left(x-3\right)}+\sqrt{9x-27}=10\)
=>\(2\sqrt{x-3}+3\sqrt{x-3}=10\)
=>\(5\sqrt{x-3}=10\)
=>\(\sqrt{x-3}=\dfrac{10}{5}=2\)
=>x-3=4
=>x=4+3=7(nhận)
3: ĐKXĐ: x>=2
\(\sqrt{4x-8}=6-\sqrt{x-2}\)
=>\(2\sqrt{x-2}+\sqrt{x-2}=6\)
=>\(3\sqrt{x-2}=6\)
=>\(\sqrt{x-2}=\dfrac{6}{3}=2\)
=>x-2=4
=>x=6(nhận)
5:
ĐKXĐ: x>=5
\(5\sqrt{x-5}+\sqrt{9x-45}=16\)
=>\(5\sqrt{x-5}+3\sqrt{x-5}=16\)
=>\(8\sqrt{x-5}=16\)
=>\(\sqrt{x-5}=2\)
=>x-5=4
=>x=4+5=9(nhận)
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